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Author: Tinku Tara

let-P-x-1-ix-n-1-ix-n-with-n-integr-decompose-the-Fraction-F-x-1-P-x-

Question Number 73486 by abdomathmax last updated on 13/Nov/19 $${let}\:{P}\left({x}\right)=\left(\mathrm{1}+{ix}\right)^{{n}} −\left(\mathrm{1}−{ix}\right)^{{n}} \:{with}\:{n}\:{integr} \\ $$$${decompose}\:{the}\:{Fraction}\:{F}\:\left({x}\right)=\frac{\mathrm{1}}{{P}\left({x}\right)} \\ $$ Commented by abdomathmax last updated on 17/Nov/19 $${P}\left({x}\right)=\mathrm{0}\:\Leftrightarrow\frac{\left(\mathrm{1}−{ix}\right)^{{n}} }{\left(\mathrm{1}+{ix}\right)^{{n}}…

let-and-roots-of-the-equation-x-2-x-2-0-simplify-A-p-p-p-and-calculate-p-0-n-1-A-p-and-p-0-n-1-A-p-2-

Question Number 73487 by abdomathmax last updated on 13/Nov/19 $${let}\:\:\:\:\alpha\:{and}\:\beta\:{roots}\:{of}\:\:{the}\:{equation}\:\:{x}^{\mathrm{2}} −{x}+\mathrm{2}=\mathrm{0} \\ $$$${simplify}\:\:\:{A}_{{p}} =\:\alpha^{{p}} \:+\beta^{{p}} \:{and}\:{calculate} \\ $$$$\sum_{{p}=\mathrm{0}} ^{{n}−\mathrm{1}} \:{A}_{{p}} \:\:{and}\:\sum_{{p}=\mathrm{0}} ^{{n}−\mathrm{1}} \:\:{A}_{{p}} ^{\mathrm{2}} \\…

find-Re-z-and-Im-z-of-z-2i-3-2-

Question Number 139023 by mohammad17 last updated on 21/Apr/21 $${find}\:{Re}\left({z}\right)\:{and}\:{Im}\left({z}\right)\:{of}\:{z}=\left(−\mathrm{2}{i}\right)^{−\frac{\mathrm{3}}{\mathrm{2}}} \\ $$ Answered by MJS_new last updated on 21/Apr/21 $$−\mathrm{2i}=\mathrm{2e}^{−\frac{\pi}{\mathrm{2}}\mathrm{i}} \\ $$$$\left(\mathrm{2e}^{−\frac{\pi}{\mathrm{2}}\mathrm{i}} \right)^{−\frac{\mathrm{3}}{\mathrm{2}}} =\mathrm{2}^{−\frac{\mathrm{3}}{\mathrm{2}}} \mathrm{e}^{\frac{\mathrm{3}\pi}{\mathrm{4}}\mathrm{i}}…

find-the-roots-of-P-x-1-ix-jx-2-n-1-with-j-e-i-2pi-3-then-factorize-P-x-inside-C-x-decompose-the-fraction-F-1-P-

Question Number 73485 by abdomathmax last updated on 13/Nov/19 $${find}\:{the}\:{roots}\:{of}\:{P}\left({x}\right)=\left(\mathrm{1}+{ix}\:+{jx}^{\mathrm{2}} \right)^{{n}} −\mathrm{1} \\ $$$${with}\:{j}\:={e}^{{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \:\:\:{then}\:{factorize}\:{P}\left({x}\right)\:{inside}\:{C}\left[{x}\right] \\ $$$${decompose}\:{the}\:{fraction}\:{F}=\frac{\mathrm{1}}{{P}} \\ $$ Terms of Service Privacy Policy Contact:…