Question Number 74637 by mathmax by abdo last updated on 28/Nov/19 $$\left.\mathrm{1}\right){calculate}\:{f}\left({x}\right)=\int_{\mathrm{0}} ^{\mathrm{1}} {t}^{\mathrm{2}} \sqrt{{x}^{\mathrm{2}} +{t}^{\mathrm{2}} }{dt}\:\:{with}\:{x}>\mathrm{0} \\ $$$$\left.\mathrm{2}\right)\:{calculste}\:{g}\left({x}\right)=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{t}^{\mathrm{2}} }{\:\sqrt{{x}^{\mathrm{2}} +{t}^{\mathrm{2}} }}{dt} \\…
Question Number 9100 by arinto27 last updated on 18/Nov/16 $$\mathrm{luas}\:\mathrm{segi}\:\mathrm{6}\:\mathrm{beraturan}\:\mathrm{dgn}\:\mathrm{panjang}\: \\ $$$$\mathrm{sisi}\:\mathrm{10}\:\mathrm{cm}\:\mathrm{adalah}…? \\ $$$$ \\ $$ Answered by sandy_suhendra last updated on 20/Nov/16 $$\mathrm{segi}\:\mathrm{6}\:\mathrm{beraturan}\:\mathrm{terdiri}\:\mathrm{dr}\:\mathrm{6}\:\mathrm{segitiga}\:\mathrm{sm}\:\mathrm{sisi} \\…
Question Number 74634 by Mr. K last updated on 27/Nov/19 Commented by Mr. K last updated on 28/Nov/19 $${The}\:{square}\:{is}\:{divided}\:{into}\:\mathrm{2}\:{triangles} \\ $$$${and}\:{one}\:{quadrilateral}.\:{The}\:{yellow} \\ $$$${area}\:{is}\:{S}\:{and}\:{the}\:{blue}\:{area}\:{is}\:\:\frac{{S}}{\mathrm{2}}. \\ $$$${Find}\:{AB}.…
Question Number 74632 by TawaTawa last updated on 27/Nov/19 $$. \\ $$ Commented by TawaTawa last updated on 27/Nov/19 The force F acting along an inclined plane is just sufficient to maintain a body on the plane, the angle of friction M being less than Y, the angle of plane. prove that the least force acting along the plane, sufficient to drag the body up the plane is : F sin( M + Y )/sin( M - Y) Terms of Service Privacy Policy…
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Question Number 9096 by tawakalitu last updated on 17/Nov/16 Answered by mrW last updated on 19/Nov/16 $${let}\:{R}_{\mathrm{1}} \:{and}\:{R}_{\mathrm{2}} \:{be}\:{the}\:{rent}\:{of}\:{the}\:{first} \\ $$$${and}\:{second}\:{house}\:{last}\:{year}. \\ $$$$\frac{{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} }=\frac{\mathrm{16}}{\mathrm{23}}…
Question Number 140166 by mathdanisur last updated on 04/May/21 $$\frac{\mathrm{7}−\mathrm{8}\sqrt{\mathrm{7}}{cos}\left(\frac{{arcsin}\left(\frac{\mathrm{3}\sqrt{\mathrm{21}}}{\mathrm{14}}\right)+\mathrm{4}\pi}{\mathrm{3}}\right)}{\mathrm{3}}\:+\:\mathrm{8}{cos}\left(\frac{\mathrm{4}\pi}{\mathrm{7}}\right)=\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74622 by Raxreedoroid last updated on 27/Nov/19 $$\mathrm{Expand} \\ $$$$\mathrm{1}+\frac{\mathrm{2}}{\mathrm{3}}\centerdot\left(\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\left[{cos}\left(\frac{\mathrm{2}\pi}{\mathrm{3}}{x}\right)\right]+\mathrm{2}{n}−\mathrm{2}\right) \\ $$ Commented by Raxreedoroid last updated on 28/Nov/19 $$\mathrm{No}\:\mathrm{its}\:\mathrm{just}\:\mathrm{to}\:\mathrm{clarify}\:\mathrm{whats}\:\mathrm{inside}\:\mathrm{sigma} \\…
Question Number 9087 by sandipkd@ last updated on 17/Nov/16 Commented by 123456 last updated on 17/Nov/16 $$\frac{\partial{w}}{\partial{x}}=\mathrm{4}{cx}+\mathrm{4}+{y} \\ $$$$\frac{\partial{w}}{\partial{y}}=\mathrm{3}{ab}+{x} \\ $$ Terms of Service Privacy…
Question Number 74623 by liki last updated on 27/Nov/19 Commented by liki last updated on 27/Nov/19 $$….\:{I}\:{need}\:{help}\:{plz}… \\ $$ Answered by mr W last updated…