Question Number 138206 by Bekzod Jumayev last updated on 11/Apr/21 Commented by Bekzod Jumayev last updated on 11/Apr/21 $${Help}? \\ $$ Answered by mr W…
Question Number 72666 by aliesam last updated on 31/Oct/19 Answered by mind is power last updated on 31/Oct/19 $$\mathrm{let}\:\alpha=\angle\mathrm{CDA}=\mathrm{BAE}\:\:,\mathrm{OCA}=\mathrm{2}\alpha \\ $$$$\mathrm{E}=\left(\mathrm{AD}\right)\cap\mathrm{BC} \\ $$$$\frac{\mathrm{3}}{\mathrm{5}}=\frac{\mathrm{BE}}{\mathrm{EC}},\mathrm{BE}+\mathrm{EC}=\mathrm{4} \\ $$$$\Rightarrow\mathrm{BE}=\frac{\mathrm{3}}{\mathrm{2}}…
Question Number 138203 by liberty last updated on 11/Apr/21 $${Three}\:{circles}\:{each}\:{radius}\:\mathrm{1},\:{touch}\:{one} \\ $$$${another}\:{externally}\:{and}\:{they}\:{lie} \\ $$$${between}\:{two}\:{parallel}\:{line}.\:{The}\: \\ $$$${minimum}\:{possible}\:{distance}\:{between}\: \\ $$$${the}\:{lines}\:{is}\:\_\: \\ $$ Answered by bobhans last updated…
Question Number 72665 by TawaTawa last updated on 31/Oct/19 $$\int_{\:\mathrm{2}} ^{\:\mathrm{3}} \:\:\frac{\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{x}\right)}{\mathrm{1}\:−\:\mathrm{x}^{\mathrm{2}} }\:\mathrm{dx} \\ $$ Commented by mind is power last updated on 31/Oct/19…
Question Number 7127 by Tawakalitu. last updated on 11/Aug/16 Commented by Yozzii last updated on 11/Aug/16 $${Let}\:{u}={x}\sqrt{\mathrm{1}+\left({x}+\mathrm{1}\right)+\sqrt{\mathrm{1}+\left({x}+\mathrm{2}\right)+\sqrt{\mathrm{1}+\left({x}+\mathrm{3}\right)+\sqrt{\mathrm{1}+….}}}} \\ $$$$\Rightarrow\frac{{u}}{{x}}=\sqrt{\mathrm{1}+\left({x}+\mathrm{1}\right)+\sqrt{\mathrm{1}+\left({x}+\mathrm{2}\right)+\sqrt{\mathrm{1}+\left({x}+\mathrm{3}\right)+\sqrt{\mathrm{1}+….}}}} \\ $$$${let}\:{n}={x}+\mathrm{1}\Rightarrow{x}={n}−\mathrm{1}. \\ $$$$\therefore\frac{{u}}{{n}−\mathrm{1}}=\sqrt{\mathrm{1}+{n}+\sqrt{\mathrm{1}+\left({n}+\mathrm{1}\right)+\sqrt{\mathrm{1}+\left({n}+\mathrm{2}\right)+\sqrt{\mathrm{1}+\left({n}+\mathrm{3}\right)+\sqrt{\mathrm{1}+…..}}}}} \\ $$$$\frac{{u}^{\mathrm{2}}…
Question Number 7126 by Tawakalitu. last updated on 11/Aug/16 Commented by Tawakalitu. last updated on 11/Aug/16 $${I}\:{need}\:{solution}\:{to}\:{this}\:{one}.\:{thanks}\:{in}\:{advance} \\ $$ Commented by Yozzii last updated on…
Question Number 7125 by Tawakalitu. last updated on 11/Aug/16 Commented by Tawakalitu. last updated on 11/Aug/16 $${I}\:{have}\:{seen}\:{a}\:{solution}\:{to}\:{this}\:{question} \\ $$ Answered by sandy_suhendra last updated on…
Question Number 138193 by mey3nipaba last updated on 10/Apr/21 $${Given}\:{x}\neq{y}\:{and}\:{x}^{\mathrm{2}} =\mathrm{25}{x}+{y},\:{y}^{\mathrm{2}} ={x}+\mathrm{25}{y}\: \\ $$$${solve}\:{for}\:{the}\:{value}\:{of}\:\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{1}}\:{without}\: \\ $$$${using}\:{calculators}\:{or}\:{tools}. \\ $$$${Show}\:{your}\:{method}. \\ $$ Answered by liberty…
Question Number 7122 by 314159 last updated on 11/Aug/16 Answered by uchechukwu okorie favour last updated on 11/Aug/16 $${let}\:{the}\:{probability}\:{that}\:{a}\:{student} \\ $$$${picked}\:{at}\:{random}\:{be}\:{taller}\:{than} \\ $$$$\mathrm{1}.\mathrm{8}\:{metres}\:{be}\:{Pr}\left({T}\right) \\ $$$${Also};\:{let}\:{the}\:{probability}\:{that}\:{a}…
Question Number 72640 by azizullah last updated on 31/Oct/19 Answered by ajfour last updated on 31/Oct/19 $$\mathrm{1}+\mathrm{0}=\mathrm{1} \\ $$ Answered by MJS last updated on…