Question Number 9312 by tawakalitu last updated on 29/Nov/16 $$\mathrm{Solve}\:\mathrm{simultaneously} \\ $$$$\mathrm{xy}\:+\:\mathrm{x}\:+\:\mathrm{y}\:=\:\mathrm{23}\:\:\:\:…….\:\left(\mathrm{i}\right) \\ $$$$\mathrm{xz}\:+\:\mathrm{x}\:+\:\mathrm{z}\:=\:\mathrm{41}\:\:\:\:……..\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{yz}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{27}\:\:\:\:\:……..\:\left(\mathrm{iii}\right) \\ $$ Commented by RasheedSoomro last updated on 30/Nov/16…
Question Number 140381 by Willson last updated on 07/May/21 $$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{xe}^{\mathrm{1}−\mathrm{x}} \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\:\:\:\:\underset{\mathrm{n}\rightarrow+\infty} {\mathrm{lim}}\:\sqrt{\mathrm{n}}\:\underset{\mathrm{0}} {\int}^{\:\mathrm{1}} \left[\mathrm{f}\left(\mathrm{x}\right)\right]^{\mathrm{n}} \:\mathrm{dt}\:=\:\sqrt{\frac{\pi}{\mathrm{2}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 140382 by john_santu last updated on 07/May/21 $$\mathrm{sin}\:^{\mathrm{10}} {x}\:+\:\mathrm{cos}\:^{\mathrm{10}} {x}\:=\:\frac{\mathrm{61}}{\mathrm{256}} \\ $$ Answered by MJS_new last updated on 07/May/21 $$\mathrm{sin}\:{x}\:={s}\wedge\mathrm{cos}\:{x}\:=\sqrt{\mathrm{1}−{s}^{\mathrm{2}} } \\ $$$$\mathrm{5}{s}^{\mathrm{8}}…
Question Number 140377 by cherokeesay last updated on 07/May/21 Commented by help last updated on 07/May/21 $$\mathrm{12}\sqrt{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 9306 by tawakalitu last updated on 29/Nov/16 $$\mathrm{Differentiate}\:\mathrm{from}\:\mathrm{the}\:\mathrm{first}\:\mathrm{principle}: \\ $$$$\mathrm{y}\:=\:\mathrm{tan2x} \\ $$ Answered by mrW last updated on 30/Nov/16 $$\mathrm{y}\left(\mathrm{x}\right)=\mathrm{tan}\:\left(\mathrm{2x}\right) \\ $$$$\mathrm{y}\left(\mathrm{x}+\mathrm{h}\right)=\mathrm{tan}\:\left(\mathrm{2x}+\mathrm{2h}\right)=\frac{\mathrm{tan}\:\left(\mathrm{2x}\right)+\mathrm{tan}\:\left(\mathrm{2h}\right)}{\mathrm{1}−\mathrm{tan}\:\left(\mathrm{2x}\right)×\mathrm{tan}\:\left(\mathrm{2h}\right)} \\…
Question Number 74840 by aliesam last updated on 01/Dec/19 Commented by kaivan.ahmadi last updated on 01/Dec/19 $${a}^{\mathrm{4}} =\mathrm{1}\Rightarrow \\ $$$${b}^{\mathrm{4}} ={a}^{\mathrm{4}} =\mathrm{1}\Rightarrow{o}\left({b}\right)=\mathrm{4} \\ $$$$\left({a}^{\mathrm{2}} \right)^{\mathrm{2}}…
Question Number 140378 by benjo_mathlover last updated on 07/May/21 $$\sqrt{\mathrm{sin}\:^{\mathrm{4}} \mathrm{x}+\mathrm{4cos}\:^{\mathrm{2}} \mathrm{x}}−\sqrt{\mathrm{cos}\:^{\mathrm{4}} \mathrm{x}+\mathrm{4sin}\:^{\mathrm{2}} \mathrm{x}}\:=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\:\mathrm{for}\:\mathrm{x}\in\:\left[\:\mathrm{0},\mathrm{2}\pi\:\right] \\ $$ Commented by john_santu last updated on 07/May/21…
Question Number 140373 by mr W last updated on 06/May/21 Commented by mr W last updated on 06/May/21 $${find}\:{the}\:{radius}\:{of}\:{the}\:{smallest}\: \\ $$$${hollow}\:{sphere}\:{which}\:{can}\:{hold} \\ $$$${four}\:{balls}\:{with}\:{radii}\:{a},{b},{c}\:{and}\:{d}\: \\ $$$${respectively}\:{inside}.…
Question Number 140369 by meetbhavsar25 last updated on 06/May/21 Commented by meetbhavsar25 last updated on 08/May/21 $${mr}\:{W},\:{please}\:{help}\:{me}\:{out} \\ $$ Answered by john_santu last updated on…
Question Number 140368 by meetbhavsar25 last updated on 06/May/21 Answered by benjo_mathlover last updated on 07/May/21 $$\mathrm{cos}^{−\mathrm{1}} \left(\frac{\mathrm{3}+\mathrm{5cos}\:\mathrm{x}}{\mathrm{5}+\mathrm{3cos}\:\mathrm{x}}\right)\:=\:\mathrm{u} \\ $$$$\Rightarrow\frac{\mathrm{3}+\mathrm{5cos}\:\mathrm{x}}{\mathrm{5}+\mathrm{3cos}\:\mathrm{x}}\:=\:\mathrm{cos}\:\mathrm{u} \\ $$$$\Rightarrow\mathrm{3}+\mathrm{5cos}\:\mathrm{x}\:=\:\mathrm{5cos}\:\mathrm{u}+\mathrm{3cos}\:\mathrm{u}\:\mathrm{cos}\:\mathrm{x} \\ $$$$\Rightarrow\left(\mathrm{5}−\mathrm{3cos}\:\mathrm{u}\right)\mathrm{cos}\:\mathrm{x}\:=\:\mathrm{5cos}\:\mathrm{u}−\mathrm{3} \\…