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Prove-that-2-4-G-Potential-of-Gravitational-field-Density-G-Universal-Gravitational-Constant-

Question Number 137970 by Dwaipayan Shikari last updated on 08/Apr/21 $${Prove}\:{that}\: \\ $$$$\bigtriangledown^{\mathrm{2}} \boldsymbol{\phi}=−\mathrm{4}\boldsymbol{\pi{G}}\rho\:\: \\ $$$$\phi={Potential}\:{of}\:{Gravitational}\:{field} \\ $$$$\rho={Density}\:\:\:\boldsymbol{{G}}={Universal}\:{Gravitational}\:{Constant} \\ $$ Answered by ajfour last updated…

Hello-find-finde-0-ln-x-x-2-ax-b-dx-conditions-a-2-lt-4b-in-therm-of-x-1-x-2-root-of-X-2-aX-b-hint-Residus-theorem-applied-too-log-2-z-z-2-az-b-this-is-very-usufull-

Question Number 72430 by mind is power last updated on 28/Oct/19 $$\mathrm{Hello}\:\mathrm{find} \\ $$$$\mathrm{finde}\:\:\int_{\mathrm{0}} ^{+\infty} \frac{\mathrm{ln}\left(\mathrm{x}\right)}{\mathrm{x}^{\mathrm{2}} +\mathrm{ax}+\mathrm{b}}\mathrm{dx} \\ $$$$\mathrm{conditions}\:\mathrm{a}^{\mathrm{2}} <\mathrm{4b}\:\:\: \\ $$$$\mathrm{in}\:\mathrm{therm}\:\mathrm{of}\:\mathrm{x}_{\mathrm{1}} ,\mathrm{x}_{\mathrm{2}} \:\:\mathrm{root}\:\mathrm{of}\:\mathrm{X}^{\mathrm{2}} +\mathrm{aX}+\mathrm{b}\:…

Question-6893

Question Number 6893 by Tawakalitu. last updated on 01/Aug/16 Commented by Rasheed Soomro last updated on 02/Aug/16 $$\bullet{Surface}\:{area}\:{of}\:{sphere}=\mathrm{4}\pi{r}^{\mathrm{2}} \\ $$$$\:{Radius}\:{of}\:{the}\:\:{sphere}\:=\frac{\mathrm{12}}{\mathrm{2}}=\mathrm{6}\:{cm} \\ $$$${Surface}\:{area}\:{of}\:{sphere}=\mathrm{4}\pi\left(\mathrm{6}\right)^{\mathrm{2}} =\mathrm{144}\pi……….\left({i}\right) \\ $$$$…

Question-6890

Question Number 6890 by Tawakalitu. last updated on 01/Aug/16 Commented by Yozzii last updated on 02/Aug/16 $${Let}\:{EC}={x}.\:{BD}=\mathrm{3},\:{DA}=\mathrm{5} \\ $$$${BD}={BE}\:{since}\:{BD}\:{and}\:{BE}\:{are}\:{lines} \\ $$$${tangent}\:{to}\:{the}\:{same}\:{circle}\:{from}\: \\ $$$${the}\:{common}\:{point}\:{B}. \\ $$$$\therefore\:{BE}=\mathrm{3}.\:{Similarly},\:{DA}={AF}=\mathrm{5},…

1000-2-999-2-998-2-997-2-2-2-1-2-Please-the-question-says-simplify-

Question Number 6885 by Tawakalitu. last updated on 01/Aug/16 $$\left(\mathrm{1000}\right)^{\mathrm{2}} \:−\:\left(\mathrm{999}\right)^{\mathrm{2}} \:+\:\left(\mathrm{998}\right)^{\mathrm{2}} \:−\:\left(\mathrm{997}\right)^{\mathrm{2}} +\:………\:+\:\mathrm{2}^{\mathrm{2}} \:−\:\mathrm{1}^{\mathrm{2}} \:=\:? \\ $$$$ \\ $$$${Please}\:{the}\:{question}\:{says}\:{simplify} \\ $$ Answered by sou1618…