Question Number 193439 by Nimnim111118 last updated on 14/Jun/23 $$\underset{\:\:\mathrm{0}} {\int}^{\pi/\mathrm{2}} \frac{\sqrt[{\mathrm{3}}]{{tanx}}}{\left({sinx}+{cosx}\right)^{\mathrm{2}} }{dx} \\ $$ Commented by Nimnim111118 last updated on 14/Jun/23 $${help}… \\ $$…
Question Number 193438 by Mingma last updated on 14/Jun/23 Answered by qaz last updated on 14/Jun/23 $${log}_{\mathrm{3}} \left(\mathrm{9}{x}−\mathrm{3}\right)=\mathrm{1}+{log}_{\mathrm{3}} \left(\mathrm{3}{x}−\mathrm{1}\right)\:\:\:\:\:,{log}_{\mathrm{3}} \left({x}−\frac{\mathrm{1}}{\mathrm{3}}\right)={log}_{\mathrm{3}} \left(\mathrm{3}{x}−\mathrm{1}\right)−\mathrm{1} \\ $$$${log}_{\mathrm{3}} \left(\mathrm{3}{x}−\mathrm{1}\right)={y} \\…
Question Number 193435 by Mingma last updated on 14/Jun/23 Commented by maths_plus last updated on 14/Jun/23 $$\mathrm{i}\:\mathrm{want}\:\mathrm{to}\:\mathrm{known}\:… \\ $$ Answered by qaz last updated on…
Question Number 193426 by 073 last updated on 13/Jun/23 $$\int\sqrt[{\mathrm{3}}]{\mathrm{x}^{\mathrm{3}} +\mathrm{1}}\mathrm{dx}=? \\ $$$$\mathrm{solution}? \\ $$ Answered by witcher3 last updated on 15/Jun/23 $$\mathrm{x}^{\mathrm{3}} =\mathrm{t} \\…
Question Number 193423 by mustafazaheen last updated on 13/Jun/23 $$\mathrm{when}\:\:\:\mathrm{tan}\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{a}} \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{cos}\theta=?\:\mathrm{from}\:\mathrm{the}\:\mathrm{a} \\ $$ Answered by AST last updated on 13/Jun/23 $${tan}\left(\frac{\theta}{\mathrm{2}}+\frac{\theta}{\mathrm{2}}\right)=\frac{\mathrm{2}{tan}\left(\frac{\theta}{\mathrm{2}}\right)}{\mathrm{1}−{tan}^{\mathrm{2}} \left(\frac{\theta}{\mathrm{2}}\right)}\Rightarrow{tan}\left(\theta\right)=\frac{\mathrm{2}{a}}{{a}^{\mathrm{2}} −\mathrm{1}} \\…
Question Number 193414 by mokys last updated on 13/Jun/23 Answered by AST last updated on 13/Jun/23 $${Z}\:{and}\:{Z}_{\mathrm{2}} \:{in}\:{the}\:{closed}\:{unit}\:{disk}\Rightarrow\mid{Z}\mid,\mid{Z}_{\mathrm{2}} \mid\leqslant\mathrm{1} \\ $$$$\mid{Z}_{\mathrm{1}} −{Z}_{\mathrm{2}} \mid\geqslant\mathrm{1}\Rightarrow\left({Z}_{\mathrm{1}} −{Z}_{\mathrm{2}} \right)\left(\overset{−}…
Question Number 193409 by cortano12 last updated on 13/Jun/23 $$\:\:\:\Subset \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193408 by cortano12 last updated on 13/Jun/23 $$\:\underline{\underbrace{ }} \\ $$ Answered by MM42 last updated on 13/Jun/23 $${lim}_{{n}\rightarrow\infty} \:\frac{\mathrm{1}}{{n}}×\left(\frac{\mathrm{1}−\left({e}^{\frac{{a}}{{n}}} \right)^{{n}} ×\frac{\mathrm{1}}{{e}^{\frac{{a}}{{n}}} }}{\mathrm{1}−{e}^{\frac{{a}}{{n}}}…
Question Number 193411 by cortano12 last updated on 13/Jun/23 $$\:\:\:\:\: \\ $$$$ \\ $$ Commented by BaliramKumar last updated on 13/Jun/23 $$\mathrm{put}\:\:\:{x}\:=\:{cos}\mathrm{2}\theta \\ $$ Answered…
Question Number 193410 by cortano12 last updated on 13/Jun/23 $$\:\:\begin{cases}{\mathrm{x}=\sqrt{\mathrm{3}−\sqrt{\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}}}}\\{\mathrm{y}=\sqrt{\mathrm{3}+\sqrt{\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}}}}\end{cases}\: \\ $$$$\:\:\:\:\underbrace{\boldsymbol{{x}}} \\ $$ Answered by aba last updated on 13/Jun/23 $$\mathrm{xy}=\sqrt{\mathrm{9}−\left(\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}\right)}=\sqrt{\mathrm{4}−\mathrm{2}\sqrt{\mathrm{3}}}=\sqrt{\mathrm{3}}−\mathrm{1}\:\wedge\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\mathrm{6} \\…