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Author: Tinku Tara

0-1-ln-1-x-x-2-x-dx-0-1-ln-1-x-3-ln-1-x-x-dx-pi-2-6-0-1-x-3n-1-n-dx-n-1-1-3n-2-pi-2-18-pi-2-9-

Question Number 139224 by mnjuly1970 last updated on 24/Apr/21 $$\:\:\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left(\mathrm{1}+{x}+{x}^{\mathrm{2}} \right)}{{x}}{dx} \\ $$$$\:\:\:\phi=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left(\mathrm{1}−{x}^{\mathrm{3}} \right)−{ln}\left(\mathrm{1}−{x}\right)}{{x}}{dx} \\ $$$$\:\:\:\:=\Omega+\frac{\pi^{\mathrm{2}} }{\mathrm{6}} \\ $$$$\:\:\:\:\Omega=−\Sigma\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{x}^{\mathrm{3}{n}−\mathrm{1}}…

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Question Number 139226 by Dwaipayan Shikari last updated on 24/Apr/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{{x}^{\mathrm{2}} } {dx}=\frac{{e}}{\mathrm{1}+\frac{\mathrm{2}}{\mathrm{1}+\frac{\mathrm{4}}{\mathrm{1}+\frac{\mathrm{6}}{\mathrm{1}+\frac{\mathrm{8}}{\mathrm{1}+\frac{\mathrm{10}}{\mathrm{1}+…}}}}}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

show-that-the-plane-x-2y-3z-d-0-is-perpendiculr-to-each-of-the-plane-is-2x-5y-4z-1-0-and-4x-7y-3z-2-0-

Question Number 8150 by trapti rathaur@ gmail.com last updated on 02/Oct/16 $${show}\:{that}\:{the}\:{plane}\:\:\:{x}+\mathrm{2}{y}−\mathrm{3}{z}+{d}=\mathrm{0}\:\:{is}\:{perpendiculr}\:{to}\:{each}\:{of} \\ $$$${the}\:{plane}\:{is}\:\:\:\mathrm{2}{x}+\mathrm{5}{y}+\mathrm{4}{z}+\mathrm{1}=\mathrm{0}\:\:{and}\:\:\:\mathrm{4}{x}+\mathrm{7}{y}+\mathrm{3}{z}+\mathrm{2}=\mathrm{0}\:.\: \\ $$ Commented by 123456 last updated on 03/Oct/16 $$\alpha:{x}+\mathrm{2}{y}−\mathrm{3}{z}+{d}=\mathrm{0} \\…

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Question Number 139217 by mnjuly1970 last updated on 24/Apr/21 $$\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:…..\:{nice}\:….\:….\:{math}…. \\ $$$$\:\:\:{prove}\:{that}: \\ $$$$\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \frac{{ln}\left(\mathrm{1}+{sin}\left({x}\right).{cos}\left({x}\right)\right)}{{tan}\left({x}\right)}{dx}=\frac{\mathrm{5}\pi^{\mathrm{2}} }{\mathrm{72}} \\ $$ Commented by liki last…

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Question Number 73679 by Tinku Tara last updated on 14/Nov/19 $$\mathrm{We}\:\mathrm{have}\:\mathrm{updated}\:\mathrm{backend}\:\mathrm{code}\:\mathrm{to}\: \\ $$$$\mathrm{disallow}\:\mathrm{delete}\:\mathrm{of}\:\mathrm{question}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{already}\:\mathrm{answered}\:\mathrm{or}\:\mathrm{commented}. \\ $$$$ \\ $$ Commented by malwaan last updated on…

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Question Number 8139 by sou1618 last updated on 01/Oct/16 $${is}\:{it}\:{correct}? \\ $$$${when} \\ $$$${S}_{{n}} =\left\{\right. \\ $$$$\mathrm{1}×\mathrm{2}+\mathrm{1}×\mathrm{3}+\mathrm{1}×\mathrm{4}+\mathrm{1}×\mathrm{5}+…….+\mathrm{1}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:+\mathrm{2}×\mathrm{3}+\mathrm{2}×\mathrm{4}+\mathrm{2}×\mathrm{5}+…….+\mathrm{2}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\mathrm{3}×\mathrm{4}+\mathrm{3}×\mathrm{5}+…….+\mathrm{3}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\mathrm{4}×\mathrm{5}+…….+\mathrm{4}×{n} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:….…