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Author: Tinku Tara

Show-that-2-x-1-5-x-3-5-x-dx-1-ln-1-5-ln2-ln-1-5-1-2-x-5-1-2-x-C-

Question Number 7184 by Yozzia last updated on 15/Aug/16 $${Show}\:{that} \\ $$$$\int\frac{\mathrm{2}^{{x}} }{\left(\mathrm{1}+\sqrt{\mathrm{5}}\right)^{{x}} +\left(\mathrm{3}+\sqrt{\mathrm{5}}\right)^{{x}} }{dx}=\frac{\mathrm{1}}{{ln}\left(\mathrm{1}+\sqrt{\mathrm{5}}\right)−{ln}\mathrm{2}}\left({ln}\left[\mathrm{1}+\left(\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\right)^{{x}} \right]−\left(\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\right)^{{x}} \right)+{C} \\ $$$$ \\ $$ Terms of Service Privacy…

Question-7178

Question Number 7178 by aftab ahmad last updated on 14/Aug/16 Commented by aftab ahmad last updated on 14/Aug/16 $$\boldsymbol{{Very}}\:\boldsymbol{{nice}}\:\boldsymbol{{approach}}\:\boldsymbol{{sir}}..\boldsymbol{{T}}{h}\boldsymbol{{anks}}\:\boldsymbol{{a}}\:\boldsymbol{{lot}}. \\ $$ Commented by Yozzia last…

x-2-10x-6-x-2-gt-1-

Question Number 138250 by sahnaz last updated on 11/Apr/21 $$\left(\mathrm{x}^{\mathrm{2}} −\mathrm{10x}+\mathrm{6}\right)^{\mathrm{x}−\mathrm{2}} >\mathrm{1} \\ $$ Answered by bobhans last updated on 11/Apr/21 $$\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{{x}−\mathrm{2}} \:>\:\left({x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{6}\right)^{\mathrm{0}}…

x-1-dy-dx-xy-2xe-x-

Question Number 138240 by bobhans last updated on 11/Apr/21 $$\:\left({x}−\mathrm{1}\right)\frac{{dy}}{{dx}}\:+{xy}\:=\:\mathrm{2}{xe}^{−{x}} \\ $$ Answered by EDWIN88 last updated on 11/Apr/21 $$\:\frac{{dy}}{{dx}}\:+\:\frac{{x}}{{x}−\mathrm{1}}\:{y}\:=\:\frac{\mathrm{2}{x}}{{e}^{{x}} \left({x}−\mathrm{1}\right)} \\ $$$${put}\:{IF}\:=\:{e}^{\int\:\frac{{x}}{{x}−\mathrm{1}}\:{dx}} \:=\:{e}^{\int\:\frac{{x}−\mathrm{1}+\mathrm{1}}{{x}−\mathrm{1}}\:{dx}} ={e}^{{x}+\mathrm{ln}\:\left({x}−\mathrm{1}\right)}…

I-have-five-envelopes-numbered-3-4-5-6-7-all-hidden-in-a-box-i-picked-an-envelope-If-its-prime-then-i-get-the-square-of-that-number-in-Naira-Otherwise-without-replacement-i-picked-another-env

Question Number 7168 by Tawakalitu. last updated on 14/Aug/16 $${I}\:{have}\:{five}\:{envelopes}\:{numbered}\:\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7}\:{all}\:{hidden}\:{in}\:{a} \\ $$$${box},\:{i}\:{picked}\:{an}\:{envelope}\:.\:\:{If}\:{its}\:{prime}\:{then}\:{i}\:{get}\:{the}\: \\ $$$${square}\:{of}\:{that}\:{number}\:{in}\:{Naira}.\:{Otherwise}\:\left({without}\:\right. \\ $$$$\left.{replacement}\right)\:{i}\:{picked}\:{another}\:{envelope}\:{and}\:{then}\:{get}\:{the} \\ $$$${sum}\:{of}\:{the}\:{squares}\:{of}\:{the}\:{two}\:{numbers}\:{picked}\:\left({in}\:{Naira}\right) \\ $$$${what}\:{is}\:{the}\:{chance}\:{of}\:{me}\:{getting}\:\:{N}\mathrm{25}\:\:? \\ $$$$ \\ $$ Commented…