Question Number 8794 by faster1998 last updated on 28/Oct/16 $${f}\left({x}\right)=×^{\frac{\mathrm{4}}{\mathrm{3}}} −\mathrm{2}×^{\frac{\mathrm{1}}{\mathrm{3}}} \\ $$ Commented by ridwan balatif last updated on 28/Oct/16 $$\mathrm{f}\left(\mathrm{x}\right)\:=\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{3}}} .\mathrm{x}−\mathrm{2x}^{\frac{\mathrm{1}}{\mathrm{3}}} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)\:=\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{3}}}…
Question Number 139867 by Maclaurin Stickker last updated on 01/May/21 $${a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} =\mathrm{0} \\ $$$${a}^{\mathrm{12}} +{b}^{\mathrm{12}} +{c}^{\mathrm{12}} =\mathrm{8} \\ $$$${a}^{\mathrm{6}} +{b}^{\mathrm{6}} +{c}^{\mathrm{6}} =? \\…
Question Number 74328 by arthur.kangdani@gmail.com last updated on 22/Nov/19 Answered by ajfour last updated on 22/Nov/19 $${x}=\frac{\begin{vmatrix}{\mathrm{10}}&{\mathrm{2}}&{\mathrm{4}}\\{\mathrm{4}}&{\mathrm{10}}&{\mathrm{7}}\\{\mathrm{9}}&{\mathrm{5}}&{\mathrm{16}}\end{vmatrix}_{} }{\begin{vmatrix}{\mathrm{6}}&{\mathrm{2}}&{\mathrm{4}}\\{\mathrm{9}}&{\mathrm{10}}&{\mathrm{7}}\\{\mathrm{12}}&{\mathrm{5}}&{\mathrm{16}}\end{vmatrix}^{} } \\ $$$$\Rightarrow\:\:{x}=\frac{\mathrm{10}\left(\mathrm{160}−\mathrm{35}\right)−\mathrm{2}\left(\mathrm{64}−\mathrm{63}\right)+\mathrm{4}\left(\mathrm{20}−\mathrm{90}\right)}{\mathrm{6}\left(\mathrm{160}−\mathrm{35}\right)−\mathrm{2}\left(\mathrm{144}−\mathrm{84}\right)+\mathrm{4}\left(\mathrm{45}−\mathrm{120}\right)} \\ $$$$\:\:\:\:\:{x}=\frac{\mathrm{1250}−\mathrm{2}−\mathrm{280}}{\mathrm{750}−\mathrm{120}−\mathrm{300}}\:=\:\frac{\mathrm{968}}{\mathrm{330}}\:=\:\frac{\mathrm{88}}{\mathrm{30}} \\ $$$$…..…
Question Number 74329 by Learner-123 last updated on 22/Nov/19 $${Solve}\:: \\ $$$${ax}+{by}={r} \\ $$$${bx}−{ay}={s} \\ $$ Commented by Learner-123 last updated on 22/Nov/19 $${any}\:{short}\:{method}\:{when}\:{a},{b},{r},{s}\:{are}\: \\…
Question Number 139861 by mathdanisur last updated on 01/May/21 $$\sqrt[{\mathrm{3}}]{\mathrm{2}\boldsymbol{{z}}+\mathrm{1}}\:+\:\sqrt[{\mathrm{5}}]{\mathrm{8}\boldsymbol{{z}}+\mathrm{4}}\:=\:\sqrt{\mathrm{16}} \\ $$ Answered by mindispower last updated on 01/May/21 $${z}=\frac{\mathrm{7}}{\mathrm{2}},{solution} \\ $$$${over}\:\mathbb{R} \\ $$$${f}\left({z}\right)=\sqrt[{\mathrm{3}}]{\mathrm{2}{z}+\mathrm{1}}+\sqrt[{\mathrm{5}}]{\mathrm{8}{z}+\mathrm{4}}\:{is}\:{increase}\:{function} \\…
Question Number 8789 by tawakalitu last updated on 27/Oct/16 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{general}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\frac{\mathrm{2xy}\:+\:\mathrm{y}^{\mathrm{2}} }{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{2xy}} \\ $$ Commented by Yozzias last updated on 27/Oct/16 $$\mathrm{Let}\:\mathrm{y}=\mathrm{ux}\Rightarrow\mathrm{y}'=\mathrm{u}+\mathrm{xu}' \\…
Question Number 8788 by vuckintv last updated on 27/Oct/16 $${Solve}\:{for}\:\alpha \\ $$$$ \\ $$$${U}\left({z}\right)={U}_{{b}} +\frac{\mathrm{2}{A}}{{n}+\mathrm{1}}\left(\rho×{g}×\alpha\right)^{{n}} \left[{H}−{i}\left({H}−{Z}\right)^{{n}+\mathrm{1}} \right] \\ $$ Commented by ridwan balatif last updated…
Question Number 74322 by naka3546 last updated on 22/Nov/19 $${Let}\:\: \\ $$$${k}\:\:=\:\:\frac{\left({xy}\:+\:{yz}\:+\:{zx}\right)\left({x}\:+\:{y}\:+\:{z}\right)}{\left({x}\:+\:{y}\right)\left({y}\:+\:{z}\right)\left({z}\:+\:{x}\right)} \\ $$$${Find}\:\:{the}\:\:{minimum}\:\:{and}\:\:{maximum}\:\:{value}\:\:{of}\:\:\:{k}\:. \\ $$ Answered by MJS last updated on 23/Nov/19 $${k}−\mathrm{1}=\frac{{xyz}}{\left({x}+{y}\right)\left({x}+{z}\right)\left({y}+{z}\right)} \\…
Question Number 74323 by arthur.kangdani@gmail.com last updated on 22/Nov/19 Commented by arthur.kangdani@gmail.com last updated on 22/Nov/19 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{inverse}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{matrix}\:\mathrm{of}\:{AB}+{C}! \\ $$ Commented by mathmax by…
Question Number 74320 by malikmasood3535@gmail.com last updated on 22/Nov/19 $$\int_{\mathrm{0}} ^{{x}} {x}\:{e}^{{x}} \left(\mathrm{cos}\:\:{e}^{{x}} \right){e}^{{x}} {dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com