Question Number 138783 by mathdanisur last updated on 18/Apr/21 $${Solve}\:{for}\:{real}\:{numbees}: \\ $$$$\begin{cases}{{a}^{\mathrm{16}} +\mathrm{1}=\frac{{a}+{b}}{\mathrm{2}}}\\{{b}^{\mathrm{16}} +\mathrm{1}=\frac{{b}+{c}}{\mathrm{2}}}\\{{c}^{\mathrm{16}} +\mathrm{1}=\frac{{c}+{x}}{\mathrm{2}}}\end{cases} \\ $$ Commented by mr W last updated on 18/Apr/21…
Question Number 7708 by kamylla last updated on 10/Sep/16 $$\mathrm{5}×\mathrm{2} \\ $$ Commented by Rohit 57 last updated on 13/Sep/16 $${answer}\:{is}\:\mathrm{5}×\mathrm{2}=\mathrm{10}\: \\ $$ Terms of…
Question Number 73243 by mathmax by abdo last updated on 09/Nov/19 $${prove}\:{that}\:\:{for}\:{z}\:\in{C}\:\:\:{arctanz}\:=\frac{\mathrm{1}}{\mathrm{2}{i}}{ln}\left(\frac{\mathrm{1}+{iz}}{\mathrm{1}−{iz}}\right) \\ $$$$ \\ $$ Answered by mr W last updated on 09/Nov/19 $${let}\:\mathrm{tan}^{−\mathrm{1}}…
Question Number 7706 by Rohit 57 last updated on 10/Sep/16 $${what}\:{is}\:{spectrum}.\left({chemistry}\:{subject}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 7704 by Tawakalitu. last updated on 10/Sep/16 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 73238 by mathmax by abdo last updated on 08/Nov/19 $${let}\:\mathrm{0}<{a}<\mathrm{1}\:{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}\left({t}\right){t}^{{a}−\mathrm{1}} }{\mathrm{1}+{t}}{dt}\:\:{and}\:\int_{\mathrm{0}} ^{\infty} \:\frac{{ln}^{\mathrm{2}} \left({t}\right){t}^{{a}−\mathrm{1}} }{\mathrm{1}+{t}}{dt} \\ $$ Commented by mathmax by…
Question Number 7702 by Rasheed Soomro last updated on 10/Sep/16 Commented by Rasheed Soomro last updated on 11/Sep/16 $${Given} \\ $$$${AB}={BD}={DF} \\ $$$$\angle{FGH}=\alpha \\ $$$${GF}={r}…
Question Number 7701 by z last updated on 10/Sep/16 $$\left({x}−\mathrm{2}{y}\right. \\ $$$$ \\ $$ Commented by Rohit 57 last updated on 11/Sep/16 $${what}\:{mean}\:{this}\:{qvestion}\:{plzzz}\: \\ $$…
Question Number 138774 by Bekzod Jumayev last updated on 18/Apr/21 Commented by Bekzod Jumayev last updated on 18/Apr/21 $$\:\:\:\:\:\:\boldsymbol{{x}}=?? \\ $$$$\boldsymbol{{Please}}\:\boldsymbol{{help}} \\ $$ Answered by…
Question Number 73235 by TawaTawa last updated on 08/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com