Question Number 139164 by mathlove last updated on 23/Apr/21 Answered by qaz last updated on 25/Apr/21 $${ln}\left(\mathrm{1}−{ae}^{{ix}} \right) \\ $$$$={ln}\left[\mathrm{1}−{a}\left(\mathrm{cos}\:{x}+{i}\mathrm{sin}\:{x}\right)\right] \\ $$$$={ln}\left(\sqrt{\left(\mathrm{1}−{a}\mathrm{cos}\:{x}\right)^{\mathrm{2}} +\left({a}\mathrm{sin}\:{x}\right)^{\mathrm{2}} }{e}^{{i}\mathrm{tan}^{−\mathrm{1}} \frac{−{a}\mathrm{sin}\:{x}}{\mathrm{1}−{a}\mathrm{cos}\:{x}}}…
Question Number 139167 by Dwaipayan Shikari last updated on 23/Apr/21 Answered by mr W last updated on 23/Apr/21 Commented by mr W last updated on…
Question Number 73628 by Waseem Yaqoob last updated on 14/Nov/19 $${find}\:{coefficient}\:{of}\:{x}^{{r}\:} \:{in}\:{the}\:{expension}\:{of}\: \\ $$$$\:\left(\mathrm{2}{x}−\mathrm{6}{y}\right)^{−\mathrm{8}} \\ $$ Answered by mr W last updated on 14/Nov/19 $$\left(\mathrm{2}{x}−\mathrm{6}{y}\right)^{−\mathrm{8}}…
Question Number 8093 by Tinku Tara last updated on 30/Sep/16 $$\mathrm{App}\:\mathrm{has}\:\mathrm{been}\:\mathrm{updated}\:\left(\mathrm{ver}\:\mathrm{1}.\mathrm{48}\right) \\ $$$$\bullet\:\mathrm{Customizable}\:\mathrm{key}\:\mathrm{screen}\:\bigstar \\ $$$$\:\:\:\:\mathrm{long}\:\mathrm{press}\:\mathrm{on}\:\mathrm{any}\:\mathrm{key}\:\mathrm{on}\:\mathrm{that}\:\mathrm{screen} \\ $$$$\:\:\:\:\mathrm{to}\:\mathrm{change}\:\mathrm{the}\:\mathrm{symbol}\:\mathrm{on}\:\mathrm{that}\:\mathrm{location} \\ $$$$\bullet\:\:\mathrm{Choose}\:\mathrm{default}\:\mathrm{font}\:\mathrm{size}\:\mathrm{and}\:\mathrm{style} \\ $$$$\bullet\:\:\mathrm{option}\:\mathrm{menu}\:\mathrm{for}\:\mathrm{quicker}\:\mathrm{access}\:\mathrm{to}\:\mathrm{long} \\ $$$$\:\:\:\:\:\mathrm{press}\:\mathrm{menu} \\ $$$$\bullet\:\:\:\mathrm{new}\:\mathrm{symbols}\:\mathrm{and}\:\mathrm{right}\:\mathrm{curly}\:\mathrm{brace}\:\mathrm{matrix}…
Question Number 139159 by rs4089 last updated on 23/Apr/21 $${solve}\:{PDE}\:\:\:\:\:\:\:\:\:{py}^{\mathrm{3}} +{qx}^{\mathrm{2}} =\mathrm{0}\:\: \\ $$ Commented by Dwaipayan Shikari last updated on 23/Apr/21 $$\frac{\partial^{\mathrm{3}} {f}\left({x},{y}\right)}{\partial{y}^{\mathrm{3}} }+\frac{\partial^{\mathrm{2}}…
Question Number 73620 by L.Messi last updated on 14/Nov/19 Answered by MJS last updated on 14/Nov/19 $$\mathrm{do}\:\mathrm{you}\:\mathrm{at}\:\mathrm{least}\:\mathrm{know}\:\mathrm{what}\:\mathrm{Euler}'\mathrm{s}\:\mathrm{Circle}\:\mathrm{is}, \\ $$$$\mathrm{Sir}\:\mathrm{L}.\:\mathrm{Messi}? \\ $$ Commented by L.Messi last…
Question Number 139153 by henderson last updated on 23/Apr/21 $$\boldsymbol{\mathrm{hi}},\:\boldsymbol{\mathrm{everybody}}\:! \\ $$$$\boldsymbol{\mathrm{for}}\:{f}\left({x}\right)=\int_{{x}} ^{\:{x}^{\mathrm{2}} } \:\:\frac{{ln}\left(\mathrm{1}+{t}^{\mathrm{2}} \right)}{{t}}\:{dt} \\ $$$$\mathrm{1}.\:\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{domain}}\:\boldsymbol{\mathrm{of}}\:{f},\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{that}}\:{f}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{even}}. \\ $$$$\mathrm{2}.\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{that}}\:{f}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{differentiable}}\:\boldsymbol{\mathrm{on}}\:\mathbb{R},\:\boldsymbol{\mathrm{find}}\:{f}\:^{'} \left({x}\right). \\ $$$$\mathrm{3}.\:\boldsymbol{\mathrm{determine}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{expansion}}\:\boldsymbol{\mathrm{limited}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{order}}\:\mathrm{4}\:\boldsymbol{\mathrm{of}}\:{f} \\ $$$$\boldsymbol{\mathrm{in}}\:\mathrm{0}.…
Question Number 139152 by TheSupreme last updated on 23/Apr/21 $${wich}\:{program}\:{to}\:{run}\:\:{genetic}\:{algorithm}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73619 by L.Messi last updated on 14/Nov/19 Commented by MJS last updated on 14/Nov/19 $$\mathrm{what}'\mathrm{s}\:\mathrm{your}\:\mathrm{idea},\:\mathrm{Sir}\:\mathrm{L}.\:\mathrm{Messi}? \\ $$ Commented by L.Messi last updated on…
Question Number 8082 by tawakalitu last updated on 29/Sep/16 Terms of Service Privacy Policy Contact: info@tinkutara.com