Menu Close

Author: Tinku Tara

9-9-

Question Number 8582 by thomas last updated on 16/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$ Answered by Rasheed Soomro last updated on 17/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)\left(\mathrm{10}−\mathrm{1}\right) \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)^{\mathrm{2}}…

Question-139655

Question Number 139655 by mohammad17 last updated on 30/Apr/21 Answered by qaz last updated on 30/Apr/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {x}\mathrm{tan}^{−\mathrm{1}} \left({x}\right){ln}\left({x}^{\mathrm{2}} +\mathrm{1}\right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{tan}^{−\mathrm{1}}…

Find-the-volume-of-the-solid-that-lies-within-the-sphere-x-2-y-2-z-2-16-above-the-x-y-plane-and-below-the-cone-z-x-2-y-2-

Question Number 74117 by necxxx last updated on 19/Nov/19 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{that}\:{lies} \\ $$$${within}\:{the}\:{sphere}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{16},\:{above} \\ $$$${the}\:{x}-{y}\:{plane}\:{and}\:{below}\:{the}\:{cone} \\ $$$${z}=\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\ $$ Commented by…

Question-8578

Question Number 8578 by tawakalitu last updated on 16/Oct/16 Answered by ridwan balatif last updated on 17/Oct/16 Commented by tawakalitu last updated on 17/Oct/16 $$\mathrm{Thanks}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}.\:\mathrm{for}\:\mathrm{your}\:\mathrm{help}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}…

Question-74112

Question Number 74112 by TawaTawa last updated on 19/Nov/19 Answered by mind is power last updated on 19/Nov/19 $${let}\:{l}={side}\:{of}\:{squar}\Rightarrow{l}^{\mathrm{2}} +\frac{{l}}{\mathrm{2}}\left({x}+{z}+{y}\right)=\frac{\left({z}+{l}+{y}\right)}{\mathrm{2}}\left({l}+{x}\right) \\ $$$$\Leftrightarrow\mathrm{2}{l}^{\mathrm{2}} +{l}\left({x}+{y}+{z}\right)={l}\left({z}+{y}+{l}\right)+{x}\left({z}+{l}+{y}\right) \\ $$$$\Rightarrow\mathrm{2}{l}^{\mathrm{2}}…

Question-139645

Question Number 139645 by otchereabdullai@gmail.com last updated on 30/Apr/21 Commented by mr W last updated on 30/Apr/21 $${OD}={AO}×\mathrm{sin}\:\angle{OAB}=\mathrm{52}×\frac{\mathrm{5}}{\mathrm{13}}=\mathrm{20} \\ $$$${BD}=\sqrt{\mathrm{25}^{\mathrm{2}} −\mathrm{20}^{\mathrm{2}} }=\mathrm{15} \\ $$$${BC}=\mathrm{2}×{BD}=\mathrm{2}×\mathrm{15}=\mathrm{30} \\…

a-b-c-R-ax-5-bx-3-cx-1-x-1-proof-a-16-b-20-c-5-

Question Number 139644 by mathdanisur last updated on 30/Apr/21 $${a};{b};{c}\in\mathbb{R},\:\mid{ax}^{\mathrm{5}} +{bx}^{\mathrm{3}} +{cx}\mid\leqslant\mathrm{1},\:\forall\mid{x}\mid\leqslant\mathrm{1} \\ $$$${proof}:\:\mid{a}\mid\leqslant\mathrm{16},\:\mid{b}\mid\leqslant\mathrm{20},\:\mid{c}\mid\leqslant\mathrm{5} \\ $$ Answered by ajfour last updated on 30/Apr/21 $${let}\:\:\mid{x}\mid={r} \\…