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Author: Tinku Tara

A-2-b-translation-T-1-3-b-followed-by-translation-T-2-a-4-A-b-1-a-3-determine-the-value-of-a-b-

Question Number 8528 by suci last updated on 14/Oct/16 $${A}\left(\mathrm{2},{b}\right)\:{translation}\:{T}_{\mathrm{1}} =\begin{pmatrix}{−\mathrm{3}}\\{\:\:\:{b}}\end{pmatrix} \\ $$$${followed}\:{by}\:{translation}\:{T}_{\mathrm{2}} =\begin{pmatrix}{{a}}\\{\mathrm{4}}\end{pmatrix} \\ $$$${A}'=\left({b}−\mathrm{1},{a}−\mathrm{3}\right) \\ $$$${determine}\:{the}\:{value}\:{of}\:{a}+{b}=…? \\ $$ Answered by sandy_suhendra last updated…

6-32-

Question Number 8527 by suci last updated on 14/Oct/16 $$\sqrt{\mathrm{6}−\sqrt{\mathrm{32}}}\:=…? \\ $$ Answered by prakash jain last updated on 14/Oct/16 $$\sqrt{\mathrm{6}−\sqrt{\mathrm{32}}}=\sqrt{\mathrm{6}−\mathrm{4}\sqrt{\mathrm{2}}} \\ $$$$\sqrt{\mathrm{6}−\mathrm{4}\sqrt{\mathrm{2}}}=\sqrt{\mathrm{a}}−\sqrt{\mathrm{b}} \\ $$$$\mathrm{squaring}…

8-2-5-

Question Number 8526 by suci last updated on 14/Oct/16 $$\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}\:=\:…? \\ $$ Answered by ridwan balatif last updated on 14/Oct/16 $$\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}=\sqrt{\mathrm{k}}+\sqrt{\mathrm{p}} \\ $$$$\left(\sqrt{\mathrm{8}+\mathrm{2}\sqrt{\mathrm{5}}}\right)^{\mathrm{2}} =\left(\sqrt{\mathrm{k}}+\sqrt{\mathrm{p}}\right)^{\mathrm{2}} \\…

Given-f-x-2-x-2-x-2-x-2-If-g-f-x-2x-1-then-g-1-1-

Question Number 139592 by bemath last updated on 29/Apr/21 $$\mathrm{Given}\:\mathrm{f}\left(\mathrm{x}\right)=\sqrt{\mathrm{2}+\mathrm{x}^{\mathrm{2}} −\mathrm{x}}\:+\sqrt{\mathrm{2}−\mathrm{x}^{\mathrm{2}} } \\ $$$$\mathrm{If}\:\left(\mathrm{g}\circ\mathrm{f}\right)\left(\mathrm{x}\right)\:=\:\mathrm{2x}+\mathrm{1}\:\mathrm{then}\:\mathrm{g}^{−\mathrm{1}} \left(−\mathrm{1}\right)=? \\ $$ Answered by EDWIN88 last updated on 29/Apr/21 $$\Rightarrow\left(\mathrm{g}\circ\mathrm{f}\right)\left(\mathrm{x}\right)=\:\mathrm{2x}+\mathrm{1}\:;\:\mathrm{g}^{−\mathrm{1}}…