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Author: Tinku Tara

A-committee-of-3-members-is-to-be-formed-from-8-members-Find-the-number-of-committees-that-can-be-formed-if-two-particular-club-members-cannot-both-be-in-a-committee-

Question Number 138748 by physicstutes last updated on 17/Apr/21 $$\mathrm{A}\:\mathrm{committee}\:\mathrm{of}\:\mathrm{3}\:\mathrm{members}\:\mathrm{is}\:\mathrm{to}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{from}\:\mathrm{8}\:\mathrm{members}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{committees}\:\mathrm{that}\:\mathrm{can}\:\mathrm{be}\:\mathrm{formed}\:\mathrm{if}\:\mathrm{two}\:\mathrm{particular} \\ $$$$\mathrm{club}\:\mathrm{members}\:\mathrm{cannot}\:\mathrm{both}\:\mathrm{be}\:\mathrm{in}\:\mathrm{a}\:\mathrm{committee} \\ $$ Answered by mr W last updated on 17/Apr/21 $${C}_{\mathrm{3}}…

nice-calculus-evaluate-0-1-x-e-pi-1-x-e-1-ln-x-1-3-dx-3-pi-

Question Number 138742 by mnjuly1970 last updated on 17/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:……..\:{nice}\:\:\:….\:\:\:{calculus}… \\ $$$$\:\:{evaluate}\::: \\ $$$$\:\:\:\:\:\:\:\:\Omega=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{x}^{{e}^{\pi} −\mathrm{1}} −{x}^{{e}^{\gamma} −\mathrm{1}} }{{ln}\left(\sqrt[{\mathrm{3}}]{{x}}\:\right)}{dx}\overset{?} {=}\mathrm{3}\left(\pi−\gamma\right) \\ $$ Answered by…

Question-7668

Question Number 7668 by 314159 last updated on 08/Sep/16 Commented by Yozzia last updated on 08/Sep/16 $${Suppose}\:{a}+{b}={c},\:{with}\:{a},{b},{c}>\mathrm{0}. \\ $$$${Let}\:{n}=\frac{{a}}{\mathrm{1}+{a}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{c}}{\mathrm{1}+{c}}. \\ $$$${n}=\frac{{a}}{\mathrm{1}+{a}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{a}+{b}}{\mathrm{1}+{a}+{b}} \\ $$$${n}=\frac{{a}}{\mathrm{1}+{a}}−\frac{{a}}{\mathrm{1}+{a}+{b}}+\frac{{b}}{\mathrm{1}+{b}}−\frac{{b}}{\mathrm{1}+{a}+{b}} \\ $$$${n}={a}\left(\frac{\mathrm{1}}{\mathrm{1}+{a}}−\frac{\mathrm{1}}{\mathrm{1}+{a}+{b}}\right)+{b}\left(\frac{\mathrm{1}}{\mathrm{1}+{b}}−\frac{\mathrm{1}}{\mathrm{1}+{a}+{b}}\right)…

2x-2-1-2x-x-2-1-x-2-x-x-1-x-2-1-dx-dx-x-x-1-1-x-3-

Question Number 73202 by MJS last updated on 08/Nov/19 $$\int\frac{\mathrm{2}{x}^{\mathrm{2}} −\mathrm{1}+\mathrm{2}{x}\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}{{x}^{\mathrm{2}} −{x}+\left({x}−\mathrm{1}\right)\sqrt{{x}^{\mathrm{2}} −\mathrm{1}}}{dx}=? \\ $$$$\int\frac{{dx}}{{x}\sqrt{{x}+\mathrm{1}}\sqrt{\left(\mathrm{1}−{x}\right)^{\mathrm{3}} }}=? \\ $$ Commented by mathmax by abdo last…

lim-x-x-x-2-log-1-1-x-

Question Number 7667 by upendrakishor99@gmail.com last updated on 08/Sep/16 $$\underset{{x}\rightarrow\alpha} {\mathrm{lim}}\left[{x}−{x}^{\mathrm{2}} \mathrm{log}\:\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)\right] \\ $$ Answered by FilupSmith last updated on 08/Sep/16 $$=\alpha−\alpha^{\mathrm{2}} \mathrm{log}\left(\mathrm{1}+\frac{\mathrm{1}}{\alpha}\right) \\ $$…

Question-73203

Question Number 73203 by Tanmay chaudhury last updated on 08/Nov/19 Commented by kaivan.ahmadi last updated on 08/Nov/19 $${xsin}\frac{\mathrm{1}}{{x}}=\mathrm{1}\Rightarrow{sin}\frac{\mathrm{1}}{{x}}=\frac{\mathrm{1}}{{x}}\Rightarrow\frac{\mathrm{1}}{{x}}=\mathrm{0}\Rightarrow{there}\:{is}\:{no}\:{root} \\ $$$${so}\:{A}\:{has}\:{exactly}\:{one}\:{element},\:{A}=\left\{\mathrm{0}\right\} \\ $$ Terms of Service…

d-dx-x-2-4-

Question Number 7665 by upendrakishor99@gmail.com last updated on 08/Sep/16 $$\frac{{d}}{{dx}}\sqrt{{x}^{\mathrm{2}} −\mathrm{4}} \\ $$ Answered by Rasheed Soomro last updated on 08/Sep/16 $$\frac{{d}}{{dx}}\left({x}^{\mathrm{2}} −\mathrm{4}\right)^{\mathrm{1}/\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}\left({x}^{\mathrm{2}} −\mathrm{4}\right)^{\left(\mathrm{1}/\mathrm{2}\right)−\mathrm{1}}…