Question Number 139002 by BHOOPENDRA last updated on 21/Apr/21 Commented by Dwaipayan Shikari last updated on 22/Apr/21 $${Probability}\:\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} \mid\Psi\left({x}\right)\mid^{\mathrm{2}} {dx}=\mathrm{1} \\ $$$$=\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} {A}^{\mathrm{2}}…
Question Number 138997 by bramlexs22 last updated on 21/Apr/21 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\sqrt[{\mathrm{3}}]{\mathrm{7}+\mathrm{x}^{\mathrm{3}} }−\sqrt{\mathrm{3}+\mathrm{x}^{\mathrm{2}} }}{\mathrm{x}−\mathrm{1}}=? \\ $$ Answered by EDWIN88 last updated on 21/Apr/21 $$\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\frac{\mathrm{x}^{\mathrm{2}} \left(\mathrm{7}+\mathrm{x}^{\mathrm{3}}…
Question Number 138996 by bramlexs22 last updated on 21/Apr/21 $$\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2}}−\sqrt{\mathrm{1}+\mathrm{sin}\:\mathrm{x}}}{\:\sqrt{\mathrm{2}}\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}}\:=? \\ $$$$ \\ $$ Answered by EDWIN88 last updated on 21/Apr/21 $$\:\underset{{x}\rightarrow\pi/\mathrm{2}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{sin}\:\mathrm{x}}{\:\sqrt{\mathrm{2}}\left(\mathrm{1}−\mathrm{sin}\:\mathrm{x}\right)}.\underset{{x}\rightarrow\pi/\mathrm{2}}…
Question Number 138999 by bramlexs22 last updated on 21/Apr/21 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions} \\ $$$$\mathrm{of}\:\mathrm{equations}\:\sqrt{\mathrm{13}−\mathrm{18tan}\:\mathrm{x}}\:=\:\mathrm{6tan}\:\mathrm{x}−\mathrm{3} \\ $$$$\mathrm{where}\:−\mathrm{2}\pi<\mathrm{x}<\mathrm{2}\pi\:\mathrm{is} \\ $$ Answered by EDWIN88 last updated on 21/Apr/21 $$\left(\mathrm{1}\right)\:\mathrm{13}−\mathrm{18tan}\:\mathrm{x}\geqslant\mathrm{0}\:;\:\mathrm{tan}\:\mathrm{x}\leqslant\frac{\mathrm{13}}{\mathrm{18}} \\…
Question Number 138998 by ZiYangLee last updated on 21/Apr/21 $$\int\:\left(\frac{{e}^{−\mathrm{1}/{x}} }{{x}^{\mathrm{2}} }\right)\:{dx}\:=? \\ $$ Answered by phanphuoc last updated on 21/Apr/21 $$=\int{e}^{\left(−\mathrm{1}/{x}\right)} {d}\left(−\mathrm{1}/{x}\right)={e}^{−\mathrm{1}/{x}} +{c} \\…
Question Number 138993 by bramlexs22 last updated on 21/Apr/21 $$\int\:\sqrt{\mathrm{x}+\sqrt{\mathrm{x}−\sqrt{\mathrm{x}+\sqrt{\mathrm{x}−\sqrt{\mathrm{x}+\sqrt{\mathrm{x}−\sqrt{\mathrm{x}+…}}}}}}}\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138994 by mathlove last updated on 21/Apr/21 Answered by qaz last updated on 21/Apr/21 $$\int\frac{{dx}}{{xln}\left({x}\right){ln}\left({lnx}\right)}=\int\frac{{d}\left({lnx}\right)}{{ln}\left({x}\right){ln}\left({lnx}\right)}=\int\frac{{d}\left({ln}\left({lnx}\right)\right)}{{ln}\left({lnx}\right)}={ln}\left({ln}\left({lnx}\right)\right)+{C} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 138989 by metamorfose last updated on 20/Apr/21 $${find}\:{the}\:{integers}\:{x}\:,\:{y}\:,\:{z}\:,\:{n}\:{that} \\ $$$${satisfy}\::\:\mathrm{2}^{{n}} ={x}!+{y}!+{z}! \\ $$ Answered by mindispower last updated on 21/Apr/21 $${let}\:{m}={min}\left({x},{y},{z}\right),{if}\:{m}\geqslant\mathrm{3}\Rightarrow \\ $$$${x}!+{y}!+{z}!\equiv\mathrm{0}\left[\mathrm{3}\right]\Leftrightarrow\mathrm{2}^{{n}}…
Question Number 138984 by bramlexs22 last updated on 20/Apr/21 $$\frac{\mathrm{36}}{\:\sqrt{\mathrm{x}−\mathrm{2}}}\:+\frac{\mathrm{4}}{\:\sqrt{\mathrm{y}−\mathrm{1}}}\:+\mathrm{4}\sqrt{\mathrm{x}−\mathrm{2}}\:+\sqrt{\mathrm{y}−\mathrm{1}}\:=\:\mathrm{28} \\ $$$$\mathrm{find}\:\mathrm{x}\:\&\:\mathrm{y} \\ $$ Answered by mitica last updated on 21/Apr/21 $$\frac{\mathrm{36}}{\:\sqrt{{x}−\mathrm{2}}}+\mathrm{4}\sqrt{{x}−\mathrm{2}}+\frac{\mathrm{4}}{\:\sqrt{{y}−\mathrm{1}}}+\sqrt{{y}−\mathrm{1}}\geqslant \\ $$$$\mathrm{2}\sqrt{\frac{\mathrm{36}}{\:\sqrt{{x}−\mathrm{2}}}\centerdot\mathrm{4}\sqrt{{x}−\mathrm{2}}}+\mathrm{2}\sqrt{\frac{\mathrm{4}}{\:\sqrt{{y}−\mathrm{1}}}\centerdot\sqrt{{y}−\mathrm{1}}}=\mathrm{24}+\mathrm{4}=\mathrm{28}\Rightarrow \\…
Question Number 73451 by Learner-123 last updated on 12/Nov/19 Commented by Learner-123 last updated on 12/Nov/19 $${Please}\:{tell}\:{whether}\:{the}\:{statement}\:{is} \\ $$$${true}\:{or}\:{false}\:.\left({all}\:\mathrm{10}\right). \\ $$ Commented by Learner-123 last…