Question Number 138627 by KwesiDerek last updated on 15/Apr/21 $$\boldsymbol{\mathrm{x}}^{\mathrm{2}} =\mathrm{16}^{\boldsymbol{\mathrm{x}}} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{x}} \\ $$ Commented by soudo last updated on 15/Apr/21 $$\mathrm{nice} \\ $$…
Question Number 7552 by Master Moon last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}+\mathrm{5}\:= \\ $$ Answered by FilupSmith last updated on 03/Sep/16 $$\sqrt{\mathrm{4}}=\pm\mathrm{2} \\ $$$$\therefore\sqrt{\mathrm{4}}+\mathrm{5}=\mathrm{5}\pm\mathrm{2}=\mathrm{3},\:\mathrm{7} \\ $$…
Question Number 138621 by mnjuly1970 last updated on 15/Apr/21 Answered by Dwaipayan Shikari last updated on 15/Apr/21 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\Gamma^{\mathrm{2}} \left({n}+\mathrm{1}\right)}{\Gamma\left(\mathrm{2}{n}+\mathrm{2}\right)}=\int_{\mathrm{0}} ^{\mathrm{1}} \Sigma{x}^{{n}} \left(\mathrm{1}−{x}\right)^{{n}} {dx}…
Question Number 73084 by rajesh4661kumar@gmail.com last updated on 06/Nov/19 Answered by Tanmay chaudhury last updated on 06/Nov/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138619 by Dwaipayan Shikari last updated on 15/Apr/21 $$\int_{\mathrm{0}} ^{\infty} \left({e}^{−{x}^{\sqrt{\mathrm{3}}} } −\frac{\mathrm{1}}{\left(\mathrm{1}+{x}^{\sqrt{\mathrm{3}}} \right)^{\sqrt{\mathrm{3}}} }\right)\frac{{dx}}{{x}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\psi\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\right) \\ $$ Commented by mnjuly1970 last updated on…
Question Number 73080 by oyemi kemewari last updated on 06/Nov/19 $$\mathrm{y}''=\mathrm{e}^{\mathrm{y}} \\ $$$$\mathrm{pls}\:\mathrm{solve} \\ $$ Answered by mind is power last updated on 06/Nov/19 $$\mathrm{y}''.\mathrm{y}'=\mathrm{y}'\mathrm{e}^{\mathrm{y}}…
Question Number 7545 by Tawakalitu. last updated on 03/Sep/16 $${y}^{\mathrm{2}} \:+\:{x}^{\mathrm{2}} \:=\:\mathrm{2}^{{x}} \:+\:\mathrm{2}^{{y}} \\ $$$${Find}\:{the}\:{possible}\:{greatest}\:{value}\:{of}\:\mid{x}\:−\:{y}\mid \\ $$ Commented by Yozzia last updated on 03/Sep/16 $$\mathrm{2}^{{x}−{y}}…
Question Number 7544 by Tawakalitu. last updated on 03/Sep/16 Commented by sou1618 last updated on 03/Sep/16 $${x}={OA} \\ $$$${OB}=\sqrt{{x}^{\mathrm{2}} +\mathrm{144}} \\ $$$$\Delta{ABO}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{12}{x} \\ $$$$\Delta{AOB}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{3}\left(\mathrm{12}+{x}+\sqrt{{x}^{\mathrm{2}} +\mathrm{144}}\right)…
Question Number 138613 by byaw last updated on 15/Apr/21 Answered by physicstutes last updated on 15/Apr/21 $$\mathrm{This}\:\mathrm{question}\:\mathrm{is}\:\mathrm{real}\:\mathrm{lol}! \\ $$$$\mathrm{2}.\:\left(\mathrm{a}\right)\:\mathrm{Total}\:\mathrm{length}\:=\:\frac{\mathrm{9}}{\mathrm{4}}\:\mathrm{m}\: \\ $$$$\Rightarrow\:\mathrm{lenght}\:\mathrm{used}\:\mathrm{for}\:\mathrm{a}\:\mathrm{job}\:=\:\frac{\mathrm{2}}{\mathrm{3}}×\frac{\mathrm{9}}{\mathrm{4}}\:=\:\frac{\mathrm{3}}{\mathrm{2}}\:\mathrm{m} \\ $$$$\mathrm{length}\:\mathrm{used}\:=\:\frac{\mathrm{9}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{2}}\:=\:\frac{\mathrm{3}}{\mathrm{4}}\mathrm{m} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{lenght}\:\mathrm{used}\:\mathrm{for}\:\mathrm{job}\:=\:\frac{\mathrm{1}}{\mathrm{8}}×\frac{\mathrm{3}}{\mathrm{4}}\:=\:\frac{\mathrm{3}}{\mathrm{32}}…
Question Number 138612 by SOMEDAVONG last updated on 15/Apr/21 $$\mathrm{If}\:\mathrm{z}+\:\frac{\mathrm{1}}{\mathrm{z}}\:=\mathrm{2cos}\beta\:.\mathrm{show}\:\mathrm{that}\:\mathrm{z}^{\mathrm{m}} +\frac{\mathrm{1}}{\mathrm{z}^{\mathrm{m}} }\:=\mathrm{2cosm}\beta. \\ $$ Answered by Ar Brandon last updated on 15/Apr/21 $$\mathrm{z}=\mathrm{e}^{\mathrm{i}\beta} \\ $$$$\mathrm{z}^{\mathrm{m}}…