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Author: Tinku Tara

2x-4-5x-3-6x-2-6x-12-x-2-2x-2-3-2-dx-A-very-nice-solution-2x-4-5x-3-6x-2-6x-12-x-2-2x-2-3-2-dx-f-x-x-2-2x-2-C-f-x-ax-3-bx-2-cx-d-f

Question Number 137938 by Ñï= last updated on 09/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int\frac{\mathrm{2}{x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{3}} +\mathrm{6}{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{12}}{\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\right)^{\mathrm{3}/\mathrm{2}} }{dx}=? \\ $$$${A}\:{very}\:{nice}\:{solution}:: \\ $$$$\int\frac{\mathrm{2}{x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{3}} +\mathrm{6}{x}^{\mathrm{2}} +\mathrm{6}{x}+\mathrm{12}}{\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\right)^{\mathrm{3}/\mathrm{2}} }{dx}=\frac{{f}\left({x}\right)}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}}}+{C}…

lim-x-x-x-2-ln-1-1-x-

Question Number 72398 by 20190927 last updated on 28/Oct/19 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left[\mathrm{x}−\mathrm{x}^{\mathrm{2}} \mathrm{ln}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{x}}\right)\right] \\ $$ Commented by mathmax by abdo last updated on 28/Oct/19 $${let}\:{f}\left({x}\right)={x}−{x}^{\mathrm{2}} {ln}\left(\mathrm{1}+\frac{\mathrm{1}}{{x}}\right)\:\:{we}\:{have}\:{ln}^{'}…

Solve-the-partial-fraction-4s-3-39-2-s-2-42s-40-s-s-2-s-2-6s-10-

Question Number 6861 by Tawakalitu. last updated on 31/Jul/16 $${Solve}\:{the}\:{partial}\:{fraction}\: \\ $$$$\frac{\mathrm{4}{s}^{\mathrm{3}} \:−\:\frac{\mathrm{39}}{\mathrm{2}}{s}^{\mathrm{2}} \:+\:\mathrm{42}{s}\:−\:\mathrm{40}}{{s}\left({s}\:−\:\mathrm{2}\right)\left({s}^{\mathrm{2}} \:−\:\mathrm{6}{s}\:+\:\mathrm{10}\right)} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

let-g-x-ln-1-x-3-x-2-1-find-g-n-x-and-g-n-0-2-developp-g-at-integr-serie-

Question Number 72394 by mathmax by abdo last updated on 28/Oct/19 $${let}\:{g}\left({x}\right)=\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{3}+{x}^{\mathrm{2}} } \\ $$$$\left.\mathrm{1}\right)\:{find}\:{g}^{\left({n}\right)} \left({x}\right){and}\:{g}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{g}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by…