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Question Number 7859 by tawakalitu last updated on 21/Sep/16 $${Find}\:{the}\:{remainder}\:{if}\:\:\:\mathrm{49}^{\mathrm{1296}} \:×\:\mathrm{7}^{\mathrm{131}} \:\:{is}\:{divided} \\ $$$${by}\:\:\mathrm{13}\:\: \\ $$ Answered by sandy_suhendra last updated on 21/Sep/16 $$\mathrm{49}^{\mathrm{1296}} \:×\:\mathrm{7}^{\mathrm{131}}…
Question Number 7858 by tawakalitu last updated on 21/Sep/16 $${Find}\:{the}\:{derivative}\:{of}\:\:\:\:{x}^{{sin}\mathrm{2}{x}} \:\:\:{from}\:{the}\: \\ $$$${first}\:{priniple}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 7855 by 314159 last updated on 21/Sep/16 Commented by 123456 last updated on 21/Sep/16 $${a}_{\mathrm{1}} ,{a}_{\mathrm{2}} ,{a}_{\mathrm{3}} \Rightarrow{a}_{\mathrm{3}} −{a}_{\mathrm{2}} ={a}_{\mathrm{2}} −{a}_{\mathrm{1}} ,{a}_{\mathrm{1}} \neq{a}_{\mathrm{2}}…
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Question Number 7847 by madscientist last updated on 20/Sep/16 $${is}\:{there}\:{a}\:{proof}\:{of}\:{a}\:{relationship}\:\: \\ $$$${between}\:\varphi,\pi,{e}\:{where}\:\pi=\mathrm{3}.\mathrm{14},\varphi=\mathrm{1}.\mathrm{618}\: \\ $$$${and}\:{e}=\mathrm{2}.\mathrm{718}\:{such}\:{that}\:\varepsilon\:{is}\:{some} \\ $$$${oporator},\varepsilon=−+×\boldsymbol{\div} \\ $$$$\varphi\varepsilon\pi\varepsilon{e}=\mathrm{0}\:{or}\:\pi\varepsilon{e}\varepsilon\varphi=\mathrm{0}\:{or}\:{e}\varepsilon\varphi\varepsilon\pi=\mathrm{0} \\ $$ Commented by FilupSmith last updated…
Question Number 138916 by mathsuji last updated on 20/Apr/21 $$\underset{\:\mathrm{1}} {\overset{\:\mathrm{4}} {\int}}\:\sqrt{\frac{\sqrt{{z}}−\mathrm{1}}{\:\sqrt{{z}}}}\:{dz}\:=? \\ $$ Answered by bramlexs22 last updated on 20/Apr/21 $$\sqrt{\frac{\sqrt{\mathrm{z}}−\mathrm{1}}{\:\sqrt{\mathrm{z}}}}\:=\:\mathrm{r}\:;\:\frac{\sqrt{\mathrm{z}}\:−\mathrm{1}}{\:\sqrt{\mathrm{z}}}\:=\:\mathrm{r}^{\mathrm{2}} \rightarrow\begin{cases}{\mathrm{z}=\mathrm{1}\rightarrow\mathrm{r}=\mathrm{0}}\\{\mathrm{z}=\mathrm{4}\rightarrow\mathrm{r}=\sqrt{\frac{\mathrm{1}}{\mathrm{2}}}}\end{cases} \\ $$$$\Rightarrow\mathrm{r}^{\mathrm{2}}…
Question Number 7846 by Tinku Tara last updated on 20/Sep/16 $$\mathrm{There}\:\mathrm{is}\:\mathrm{new}\:\mathrm{update}\:\mathrm{available}. \\ $$$$\mathrm{The}\:\mathrm{following}\:\mathrm{enhacements}\:\mathrm{are}\:\mathrm{made}\:\mathrm{in} \\ $$$$\mathrm{this}\:\mathrm{update} \\ $$$$\bullet\:\mathrm{You}\:\mathrm{can}\:\mathrm{now}\:\mathrm{zoom}\:\mathrm{on}\:\mathrm{images}\:\mathrm{posted}\:\mathrm{on} \\ $$$$\:\:\:\:\mathrm{the}\:\mathrm{forum}. \\ $$$$\bullet\:\mathrm{Preview}\:\mathrm{of}\:\mathrm{the}\:\mathrm{image}\:\mathrm{is}\:\mathrm{available}\:\mathrm{while} \\ $$$$\:\:\:\:\mathrm{answering}\:\mathrm{or}\:\mathrm{commenting}.\:\mathrm{You}\:\mathrm{can} \\ $$$$\:\:\:\:\mathrm{zoom}\:\mathrm{within}\:\mathrm{the}\:\mathrm{preview}\:\mathrm{as}\:\mathrm{well}.…
Question Number 73378 by mind is power last updated on 10/Nov/19 $${Hello}\:,{i}\:{shar}\:{withe}\:{you}\:{nice}\:{problem}\: \\ $$$${show}\:{that}\:\forall{k}\in\mathbb{N}^{\ast} \:\exists{n}\in\mathbb{N}\:{such}\:{that} \\ $$$${k}\leqslant\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{j}}<{k}+\mathrm{1} \\ $$$${have}\:{a}\:{very}\:{Nice}\:{day} \\ $$$$ \\ $$…