Question Number 138799 by TheSupreme last updated on 18/Apr/21 $$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{ln}\left(\mathrm{tan}\left(\mathrm{x}\right)−\alpha\right){dx}=… \\ $$$$\alpha\in\mathbb{C} \\ $$ Answered by mathmax by abdo last updated on 19/Apr/21…
Question Number 73260 by Lontum Hans last updated on 09/Nov/19 Answered by mr W last updated on 09/Nov/19 $${T}_{{max}} ={m}\left(\frac{{v}^{\mathrm{2}} }{{r}}+{g}\right)=\mathrm{8}\left(\frac{\mathrm{6}^{\mathrm{2}} }{\mathrm{2}}+\mathrm{10}\right)=\mathrm{224}\:{N} \\ $$$${T}_{{min}} ={m}\left(\frac{{v}^{\mathrm{2}}…
Question Number 73261 by mathmax by abdo last updated on 09/Nov/19 $${calculate}\:\sum_{{n}=\mathrm{1}} ^{\infty} \left({n}^{\mathrm{4}} +\mathrm{2}{n}^{\mathrm{2}} −\mathrm{3}\right)\frac{{x}^{{n}} }{{n}!}\:{in}\:{case}\:{of}\:{convergence}. \\ $$ Commented by mathmax by abdo last…
Question Number 73258 by Lontum Hans last updated on 09/Nov/19 Answered by MJS last updated on 09/Nov/19 $$\mathrm{well},\:\mathrm{just}\:\mathrm{do}\:\mathrm{it} \\ $$$${u}=\mathrm{1}+\mathrm{cosh}\:{x}\:\rightarrow\:{dx}=\frac{{du}}{\mathrm{sinh}\:{x}} \\ $$$$…=\underset{\mathrm{2}} {\overset{\mathrm{3}} {\int}}\frac{{du}}{{u}\left({u}−\mathrm{1}\right)}=\left[\mathrm{ln}\:\frac{{u}−\mathrm{1}}{{u}}\right]_{\mathrm{2}} ^{\mathrm{3}}…
Question Number 7723 by FilupSmith last updated on 12/Sep/16 $${p}_{{n}} ={n}\mathrm{th}\:\mathrm{prime}\:\:\left({p}_{\mathrm{1}} =\mathrm{2},\:\:{p}_{\mathrm{2}} =\mathrm{3},\:\:\:{p}_{\mathrm{3}} =\mathrm{5},\:…\right) \\ $$$$\mathrm{Do}\:\mathrm{the}\:\mathrm{following}\:\mathrm{sums}\:\mathrm{converge}?\:\mathrm{Prove}/\mathrm{disprove}. \\ $$$$\left(\mathrm{1}\right)\:\:\:\:\:\:\:\:{S}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{n}}{{p}_{{n}} } \\ $$$$\left(\mathrm{2}\right)\:\:\:\:\:\:\:\:{S}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{n}}{{p}_{{n}}…
Question Number 138789 by 676597498 last updated on 18/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73255 by TawaTawa last updated on 09/Nov/19 Answered by mr W last updated on 09/Nov/19 $${there}\:{is}\:{no}\:{support}\:{on}\:{the}\:{right}\:{end} \\ $$$${of}\:{the}\:{beam}! \\ $$$$ \\ $$$$\mathrm{0}.\mathrm{4}{L}×{R}_{{Mid}} −\mathrm{0}.\mathrm{2}{L}×\mathrm{0}.\mathrm{6}{W}−\mathrm{0}.\mathrm{8}{L}×\mathrm{0}.\mathrm{15}{W}=\mathrm{0}…
Question Number 73251 by aliesam last updated on 09/Nov/19 Answered by mind is power last updated on 09/Nov/19 $$\mathrm{E}\left(\mathrm{u}_{\mathrm{n}} \right)\leqslant\mathrm{u}_{\mathrm{n}} <\mathrm{E}\left(\mathrm{u}_{\mathrm{n}} \right)+\mathrm{1}=\mathrm{U}_{\mathrm{n}+\mathrm{1}} \\ $$$$\Rightarrow\mathrm{U}_{\mathrm{n}} \mathrm{is}\:\mathrm{a}\:\mathrm{creasing}\:\mathrm{squances}…
2x-y-z-8-equation-i-x-2-y-2-2z-2-14-equation-ii-3x-3-4y-3-z-3-195-equation-iii-Solve-simultaneously-
Question Number 7713 by Tawakalitu. last updated on 11/Sep/16 $$\mathrm{2}{x}\:+\:{y}−\:{z}\:=\:\mathrm{8}\:\:\:\:……….\:{equation}\:\left({i}\right) \\ $$$${x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:+\:\mathrm{2}{z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:……….\:{equation}\:\left({ii}\right) \\ $$$$\mathrm{3}{x}^{\mathrm{3}} \:+\:\mathrm{4}{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:\:\:………\:{equation}\:\left({iii}\right) \\ $$$$ \\ $$$${Solve}\:{simultaneously}. \\…
Question Number 73247 by Lontum Hans last updated on 09/Nov/19 Answered by Kunal12588 last updated on 09/Nov/19 $${a}_{\mathrm{8}} −{a}_{\mathrm{4}} =\mathrm{40}\:\:\:….\left(\mathrm{1}\right) \\ $$$${a}_{\mathrm{8}} =\frac{\mathrm{3}}{\mathrm{2}}{a}_{\mathrm{4}} \:\:\:\:\:\:\:…..\left(\mathrm{2}\right) \\…