Question Number 8352 by tawakalitu last updated on 09/Oct/16 $$\mathrm{make}\:\mathrm{t}\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\mathrm{the}\:\mathrm{formular}. \\ $$$$\mathrm{s}\:=\:\mathrm{ut}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}^{\mathrm{2}} \:+\:\mathrm{3t}^{\mathrm{3}} \\ $$ Answered by fernandodantas1996 last updated on 13/Oct/16 $$\mathrm{s}\:=\:\mathrm{t}\left(\mathrm{u}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}+\mathrm{3t}^{\mathrm{2}} \right)\:\Leftrightarrow\:\mathrm{t}\:=\:\frac{\mathrm{s}}{\mathrm{u}\:+\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}\:+\:\mathrm{3t}^{\mathrm{2}} }…
Question Number 8351 by Nayon last updated on 09/Oct/16 $$ \\ $$$$\:\:\:{x}^{\mathrm{2}} =\mathrm{816}−\mathrm{64}\sqrt{\mathrm{77}} \\ $$$$\:\:\:{x}=?\left[{write}\:{x}\:{like}\:{a}\sqrt{{c}\:}+{b}\sqrt{\left.{d}\right]}\right. \\ $$$$ \\ $$ Commented by ridwan balatif last updated…
Question Number 8350 by Nayon last updated on 09/Oct/16 $${solve}: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\frac{\mathrm{5}}{\mathrm{3}{x}+\mathrm{2}}+\frac{\mathrm{8}}{\mathrm{4}{x}+\mathrm{2}}=\frac{\mathrm{33}}{\mathrm{9}{x}+\mathrm{8}} \\ $$ Answered by Rasheed Soomro last updated on 10/Oct/16 $$\:\frac{\mathrm{5}}{\mathrm{3}{x}+\mathrm{2}}+\frac{\mathrm{8}}{\mathrm{4}{x}+\mathrm{2}}=\frac{\mathrm{33}}{\mathrm{9}{x}+\mathrm{8}}…
Question Number 73884 by abdusalamyussif@gmail.com last updated on 16/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 139422 by 676597498 last updated on 26/Apr/21 $${C}_{{n}} ^{\:\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{8}}{P}_{{n}\:} ^{\:\mathrm{8}} \\ $$$${find}\:{n} \\ $$ Commented by mohammad17 last updated on 27/Apr/21 $${can}\:{not}\:{find}\:{value}\:{of}\:{n}\:{in}\:{this}\:{form}…
Question Number 8347 by sou1618 last updated on 09/Oct/16 $${a}_{\mathrm{1}} =\mathrm{2}\:,\:\:{a}_{{n}+\mathrm{1}} >{a}_{{n}} \\ $$$$\left({a}_{{n}+\mathrm{1}} −{a}_{{n}} \right)^{\mathrm{2}} =\:\mathrm{2}\left({a}_{{n}+\mathrm{1}} +{a}_{{n}} \right) \\ $$$$\:{a}_{{n}} =?? \\ $$$${help}\:{me}\:{please}. \\…
Question Number 139419 by mathocean1 last updated on 26/Apr/21 $${ABCD}\:{is}\:{a}\:{rectangle}\:{such}\:{that}\: \\ $$$${AD}=\mathrm{2}{AB}\:{and}\:{its}\:{center}\:{is}\:{O}.\: \\ $$$${H}\:{is}\:{the}\:{top}\:{of}\:{a}\:{pyramid}\:{which} \\ $$$${has}\:{ABCD}\:{as}\:{base}.\:{All}\:{lateral} \\ $$$${faces}\:{are}\:{isosceles}\:{triangles}.\:{planes} \\ $$$$\left({HAB}\right)\:{and}\:\left({HCD}\right)\:{are}\:\bot. \\ $$$${i}\:{have}\:{joined}\:{a}\:{graphic}. \\ $$$$\mathrm{1}.\:{show}\:{that}\:\left({OH}\right)\bot\left({ABC}\right). \\…
Question Number 8345 by suci last updated on 09/Oct/16 $${y}=\left({x}+\mathrm{2}\right)^{\mathrm{2}} −\mathrm{3} \\ $$$${Translation}\:{T}_{\mathrm{1}} =\begin{pmatrix}{{a}}\\{{b}}\end{pmatrix} \\ $$$${y}'={x}^{\mathrm{2}} \\ $$$${a}=?\:{b}=? \\ $$ Answered by sandy_suhendra last updated…
Question Number 8341 by Rasheed Soomro last updated on 09/Oct/16 $$\mathrm{What}\:\mathrm{are}\:\mathrm{necessary}\:\mathrm{and}\:\mathrm{sufficient}\:\mathrm{conditions} \\ $$$$\mathrm{that}\:\left(\mathrm{a}+\mathrm{ib}\right)^{\mathrm{n}} \:\mathrm{is}\:\mathrm{cyclic}\:\mathrm{for}\:\mathrm{an}\:\:\mathrm{n}\:\mathrm{not}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{0}? \\ $$ Answered by prakash jain last updated on 09/Oct/16 $$\mid{a}+{ib}\mid=\mathrm{1}\Rightarrow\sqrt{{a}^{\mathrm{2}}…
Question Number 139414 by mathdanisur last updated on 26/Apr/21 $$\underset{\:\mathrm{0}} {\overset{\:\pi/\mathrm{2}} {\int}}\frac{{cos}^{\mathrm{2}} {x}}{{cos}\left({x}−\pi/\mathrm{4}\right)}\:{dx} \\ $$ Commented by mr W last updated on 27/Apr/21 $$\frac{\mathrm{1}}{\mathrm{2}}\left[\mathrm{ln}\:\frac{\mathrm{1}+\mathrm{sin}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)}{\mathrm{1}−\mathrm{sin}\:\left({x}−\frac{\pi}{\mathrm{4}}\right)}\right]_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…