Question Number 7422 by Tawakalitu. last updated on 28/Aug/16 $$\int\frac{{x}^{\mathrm{2}} \:{dx}}{\left({x}\:−\:\mathrm{1}\right)\left({x}^{\mathrm{2}} \:+\:\mathrm{4}\right)^{\mathrm{2}} } \\ $$ Answered by Yozzia last updated on 28/Aug/16 $$\frac{{x}^{\mathrm{2}} }{\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} +\mathrm{4}\right)^{\mathrm{2}}…
Question Number 138495 by yutytfjh67ihd last updated on 14/Apr/21 Commented by yutytfjh67ihd last updated on 14/Apr/21 $$\mathrm{Some}\:\mathrm{missing}\:\mathrm{unsolved}\:\mathrm{probelm}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 72952 by ajfour last updated on 05/Nov/19 Commented by ajfour last updated on 05/Nov/19 $${AB}\:{divides}\:{the}\:{composite}\:{figure} \\ $$$${of}\:{square}\:{mounted}\:{by}\:{a}\:{semicircle} \\ $$$${in}\:{two}\:{equal}\:{parts}.\:{Determine}\:\alpha. \\ $$ Commented by…
Question Number 138485 by SLVR last updated on 14/Apr/21 Commented by SLVR last updated on 14/Apr/21 $${Good}\:{morning}\:{mr}.{W}\:{thanks}\:{for} \\ $$$${your}\:{support}\:.{The}\:{above}\:{is}\:{also}\:{i} \\ $$$${missed}\:{long}\:{ago}..{and}\:{i}\:{couldnot} \\ $$$${retrive}\:{from}\:{the}\:{group}.{kindly}\:{help} \\ $$…
Question Number 138484 by cherokeesay last updated on 14/Apr/21 Commented by mr W last updated on 14/Apr/21 $${why}\:{not}\:{directly}\:\frac{\mathrm{6}×\mathrm{6}}{\mathrm{4}}=\mathrm{9}? \\ $$ Commented by cherokeesay last updated…
Question Number 7413 by Tawakalitu. last updated on 28/Aug/16 Answered by sandy_suhendra last updated on 28/Aug/16 $$\left.\mathrm{9}\right)\:{the}\:{curve}\:{through}\:{the}\:{point}\:\left(−\mathrm{1},\mathrm{0}\right),\:\left(\mathrm{3},\mathrm{0}\right)\:{and}\:\left(−\mathrm{2},−\mathrm{10}\right) \\ $$$$\:\:\:\:\:{f}\left({x}\right)={a}\left({x}−{x}_{\mathrm{1}} \right)\left({x}−{x}_{\mathrm{2}} \right)\:{which}\:{x}_{\mathrm{1}} =−\mathrm{1}\:{and}\:{x}_{\mathrm{2}} =\mathrm{3} \\ $$$$\:\:\:\:\:\:−\mathrm{10}={a}\left(−\mathrm{2}+\mathrm{1}\right)\left(−\mathrm{2}−\mathrm{3}\right)…
Question Number 138477 by mathlove last updated on 14/Apr/21 Answered by Ñï= last updated on 14/Apr/21 $${a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} −{d}^{\mathrm{2}} −\mathrm{2}{cd}−{c}^{\mathrm{2}} \\ $$$$=\left({a}+{b}\right)^{\mathrm{2}} −\left({c}+{d}\right)^{\mathrm{2}} \\ $$$$=\left({a}+{b}+{c}+{d}\right)\left({a}+{b}−{c}−{d}\right)…
Question Number 7407 by Tawakalitu. last updated on 27/Aug/16 Commented by sou1618 last updated on 27/Aug/16 $${another}\:{solution} \\ $$$$\mathrm{999}^{\mathrm{2}} <\mathrm{1024}^{\mathrm{2}} =\mathrm{2}^{\mathrm{10}×\mathrm{2}} =\mathrm{2}^{\mathrm{20}} \\ $$$${so}\:\mathrm{999}^{\mathrm{2}} <\mathrm{2}^{\mathrm{20}}…
Question Number 138473 by henderson last updated on 14/Apr/21 $$\boldsymbol{\mathrm{hi}}\:! \\ $$$$\boldsymbol{\mathrm{calculate}}\::\:\underset{{x}\rightarrow\infty} {{lim}}\:\left[\frac{{ln}\left({x}+\mathrm{1}\right)}{{ln}\:\left({x}\right)}\right]^{{x}\:{ln}\:\left({x}\right)} . \\ $$ Answered by mathmax by abdo last updated on 14/Apr/21…
Question Number 7401 by txsnims last updated on 27/Aug/16 $${find}\:{the}\:{turning}\:{point}\:{on}\:{the}\:{curve}\:{y}=\frac{\mathrm{16}}{{x}}+\frac{{x}^{\mathrm{3}} }{\mathrm{3}\:}\:\:{and}\:{determine}\:{wether}\:{it}\:{is}\:{a}\:{point}\:{of}\:{maximum}\:{or}\:{minimum} \\ $$$$ \\ $$ Answered by FilupSmith last updated on 27/Aug/16 $${y}=\mathrm{16}{x}^{−\mathrm{1}} +\mathrm{3}^{−\mathrm{1}} {x}^{\mathrm{3}}…