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Author: Tinku Tara

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Question Number 7000 by FilupSmith last updated on 05/Aug/16 $${x}^{\mathrm{2}} ={x}+\sqrt{{x}} \\ $$$${x}=\mathrm{0}\:\vee\:{x}=?? \\ $$ Commented by Yozzii last updated on 05/Aug/16 $${Let}\:{u}=\sqrt{{x}}\Rightarrow{u}^{\mathrm{2}} ={x}\Rightarrow{u}^{\mathrm{4}} ={x}^{\mathrm{2}}…

v-x-c-c-constant-What-is-the-area-under-v-excluding-A-1-2-xc-area-of-triangle-

Question Number 6999 by FilupSmith last updated on 05/Aug/16 $$\boldsymbol{{v}}=\begin{bmatrix}{{x}}\\{{c}}\end{bmatrix},\:{c}=\mathrm{constant} \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{area}\:\mathrm{under}\:\boldsymbol{{v}}? \\ $$$$ \\ $$$${excluding}:\:\:\:\:{A}=\frac{\mathrm{1}}{\mathrm{2}}{xc}\:\:\:\left({area}\:{of}\:{triangle}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

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Question Number 138068 by Ñï= last updated on 09/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}{x}^{\mathrm{2}{n}} \zeta\left(\mathrm{2}{n}\right)=\frac{\mathrm{1}}{\mathrm{2}}−\frac{\pi{x}}{\mathrm{2}}\mathrm{cot}\:\pi{x} \\ $$ Answered by Dwaipayan Shikari last updated on 09/Apr/21 $$\underset{{n}=\mathrm{1}} {\overset{\infty}…

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Question Number 138065 by mnjuly1970 last updated on 09/Apr/21 $$\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:…{nice}\:…\:…\:…\:{calculus}… \\ $$$$\:\:\:\:\:\:\:{prove}:: \\ $$$$\:\:\:\:\:\:\:\:\:\Omega=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\zeta\left(\mathrm{2}{n}+\mathrm{1}\right)−\mathrm{1}}{{n}+\mathrm{1}}\:=−\gamma+{log}\left(\mathrm{2}\right) \\ $$ Answered by Ñï= last updated…

if-the-lcm-and-gcf-of-three-numbers-are-360-and-6-other-numbers-are-18-and-60-Find-the-third-number-I-need-help-plz-

Question Number 72526 by liki last updated on 30/Oct/19 $${if}\:{the}\:{lcm}\:{and}\:{gcf}\:{of}\:{three}\:{numbers} \\ $$$$\:{are}\:\mathrm{360}\:{and}\:\mathrm{6},{other}\:{numbers}\:{are}\:\mathrm{18}\: \\ $$$$\:{and}\:\mathrm{60}.{Find}\:{the}\:{third}\:{number}. \\ $$$$\:\:\:\:\:\:\:\:…\:{I}\:{need}\:{help}\:{plz}… \\ $$ Commented by TawaTawa last updated on 30/Oct/19…