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Author: Tinku Tara

It-is-desired-to-set-the-operating-point-at-3-5V-2-2mA-by-biasing-a-silicon-transistor-with-feedback-resistor-if-Beta-100-find-the-value-of-R-b-and-R-c-taking-V-be-0-7V-

Question Number 8130 by tawakalitu last updated on 01/Oct/16 $${It}\:{is}\:{desired}\:{to}\:{set}\:{the}\:{operating}\:{point}\:{at}\:\mathrm{3}.\mathrm{5}{V},\: \\ $$$$\mathrm{2}.\mathrm{2}{mA}\:{by}\:{biasing}\:{a}\:{silicon}\:{transistor}\:{with}\: \\ $$$$\left.{feedback}\:{resistor}\right).\:{if}\:\:{Beta}\:=\:\mathrm{100},\:{find}\:{the}\:{value} \\ $$$${of}\:{R}_{{b}} \:{and}\:{R}_{{c}} \:\:{taking}\:\:{V}_{{be}} \:=\:\mathrm{0}.\mathrm{7}{V} \\ $$ Terms of Service Privacy…

For-x-lt-1-we-have-that-1-x-1-2-1-1-2-x-1-2-1-2-1-2-x-2-1-2-1-2-1-1-2-2-3-x-3-1-x-1-2-1-r-1-k-0-r-1-0-5-k-r-x-r-Let-g-r-k-0-

Question Number 8127 by Yozzia last updated on 30/Sep/16 $${For}\:\mid{x}\mid<\mathrm{1},\:{we}\:{have}\:{that} \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\left(\frac{\mathrm{1}}{\mathrm{2}}\right)\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{1}\right)}{\mathrm{2}!}{x}^{\mathrm{2}} +\frac{\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{1}\right)\left(\frac{\mathrm{1}}{\mathrm{2}}−\mathrm{2}\right)}{\mathrm{3}!}{x}^{\mathrm{3}} +… \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{1}+\underset{{r}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\underset{{k}=\mathrm{0}} {\overset{{r}−\mathrm{1}} {\prod}}\left(\mathrm{0}.\mathrm{5}−{k}\right)}{{r}!}{x}^{{r}} . \\ $$$${Let}\:{g}\left({r}\right)=\underset{{k}=\mathrm{0}}…

Question-73663

Question Number 73663 by ajfour last updated on 14/Nov/19 Answered by ajfour last updated on 15/Nov/19 $${See}\:{Q}.\mathrm{73673} \\ $$$${V}=\mathrm{2}\int\left(\left(\frac{\rho^{\mathrm{2}} \left(\mathrm{2}\phi\right)}{\mathrm{2}}×\left(−{ds}\right)\right)\right. \\ $$$$\:\rho={s}\mathrm{sin}\:\alpha={s}\mathrm{sin}\:\frac{\pi}{\mathrm{6}}\:=\:\frac{{s}}{\mathrm{2}} \\ $$$$\:{s}=\frac{{a}\sqrt{\mathrm{3}}−{r}\left(\mathrm{1}−\mathrm{cos}\:\theta\right)}{\mathrm{cos}\:\alpha}=\frac{\mathrm{2}{a}}{\mathrm{3}}\left(\mathrm{2}+\mathrm{cos}\:\theta\right) \\…

m-1-32-3m-2-n-1-10-sin-2npi-11-icos-2npi-11-m-A-4-1-i-B-12-1-i-C-12-1-i-D-48-1-i-

Question Number 139193 by EnterUsername last updated on 23/Apr/21 $$\underset{{m}=\mathrm{1}} {\overset{\mathrm{32}} {\sum}}\left(\mathrm{3}{m}+\mathrm{2}\right)\left(\underset{{n}=\mathrm{1}} {\overset{\mathrm{10}} {\sum}}\left(\mathrm{sin}\left(\frac{\mathrm{2}{n}\pi}{\mathrm{11}}\right)−\mathrm{icos}\left(\frac{\mathrm{2}{n}\pi}{\mathrm{11}}\right)\right)\right)^{{m}} = \\ $$$$\left(\mathrm{A}\right)\:\mathrm{4}\left(\mathrm{1}−{i}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{12}\left(\mathrm{1}+{i}\right) \\ $$$$\left(\mathrm{C}\right)\:\mathrm{12}\left(\mathrm{1}−{i}\right)\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{48}\left(\mathrm{1}−{i}\right) \\ $$ Answered by qaz last…