Question Number 8884 by tawakalitu last updated on 03/Nov/16 Answered by sandy_suhendra last updated on 04/Nov/16 Commented by sandy_suhendra last updated on 04/Nov/16 $$\mathrm{let}\:\mathrm{AL}=\mathrm{the}\:\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{pointA}\:\mathrm{to}\:\mathrm{the}\:\mathrm{lower}\:\mathrm{hill} \\…
Question Number 74418 by peter frank last updated on 24/Nov/19 Answered by ajfour last updated on 24/Nov/19 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\overset{\:^{\overset{{N}} {\nwarrow}} \underset{\underset{{mg}} {\downarrow}} {\mathbb{C}}\rightarrow_{{mv}^{\mathrm{2}} /{R}} } {\diagup}…
Question Number 74419 by peter frank last updated on 24/Nov/19 Commented by peter frank last updated on 29/Nov/19 $${please} \\ $$ Terms of Service Privacy…
Question Number 139954 by Ar Brandon last updated on 02/May/21 Answered by mr W last updated on 03/May/21 $${x}_{{n}+\mathrm{1}} =\frac{{x}_{{n}} −\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}+\mathrm{1}}}{\mathrm{1}+{x}_{{n}} ×\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}+\mathrm{1}}} \\ $$$${let}\:\mathrm{tan}\:{A}_{{n}} ={x}_{{n}}…
Question Number 139949 by mnjuly1970 last updated on 02/May/21 $$\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:………{nice}\:….\:\ast\:….\ast\:….\:\ast\:….{calculus}\left({I}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\boldsymbol{\phi}=\:\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \left(\sqrt[{\mathrm{3}}]{{cos}\left(\sqrt{{x}}\:\right.}\:\right)^{{cot}\left({x}\right)} =?? \\ $$$$\:\:\:\:\:\:\:\:{solution}……… \\ $$$$\:\:\:\:\:\:\:{sin}\left({x}\right)\:\approx\:{x}\:\:\:\:\:\:\:\:\left({x}\:\rightarrow\:\mathrm{0}\:\right) \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\phi}:=\:\:{lim}_{{x}\rightarrow\mathrm{0}^{+} } \left\{\left({cos}\left(\sqrt{{x}}\:\right)\right)^{\frac{\mathrm{1}}{\mathrm{3}}}…
Question Number 139948 by qaz last updated on 02/May/21 $${If}\:\:\:\:{x}^{\mathrm{2}} +{xy}+{y}^{\mathrm{2}} =\mathrm{0} \\ $$$${find}\:::\:\:\:\left(\frac{{x}}{{x}+{y}}\right)^{\mathrm{2023}} +\left(\frac{{y}}{{x}+{y}}\right)^{\mathrm{2023}} \\ $$ Answered by Rasheed.Sindhi last updated on 04/May/21 $$\frac{{x}}{{y}}+\frac{{y}}{{x}}=−\mathrm{1}\Rightarrow\frac{{y}}{{x}}=−\left(\mathrm{1}+\frac{{x}}{{y}}\right)…
Question Number 74415 by Learner-123 last updated on 24/Nov/19 Commented by Learner-123 last updated on 24/Nov/19 $${please}\:{solve}\:{this}\:{by}\:{conservation}\:{of} \\ $$$${energy}. \\ $$ Answered by ajfour last…
Question Number 74412 by ajfour last updated on 24/Nov/19 $${a},{b},{c}\:{are}\:{given}\:{real}\:{constants}. \\ $$$${p},{q},{r},{t}\:{are}\:{unknowns}\:{from}\:{which} \\ $$$${we}\:{can}\:{choose}\:{values}\:{of}\:{two}\:{of} \\ $$$${them}\:\left({non}\:{zero}\right)\:{and}\:{have}\:{to}\: \\ $$$${determine}\:{the}\:{other}\:{two}\:\left({non}\:{zero}\right), \\ $$$${obeying}\:\:{two}\:{equations}\:{given}\:{below} \\ $$$$\:{p}^{\mathrm{2}} +{q}\left(\mathrm{1}+{bq}\right){t}^{\mathrm{2}} +{q}\left({ap}+{br}\right){t} \\…
Question Number 8877 by tawakalitu last updated on 03/Nov/16 Commented by Rasheed Soomro last updated on 03/Nov/16 $$\mathrm{Not}\:\mathrm{related}\:\mathrm{to}\:\mathrm{this}\:\mathrm{question}. \\ $$$$\mathrm{Please}\:\mathrm{see}\:\mathrm{my}\:\mathrm{answers}\:\mathrm{to}\:\mathrm{your} \\ $$$$\mathrm{question}\:#\mathrm{8847}\:\:\:\mathrm{and}\:\mathrm{confirm} \\ $$$$\mathrm{whether}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{is}\:\mathrm{correct} \\…
Question Number 139950 by I want to learn more last updated on 02/May/21 Answered by TheSupreme last updated on 02/May/21 $${y}={y}_{\mathrm{0}} +\mathrm{6}{t}−\frac{\mathrm{4}}{\mathrm{2}}{t}^{\mathrm{2}} −{v}_{\mathrm{0},{raptor}} {t} \\…