Question Number 72389 by mathmax by abdo last updated on 28/Oct/19 $${find}\:\sum_{{k}=\mathrm{1}} ^{{n}} {k}\left({C}_{{n}} ^{{k}} \right)^{\mathrm{2}} \:{interms}\:{of}\:{n} \\ $$ Answered by mind is power last…
Question Number 6852 by Tawakalitu. last updated on 31/Jul/16 Commented by Tawakalitu. last updated on 31/Jul/16 $${Please}\:{i}\:{need}\:{solution}\:{here}….\:{to}\:{solve}\:{for}\:{x} \\ $$ Answered by Rasheed Soomro last updated…
Question Number 6846 by Tawakalitu. last updated on 30/Jul/16 $${x}^{{x}} \:=\:\mathrm{16} \\ $$$$ \\ $$$${find}\:{the}\:{value}\:{of}\:{x}\: \\ $$ Commented by Rasheed Soomro last updated on 31/Jul/16…
Question Number 6843 by Tawakalitu. last updated on 30/Jul/16 $$\mathrm{2}^{\mathrm{10}} \:+\:\mathrm{3}^{\mathrm{20}} \:+\:\mathrm{4}^{\mathrm{30}} \:+\:\mathrm{5}^{\mathrm{40}} \:+\:\mathrm{6}^{\mathrm{50}} \:\:\left({mod}\:\mathrm{7}\right)\:=\:? \\ $$ Commented by prakash jain last updated on 31/Jul/16…
Question Number 6841 by Tawakalitu. last updated on 30/Jul/16 $${Integrate}:\:\:{x}\:{sec}^{\mathrm{2}} \left({x}^{\mathrm{2}} \right) \\ $$$$ \\ $$ Commented by Tawakalitu. last updated on 30/Jul/16 $${I}\:{have}\:{solve}\:{this}\:{one}.\:{i}\:{got}\:…\:\:\:\frac{\mathrm{1}}{\mathrm{2}}\:{tan}\left({x}^{\mathrm{2}} \right)\:+\:{C}…
Question Number 6838 by Tawakalitu. last updated on 30/Jul/16 $${Find}\:{the}\:{value}\:{of}\:{x} \\ $$$$\mathrm{4}^{{x}} \:=\:\frac{\mathrm{243}}{{x}} \\ $$ Commented by Yozzii last updated on 31/Jul/16 $$\mathrm{4}^{{x}} =\frac{\mathrm{243}}{{x}} \\…
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Question Number 6834 by nburiburu last updated on 30/Jul/16 $${a}\in\mathbb{Z},\:\left(\mathrm{2}{a}^{\mathrm{3}} +\mathrm{3}{a}^{\mathrm{2}} −\mathrm{3}{a}+\mathrm{7}\::\:{a}^{\mathrm{2}} +{a}−\mathrm{2}\right)\neq\mathrm{1}\:\Leftrightarrow\:{a}=\mathrm{3}{k}+\mathrm{1},\:{k}\in\mathbb{Z} \\ $$ Commented by Yozzii last updated on 30/Jul/16 $${All}\:{integers}\:{can}\:{be}\:{written}\:{in}\:{one} \\ $$$${of}\:{the}\:{following}\:{forms}\:{since}…
Question Number 137907 by peter frank last updated on 08/Apr/21 Answered by EnterUsername last updated on 08/Apr/21 $$\int_{\mathrm{1}} ^{{e}} \frac{\mathrm{1}+{lnx}}{{x}}{dx}=\int_{\mathrm{1}} ^{{e}} \left(\frac{\mathrm{1}}{{x}}+\frac{{lnx}}{{x}}\right){dx} \\ $$$$=\left[{lnx}+\frac{{ln}^{\mathrm{2}} {x}}{\mathrm{2}}\right]_{\mathrm{1}}…
Question Number 137906 by peter frank last updated on 08/Apr/21 Terms of Service Privacy Policy Contact: info@tinkutara.com