Question Number 137582 by SOMEDAVONG last updated on 04/Apr/21 $$\mathrm{A}=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$ Answered by Ñï= last updated on 04/Apr/21 $${A}=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}−\mathrm{1}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$$$=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}\left(\sqrt[{\mathrm{3}}]{\mathrm{4}}−\mathrm{1}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{2}} }=\sqrt[{\mathrm{3}}]{\frac{\mathrm{1}}{\mathrm{3}}\left(\sqrt[{\mathrm{3}}]{\mathrm{4}}−\mathrm{1}\right)\left(\sqrt[{\mathrm{3}}]{\mathrm{4}}+\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{2}}+\mathrm{1}\right)}…
Question Number 137579 by liberty last updated on 04/Apr/21 $$\left(−\mathrm{1}\right)×\frac{\mathrm{1}}{\pi.{i}}\:=?\: \\ $$ Answered by Engr_Jidda last updated on 04/Apr/21 $$\left(−\mathrm{1}\right)×\frac{\mathrm{1}}{\pi{i}}=\:{i}^{\mathrm{2}} \frac{\mathrm{1}}{\pi{i}}=\frac{{i}}{\pi} \\ $$ Terms of…
Question Number 6505 by nburiburu last updated on 29/Jun/16 $${Find}\:{general}\:{solution}\:{for} \\ $$$${y}'\:+{P}\left({x}\right)\centerdot{y}^{\mathrm{2}} ={Q}\left({x}\right) \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137575 by Engr_Jidda last updated on 04/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 72036 by mr W last updated on 23/Oct/19 Commented by mr W last updated on 23/Oct/19 $${the}\:{cup}\:{has}\:{the}\:{shape}\:{of}\:{hemisphere} \\ $$$${with}\:{radius}\:{R}.\:{a}\:{stick}\:{of}\:{mass}\:{m}\:{and} \\ $$$${length}\:{l}\:\left(\mathrm{2}{R}<{l}<\mathrm{4}{R}\right)\:{is}\:{released}\:{at} \\ $$$${blue}\:{position}.\:{there}\:{is}\:{no}\:{friction}…
Question Number 137574 by Engr_Jidda last updated on 04/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137568 by JulioCesar last updated on 04/Apr/21 Commented by JulioCesar last updated on 04/Apr/21 $${why}\:{it}\:{has}\:{background}?? \\ $$ Commented by mr W last updated…
Question Number 6495 by sanusihammed last updated on 29/Jun/16 $${A}\:{refrigerator}\:{is}\:{rated}\:\mathrm{20}\:{watts}\:{of}\:{electricity}\:{which} \\ $$$${cost}\:\mathrm{5}{k}\:{per}\:{kwh}\:,\:{what}\:{is}\:{the}\:{cost}\:{of}\:{operation}\:{for}\:\mathrm{20}\:{days}. \\ $$ Answered by sandy_suhendra last updated on 30/Jun/16 $$\mathrm{20}\:{days}×\mathrm{24}\:{hour}×\mathrm{20}\:{watts}=\mathrm{9600}\:{wh}=\mathrm{9}.\mathrm{6}{kwh} \\ $$$${it}'{s}\:{cost}=\mathrm{9}.\mathrm{6}×\mathrm{5}{k}=\mathrm{48}{k} \\…
Question Number 72026 by mathmax by abdo last updated on 23/Oct/19 $${prove}\:{that}\:{x}^{\mathrm{4}} \:{divide}\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{{n}} −{nx}^{\mathrm{2}} −\mathrm{1}\:\:{without}\:{use}\:\:{binomial} \\ $$$${formula}. \\ $$ Commented by mathmax by abdo…
Question Number 6491 by Temp last updated on 29/Jun/16 $$\mathrm{Is}\:\mathrm{it}\:\mathrm{possible}\:\mathrm{such}\:\mathrm{that}\:\mathrm{two}\:\mathrm{trancendental} \\ $$$$\mathrm{numbers}\:\mathrm{add}\:\mathrm{or}\:\mathrm{multiply}\:\mathrm{to}\:\mathrm{give}\:\mathrm{a}\:\mathrm{whole}\:\mathrm{number}? \\ $$ Commented by prakash jain last updated on 29/Jun/16 $$\pi\:\mathrm{is}\:\mathrm{transcendental}. \\ $$$$\frac{\mathrm{1}}{\pi}\:\mathrm{is}\:\mathrm{also}\:\mathrm{transcendental}.…