Question Number 74573 by Raxreedoroid last updated on 26/Nov/19 $$\mathrm{Find}\:\left(\mathrm{turn}\:\mathrm{it}\:\mathrm{into}\:\mathrm{non}-\mathrm{segma}\:\mathrm{expression}\right) \\ $$$$\mathrm{1}+\underset{{k}=\mathrm{1}} {\overset{{n}−\mathrm{1}} {\sum}}\frac{\left(−\mathrm{1}\right)^{{k}} +\mathrm{3}}{\mathrm{2}} \\ $$ Commented by mathmax by abdo last updated on…
Question Number 74570 by Learner-123 last updated on 26/Nov/19 $${lim}_{{n}\rightarrow\infty} \frac{\mathrm{1}}{\left({n}\right)^{\frac{\mathrm{1}}{{n}}} }\:=\:? \\ $$ Answered by mind is power last updated on 26/Nov/19 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}n}^{−\frac{\mathrm{1}}{\mathrm{n}}}…
Question Number 140104 by EnterUsername last updated on 04/May/21 $$\mathrm{Let}\:{z}=\mathrm{1}+\mathrm{cos}\left(\mathrm{10}\pi/\mathrm{9}\right)+{i}\mathrm{sin}\left(\mathrm{10}\pi/\mathrm{9}\right).\:\mathrm{Then} \\ $$$$\left(\mathrm{A}\right)\:\mid{z}\mid=\mathrm{2cos}\left(\frac{\mathrm{2}\pi}{\mathrm{9}}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{arg}\:{z}=\frac{\mathrm{8}\pi}{\mathrm{9}} \\ $$$$\left(\mathrm{C}\right)\:\mid{z}\mid=\mathrm{2cos}\left(\frac{\mathrm{4}\pi}{\mathrm{9}}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{arg}\:{z}=\frac{\mathrm{5}\pi}{\mathrm{9}} \\ $$ Commented by EnterUsername last updated on 04/May/21 $$\mathrm{One}\:\mathrm{or}\:\mathrm{more}\:\mathrm{answers}\:\mathrm{may}\:\mathrm{be}\:\mathrm{correct}. \\…
Question Number 140107 by EnterUsername last updated on 04/May/21 $$\mathrm{If}\:{z}_{\mathrm{1}} ,\:{z}_{\mathrm{2}} ,\:\mathrm{and}\:{z}_{\mathrm{3}} \:\mathrm{are}\:\mathrm{the}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle} \\ $$$$\mathrm{described}\:\mathrm{in}\:\mathrm{counterclock}\:\mathrm{sense}\:\mathrm{and}\:{w}\neq\mathrm{1}\:\mathrm{is}\:\mathrm{a}\:\mathrm{cube}\:\mathrm{root} \\ $$$$\mathrm{of}\:\mathrm{unity},\:\mathrm{then} \\ $$$$\left(\mathrm{A}\right)\:{z}_{\mathrm{1}} −{z}_{\mathrm{3}} =\left({z}_{\mathrm{3}} −{z}_{\mathrm{2}} \right){w} \\ $$$$\left(\mathrm{B}\right)\:{z}_{\mathrm{1}}…
Question Number 9032 by ayisha last updated on 15/Nov/16 $$ \\ $$ Commented by mrW last updated on 15/Nov/16 $$\left.\mathrm{can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{use}\:\mathrm{visible}\:\mathrm{ink}?\::\right) \\ $$ Commented by FilupSmith…
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Question Number 9030 by Nemish Zawar last updated on 15/Nov/16 $${f}\left({x}\:,{y}\right)={f}\left(\mathrm{2}{x}+\mathrm{2}{y},\:\mathrm{2}{y}−\mathrm{2}{x}\right) \\ $$$$\mathrm{I}{F}\:{f}\left(\mathrm{2}^{{x}} ,\mathrm{0}\right)={f}\left(\mathrm{2}^{{x}+{k}} ,\mathrm{0}\right) \\ $$$$\boldsymbol{\mathrm{F}}\mathrm{ind}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}>\mathrm{0}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 9029 by rzagung last updated on 15/Nov/16 $$ \\ $$$$\mathrm{2}{cos}\left({x}+\Pi/\mathrm{4}\right)={cos}\left({x}−\Pi/\mathrm{4}\right) \\ $$ Answered by Rasheed Soomro last updated on 15/Nov/16 $$\mathrm{2}{cos}\left({x}+\pi/\mathrm{4}\right)={cos}\left({x}−\pi/\mathrm{4}\right) \\ $$$$\mathrm{cos}\left(\mathrm{x}+\pi/\mathrm{4}\right)+\mathrm{cos}\left(\mathrm{x}+\pi/\mathrm{4}\right)−\mathrm{cos}\left(\mathrm{x}−\pi/\mathrm{4}\right)=\mathrm{0}…
Question Number 140102 by mr W last updated on 04/May/21 $${if}\:{a}_{{n}} −\mathrm{5}{a}_{{n}−\mathrm{1}} +\mathrm{6}{a}_{{n}−\mathrm{2}} =\mathrm{1}\:{and}\: \\ $$$${a}_{\mathrm{0}} =\mathrm{1},\:{a}_{\mathrm{1}} =\mathrm{2}. \\ $$$${find}\:{a}_{{n}} \:{in}\:{terms}\:{of}\:{n}. \\ $$ Commented by…