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Author: Tinku Tara

calculate-dx-2-x-2-3-x-2-

Question Number 138128 by mathmax by abdo last updated on 10/Apr/21 $$\mathrm{calculate}\:\int\:\:\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{2}−\mathrm{x}^{\mathrm{2}} }+\sqrt{\mathrm{3}+\mathrm{x}^{\mathrm{2}} }} \\ $$ Answered by MJS_new last updated on 10/Apr/21 $$\int\frac{{dx}}{\:\sqrt{\mathrm{2}−{x}^{\mathrm{2}} }+\sqrt{\mathrm{3}+{x}^{\mathrm{2}}…

2-2-2-2-

Question Number 72595 by zillnehu@gmail.com last updated on 30/Oct/19 $$\left(\alpha+\beta\right)^{\mathrm{2}} \:=\:\alpha^{\mathrm{2}} \:+\:\mathrm{2}\alpha\beta\:+\:\beta^{\mathrm{2}\:} \\ $$ Commented by ajfour last updated on 30/Oct/19 $${according}\:{to}\:{new}\:{research}.. \\ $$ Commented…

If-the-length-of-a-square-is-increased-by-25-while-its-width-is-decrease-by-15-to-form-a-rectangle-What-is-the-ratio-of-the-area-of-the-rectangle-to-the-area-of-the-square-

Question Number 72593 by TawaTawa last updated on 30/Oct/19 $$\mathrm{If}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{a}\:\mathrm{square}\:\mathrm{is}\:\mathrm{increased}\:\mathrm{by}\:\:\mathrm{25\%}\:\mathrm{while}\:\mathrm{its} \\ $$$$\mathrm{width}\:\mathrm{is}\:\mathrm{decrease}\:\mathrm{by}\:\:\:\mathrm{15\%}\:\:\:\mathrm{to}\:\mathrm{form}\:\mathrm{a}\:\mathrm{rectangle}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{rectangle}\:\mathrm{to}\:\mathrm{the} \\ $$$$\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square} \\ $$ Answered by Tanmay chaudhury last updated on…

Show-that-x-0-2-tanx-sin4x-0-

Question Number 7055 by Tawakalitu. last updated on 08/Aug/16 $${Show}\:{that}\:\forall\:{x}\:\in\:\left[\:\mathrm{0},\:\frac{\Pi}{\mathrm{2}}\:\right]\:,\:{tanx}\:+\:{sin}\mathrm{4}{x}\:\geqslant\:\mathrm{0}\: \\ $$$$ \\ $$ Commented by Yozzii last updated on 08/Aug/16 $${If}\:\mathrm{0}\leqslant{x}\leqslant\frac{\pi}{\mathrm{2}}\Rightarrow\mathrm{0}\leqslant\mathrm{4}{x}\leqslant\mathrm{2}\pi \\ $$$${For}\:−\mathrm{1}\leqslant{sin}\mathrm{4}{x}<\mathrm{0}\Rightarrow\pi<\mathrm{4}{x}\leqslant\frac{\mathrm{3}\pi}{\mathrm{2}}\:{or}\:\frac{\mathrm{3}\pi}{\mathrm{2}}\leqslant\mathrm{4}{x}<\mathrm{2}\pi\: \\…

Solve-for-x-x-x-27x-x-

Question Number 72589 by TawaTawa last updated on 30/Oct/19 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}:\:\:\:\:\left(\sqrt{\boldsymbol{\mathrm{x}}}\right)^{\boldsymbol{\mathrm{x}}} \:\:=\:\:\mathrm{27}\boldsymbol{\mathrm{x}}^{\sqrt{\boldsymbol{\mathrm{x}}}} \\ $$ Commented by MJS last updated on 30/Oct/19 $$\mathrm{trying}\:\mathrm{we}\:\mathrm{find}\:{x}=\mathrm{9} \\ $$ Commented by…