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Author: Tinku Tara

let-g-x-ln-1-x-3-x-2-1-find-g-n-x-and-g-n-0-2-developp-g-at-integr-serie-

Question Number 72394 by mathmax by abdo last updated on 28/Oct/19 $${let}\:{g}\left({x}\right)=\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{3}+{x}^{\mathrm{2}} } \\ $$$$\left.\mathrm{1}\right)\:{find}\:{g}^{\left({n}\right)} \left({x}\right){and}\:{g}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{g}\:{at}\:{integr}\:{serie} \\ $$ Commented by mathmax by…

nice-calculus-calculation-of-2-6-1-x-2-x-4-x-6-1-3-cos-2021-pix-x-2-8x-20-dx-solution-x-4-t-x-6-t-2

Question Number 137930 by mnjuly1970 last updated on 08/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:…..{nice}\:\:…\:…\:{calculus}….. \\ $$$$\:\:\:\:\:{calculation}\:{of}::: \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{2}} ^{\:\mathrm{6}} \:\frac{\mathrm{1}+\left(\sqrt[{\mathrm{3}}]{\left({x}−\mathrm{2}\right)\left({x}−\mathrm{4}\right)\left({x}−\mathrm{6}\right)}\:\right){cos}^{\mathrm{2021}} \left(\pi{x}\right)}{{x}^{\mathrm{2}} −\mathrm{8}{x}+\mathrm{20}}{dx}=? \\ $$$$\:\:\:\:\:{solution}:: \\ $$$$\:\:\:\:\:{x}−\mathrm{4}={t}\:\Rightarrow\left\{_{\:{x}=\mathrm{6}\:\Rightarrow\:{t}=\mathrm{2}} ^{{x}=\mathrm{2}\:\Rightarrow{t}=−\mathrm{2}} \right. \\…

let-f-x-cos-narccosx-1-calculate-f-n-x-and-f-n-0-2-developp-f-at-integr-serie-

Question Number 72393 by mathmax by abdo last updated on 28/Oct/19 $${let}\:{f}\left({x}\right)\:={cos}\left({narccosx}\right) \\ $$$$\left.\mathrm{1}\right){calculate}\:{f}^{\left({n}\right)} \left({x}\right)\:{and}\:{f}^{\left({n}\right)} \left(\mathrm{0}\right) \\ $$$$\left.\mathrm{2}\right){developp}\:{f}\:{at}\:{integr}\:{serie} \\ $$ Terms of Service Privacy Policy…

0-2-x-2-cos-xdx-

Question Number 137926 by brayan last updated on 08/Apr/21 $$\int_{\mathrm{0}} ^{\frac{\Pi}{\mathrm{2}}} {x}^{\mathrm{2}} \mathrm{cos}\:{xdx}= \\ $$ Answered by Ñï= last updated on 08/Apr/21 $$\frac{\mathrm{1}}{{D}}{x}^{\mathrm{2}} \mathrm{cos}\:{x}={Re}\left({e}^{{ix}} \frac{\mathrm{1}}{{D}+{i}}{x}^{\mathrm{2}}…