Question Number 8964 by Joel575 last updated on 08/Nov/16 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{solve}\:\mathrm{this}\:\mathrm{problem}? \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{log}\:\left({x}^{\mathrm{3}} \:+\:\left(\mathrm{log}\:{x}\right)^{\mathrm{3}} \right)}{\mathrm{log}\:\left({x}^{\mathrm{2}} \:+\:\left(\mathrm{log}\:{x}\right)^{\mathrm{2}} \right)}\: \\ $$ Commented by sou1618 last updated on…
Question Number 74498 by mathmax by abdo last updated on 25/Nov/19 $$\left.\mathrm{1}\right)\:{calculte}\:\:{A}_{{n}} =\int_{\mathrm{0}} ^{\infty} \:{e}^{−{nx}} \left[{e}^{{x}} \right]\:{dx}\:\:\:{with}\:{n}\:{integr}\:{and}\:{n}\geqslant\mathrm{2} \\ $$$$\left.\mathrm{2}\right){find}\:{lim}_{{n}\rightarrow+\infty} \:{n}^{{n}} \:{A}_{{n}} \\ $$ Commented by…
Question Number 74499 by mathmax by abdo last updated on 25/Nov/19 $${decompose}\:{inside}\:{C}\left({x}\right)\:{the}\:{fraction} \\ $$$${f}\left({x}\right)=\frac{\mathrm{1}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{{n}} } \\ $$ Commented by mathmax by abdo last updated…
Question Number 140029 by metamorfose last updated on 03/May/21 $${si}\:{p}={ab}\:{and}\:\left({a}=\mathrm{1}\:{ou}\:{b}=\mathrm{1}\right)\:{then}\:{p}\:{is}\:{prime}? \\ $$ Answered by MJS_new last updated on 03/May/21 $$\mathrm{example}:\:{a}=\mathrm{1}\wedge{b}=\mathrm{4}\:\Rightarrow\:{p}=\mathrm{4}\:\mathrm{not}\:\mathrm{prime} \\ $$ Terms of Service…
Question Number 140028 by mnjuly1970 last updated on 03/May/21 $$\:\:\:{Evaluate}\:::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{P}\::=\underset{{k}=\mathrm{3}} {\overset{\infty} {\prod}}\frac{\left({k}^{\mathrm{3}} +\mathrm{3}{k}\right)^{\mathrm{2}} }{{k}^{\mathrm{6}} −\mathrm{64}}=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:…………………….. \\ $$ Terms of Service Privacy…
Question Number 8958 by Sopheak last updated on 07/Nov/16 $${Prove}\:{that}\:\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+….+\frac{\mathrm{1}}{\mathrm{2009}}=\mathrm{2009}−\left(\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{3}}{\mathrm{4}}+…+\frac{\mathrm{2008}}{\mathrm{2009}}\right) \\ $$ Answered by sou1618 last updated on 07/Nov/16 $$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}…+\frac{\mathrm{1}}{\mathrm{2009}} \\ $$$$=\left(\mathrm{1}−\frac{\mathrm{0}}{\mathrm{1}}\right)+\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\right)+\left(\mathrm{1}−\frac{\mathrm{2}}{\mathrm{3}}\right)+\left(\mathrm{1}−\frac{\mathrm{3}}{\mathrm{4}}\right)…+\left(\mathrm{1}−\frac{\mathrm{2008}}{\mathrm{2009}}\right) \\ $$$$=\mathrm{2009}−\left(\frac{\mathrm{0}}{\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{3}}{\mathrm{4}}…+\frac{\mathrm{2008}}{\mathrm{2009}}\right) \\…
Question Number 74492 by mathmax by abdo last updated on 24/Nov/19 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left({x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} \:+\mathrm{9}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 8957 by Sopheak last updated on 07/Nov/16 $$\: \\ $$$${Let}\:{n}\:{be}\:{a}\:{positive}\:{integer}\:{such}\:{that}\:{one}\:{of} \\ $$$${the}\:{roofs}\:{of}\:{the}\:{quadratic}\:{equation}\: \\ $$$$\mathrm{4}{x}^{\mathrm{2}} −\left(\mathrm{4}\sqrt{\mathrm{3}}+\mathrm{4}\right){x}+\sqrt{\mathrm{3}}{n}−\mathrm{24}=\mathrm{0}\:{is}\:{an}\:{integer}\: \\ $$$${Find}\:{the}\:{value}\:{of}\:{n}\: \\ $$$$\: \\ $$ Commented by…
Question Number 140030 by mathdanisur last updated on 03/May/21 Answered by mr W last updated on 03/May/21 Commented by mathdanisur last updated on 03/May/21 $${cool}\:{thanks}\:{sir}…
Question Number 8956 by j.masanja06@gmail.com last updated on 07/Nov/16 $$\mathrm{prove}\:\mathrm{that}; \\ $$$$\mathrm{log}_{\mathrm{ab}} \mathrm{x}=\frac{\mathrm{log}_{\mathrm{a}} \mathrm{x}−\mathrm{log}_{\mathrm{b}} \mathrm{x}}{\mathrm{log}_{\mathrm{a}} \mathrm{x}+\mathrm{log}_{\mathrm{b}} \mathrm{x}} \\ $$ Commented by sou1618 last updated on…