Question Number 140076 by bobhans last updated on 04/May/21 Commented by mr W last updated on 05/May/21 $${eqn}.\:\mathrm{2}{x}−\mathrm{3}{y}+{a}=\mathrm{0}\:{fixes}\:{only}\:{the} \\ $$$${inclination}\:{of}\:{the}\:{line}.\:{the}\:{vertical} \\ $$$${position}\:{will}\:{be}\:{determined}\:{by}\:{the} \\ $$$${value}\:{of}\:{a}.\:{the}\:{distance}\:{from}\:{point} \\…
Question Number 9004 by mrW last updated on 12/Nov/16 $$\mathrm{prove} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\centerdot\frac{\mathrm{3}}{\mathrm{4}}\centerdot\frac{\mathrm{5}}{\mathrm{6}}\centerdot\centerdot\centerdot\centerdot\centerdot\frac{\mathrm{2n}−\mathrm{1}}{\mathrm{2n}}\leqslant\frac{\mathrm{1}}{\:\sqrt{\mathrm{3n}+\mathrm{1}}} \\ $$ Answered by mrW last updated on 15/Nov/16 $$\mathrm{Using}\:\mathrm{mathematical}\:\mathrm{induction} \\ $$$$\mathrm{prove}\:{P}\left(\mathrm{n}\right)=\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}}…
Question Number 140073 by EDWIN88 last updated on 04/May/21 $$\mathrm{Let}\:\mathrm{f}\left(\mathrm{x}\right)=\begin{cases}{\mathrm{3x}^{\mathrm{2}} −\mathrm{1}\:;\:\mathrm{x}<\mathrm{0}}\\{\mathrm{cx}+\mathrm{d}\:;\:\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{1}}\\{\sqrt{\mathrm{x}+\mathrm{8}}\:;\:\mathrm{x}>\mathrm{1}}\end{cases} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{c}\:\&\:\mathrm{d}\:\mathrm{such}\:\mathrm{that}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{continous} \\ $$$$\mathrm{everywhere} \\ $$ Answered by bobhans last updated on 04/May/21 $$\mathrm{since}\:\underset{{x}\rightarrow\mathrm{0}^{\:−}…
Question Number 140075 by mohammad17 last updated on 04/May/21 $${if}\:{z}=\frac{{x}^{\mathrm{2}} }{{y}}+\mathrm{3}{y}\:\:\:{find}\:{the}\:{absolute}\:{and}\:{relative} \\ $$$${error}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 74536 by mhmd last updated on 25/Nov/19 $${find}\:{limz}\Rightarrow\mathrm{0}\:\:\left({xy}^{\mathrm{2}} /{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)\:{pleas}\:{sir}\:{help}\:{me}\: \\ $$ Answered by mind is power last updated on 26/Nov/19 $$\underset{\left({x},{y}\right)\rightarrow\left(\mathrm{0},\mathrm{0}\right)}…
Question Number 8999 by tawakalitu last updated on 11/Nov/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8998 by tawakalitu last updated on 11/Nov/16 $$\mathrm{If}\:\:\mathrm{2}^{\mathrm{x}} \:=\:\mathrm{3}^{\mathrm{y}} \:=\:\mathrm{6}^{−\mathrm{z}} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\::\:\:\frac{\mathrm{1}}{\mathrm{x}}\:+\:\frac{\mathrm{1}}{\mathrm{y}}\:+\:\frac{\mathrm{1}}{\mathrm{z}} \\ $$ Answered by Rasheed Soomro last updated on 12/Nov/16 $$\mathrm{If}\:\:\mathrm{2}^{\mathrm{x}}…
For-what-value-of-k-is-the-following-continous-function-f-x-7x-2-6x-4-x-2-if-x-2-7-amp-x-2-k-if-x-2-
Question Number 140071 by EDWIN88 last updated on 04/May/21 $$\mathrm{For}\:\mathrm{what}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{is}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{continous}\:\mathrm{function}\:? \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\begin{cases}{\frac{\sqrt{\mathrm{7x}+\mathrm{2}}−\sqrt{\mathrm{6x}+\mathrm{4}}}{\mathrm{x}−\mathrm{2}}\:;\:\mathrm{if}\:\mathrm{x}\geqslant−\frac{\mathrm{2}}{\mathrm{7}}\:\&\:\mathrm{x}\neq\mathrm{2}}\\{\:\:\:\:\:\:\:\:\mathrm{k}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:;\:\mathrm{if}\:\mathrm{x}=\mathrm{2}}\end{cases} \\ $$ Answered by bobhans last updated on 04/May/21 $$\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\mathrm{f}\left(\mathrm{x}\right)=\underset{{x}\rightarrow\mathrm{2}}…
Question Number 8996 by Basant007 last updated on 11/Nov/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{derivative}\:\mathrm{of}\:\mathrm{sin}\:^{\mathrm{2}} \mathrm{2x} \\ $$ Commented by FilupSmith last updated on 13/Nov/16 $${y}=\mathrm{sin}^{\mathrm{2}} \left(\mathrm{2}{x}\right) \\ $$$${u}=\mathrm{sin}\left(\mathrm{2}{x}\right)\:\Rightarrow\:{du}=\mathrm{2cos}\left(\mathrm{2}{x}\right){dx} \\…
Question Number 140064 by Algoritm last updated on 03/May/21 Terms of Service Privacy Policy Contact: info@tinkutara.com