Question Number 6972 by Tawakalitu. last updated on 03/Aug/16 $${Evaluate}\:\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:{dx}\:\underset{\mathrm{0}} {\overset{{x}} {\int}}\:{e}^{\frac{{y}}{{x}}} \:{dy} \\ $$ Answered by FilupSmith last updated on 03/Aug/16 $$=\mathrm{1}\left(\frac{\mathrm{1}}{{x}}\left[{e}^{{y}/{x}}…
Question Number 138041 by mnjuly1970 last updated on 09/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:…….{advanced}\:…\:…\:…\:{calculus}…… \\ $$$$\:\:{prove}\:\:{that}\:::: \\ $$$$\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \psi\left({x}\right).{sin}\left(\mathrm{2}\pi{x}\right){dx}=−\frac{\pi}{\mathrm{2}}\:…\checkmark \\ $$$$ \\ $$ Answered by Dwaipayan Shikari last…
Question Number 6971 by Tawakalitu. last updated on 03/Aug/16 $${Evaluate}\:\:\int\left({x}\:+\:\mathrm{3}{y}\right)\:{dx} \\ $$$${from}\:\left(\mathrm{0},\mathrm{1}\right)\:{to}\:\left(\mathrm{2},\mathrm{5}\right)\:{along}\:{the}\:{curve}\:\:{y}\:=\:\mathrm{1}\:+\:{x}^{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 6970 by Tawakalitu. last updated on 03/Aug/16 $${Integrate}\:\:{dz}\:=\:\left(\mathrm{8}{e}^{\mathrm{4}{x}} \:+\:\mathrm{2}{xy}^{\mathrm{2}} \right)\:{dx}\:+\:\left(\mathrm{4}{cos}\:\mathrm{4}{y}\:\:−\:\mathrm{2}{xy}\right)\:{dy} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 138037 by greg_ed last updated on 09/Apr/21 $$\underline{\boldsymbol{\mathrm{States}}} \\ $$$$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{increase}}\:\boldsymbol{\mathrm{in}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{population}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{country}}\:\boldsymbol{\mathrm{is}} \\ $$$$\boldsymbol{\mathrm{proportional}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{population}}. \\ $$$$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{population}}\:\boldsymbol{\mathrm{doubles}}\:\boldsymbol{\mathrm{every}}\:\mathrm{50}\:\boldsymbol{\mathrm{years}}. \\ $$$$\boldsymbol{\mathrm{How}}\:\boldsymbol{\mathrm{quickly}}\:\boldsymbol{\mathrm{does}}\:\boldsymbol{\mathrm{it}}\:\boldsymbol{\mathrm{triple}}\:? \\ $$ Answered by MJS_new last updated…
Question Number 72498 by Mr Jor last updated on 29/Oct/19 $${Karanja}\:{and}\:{Ouma}\:{can}\:{do}\:{a}\: \\ $$$${certain}\:{job}\:{in}\:\mathrm{6}\:{days}.\:{Karanja}\: \\ $$$${alone}\:{can}\:{do}\:{the}\:{work}\:{in}\:\mathrm{5}\:{days} \\ $$$${more}\:{than}\:{Ouma}.\:{How}\:{many}\: \\ $$$${days}\:{can}\:{Karanja}\:{take}\:{to}\:{do}\:{the} \\ $$$${job}\:{alone}? \\ $$ Answered by…
Question Number 72499 by Mr Jor last updated on 29/Oct/19 $${Find}\:{the}\:{ratio}\:{of};\:{x}:{y}\:{if}\:\mathrm{10}{x}^{\mathrm{2}} −\mathrm{9}{xy} \\ $$$$+\mathrm{2}{y}^{\mathrm{2}} =\mathrm{0} \\ $$ Answered by Tanmay chaudhury last updated on 29/Oct/19…
Question Number 72496 by Shamim last updated on 29/Oct/19 $$\mathrm{if}\:\mathrm{a}^{\mathrm{x}} =\mathrm{b},\:\mathrm{b}^{\mathrm{y}} =\mathrm{c},\:\mathrm{c}^{\mathrm{z}} =\mathrm{a}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}, \\ $$$$\mathrm{xyz}=\mathrm{0}. \\ $$ Answered by som(math1967) last updated on 29/Oct/19 $${a}^{{x}}…
Question Number 72497 by Shamim last updated on 29/Oct/19 $$\mathrm{if},\:\mathrm{cot}\:\theta+\mathrm{cosec}\:\theta=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:\theta\:\mathrm{where}\:\mathrm{0}<\theta\leqslant\mathrm{2}\pi. \\ $$ Answered by behi83417@gmail.com last updated on 29/Oct/19 $$\frac{\mathrm{cos}\theta}{\mathrm{sin}\theta}+\frac{\mathrm{1}}{\mathrm{sin}\theta}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\Rightarrow\frac{\mathrm{1}+\mathrm{cos}\theta}{\mathrm{sin}\theta}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\Rightarrow \\ $$$$\frac{\mathrm{2cos}^{\mathrm{2}} \frac{\theta}{\mathrm{2}}}{\mathrm{2sin}\frac{\theta}{\mathrm{2}}\mathrm{cos}\frac{\theta}{\mathrm{2}}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}\Rightarrow\begin{cases}{\mathrm{1}.\mathrm{cos}\frac{\theta}{\mathrm{2}}=\mathrm{0}}\\{\mathrm{2}.\mathrm{cot}\frac{\theta}{\mathrm{2}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}}\end{cases}…