Menu Close

Author: Tinku Tara

x-y-dx-x-y-2-dy-0-

Question Number 137558 by liberty last updated on 04/Apr/21 $$\left({x}+{y}\right){dx}\:+\:\left({x}+{y}^{\mathrm{2}} \right){dy}\:=\:\mathrm{0}\: \\ $$ Answered by Ñï= last updated on 04/Apr/21 $$\left({x}+{y}\right){dx}+\left({x}+{y}^{\mathrm{2}} \right){dy} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}{d}\left({x}^{\mathrm{2}} \right)+{ydx}+{xdy}+\frac{\mathrm{1}}{\mathrm{3}}{d}\left({y}^{\mathrm{3}}…

Question-6476

Question Number 6476 by sanusihammed last updated on 28/Jun/16 Answered by Rasheed Soomro last updated on 28/Jun/16 $${Given}\:{equation}:\:{x}^{\mathrm{2}} −{px}+\mathrm{8}=\mathrm{0} \\ $$$$\:\:\:\:\:{Sum}\:{of}\:{the}\:{roots}\:=−\frac{{coefficient}\:{of}\:{x}}{{coefficient}\:{of}\:{x}^{\mathrm{2}} } \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=−\frac{−{p}}{\mathrm{1}}={p} \\…