Question Number 137112 by Algoritm last updated on 29/Mar/21 Answered by Ñï= last updated on 03/Apr/21 $$\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{3}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{2}}{\mathrm{9}}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{4}}{\mathrm{23}}\right)+… \\ $$$$={arg}\left(\mathrm{3}+{i}\right)+{arg}\left(\mathrm{9}+\mathrm{2}{i}\right)+{arg}\left(\mathrm{23}+\mathrm{4}{i}\right)+… \\ $$$$={arg}\left[\left(\mathrm{3}+{i}\right)\left(\mathrm{9}+\mathrm{2}{i}\right)\left(\mathrm{23}+\mathrm{4}{i}\right)\centerdot…\right] \\…
Question Number 6042 by FilupSmith last updated on 10/Jun/16 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{solve}\:\mathrm{the}\:\mathrm{indefinite}\:\mathrm{integral}: \\ $$$$\int{e}^{−{u}} {u}^{{n}} {du} \\ $$ Commented by Yozzii last updated on 11/Jun/16 $${Define}\:{I}\left({n}\right)=\int{e}^{−{u}} {u}^{{n}}…
Question Number 137115 by yutytfjh67ihd last updated on 29/Mar/21 $${Q}\mathrm{136739} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137111 by mnjuly1970 last updated on 29/Mar/21 Answered by Dwaipayan Shikari last updated on 29/Mar/21 $$\underset{{n}=−\infty} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} +\mathrm{1}}=\mathrm{1}+\mathrm{2}\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} +\mathrm{1}}=\mathrm{1}+\frac{\mathrm{2}}{\mathrm{2}}\left(\pi{coth}\left(\pi\right)−\mathrm{1}\right)=\pi\frac{{e}^{\mathrm{2}\pi} +\mathrm{1}}{{e}^{\mathrm{2}\pi}…
Question Number 71572 by TawaTawa last updated on 17/Oct/19 Commented by TawaTawa last updated on 17/Oct/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\:\mathrm{How}\:? \\ $$ Answered by Kunal12588 last updated on…
Question Number 71570 by TawaTawa last updated on 17/Oct/19 $$\mathrm{Solve}:\:\:\:\:\:\left(\mathrm{2x}\:+\:\mathrm{x}^{\mathrm{2}} \right)\mathrm{y}''\:−\:\mathrm{2}\left(\mathrm{1}\:+\:\mathrm{x}\right)\mathrm{y}'\:+\:\mathrm{2y}\:\:=\:\:\mathrm{0} \\ $$$$\mathrm{Given}\:\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} \:\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution}. \\ $$ Answered by mind is power last updated on 17/Oct/19…
Question Number 137106 by mohammad17 last updated on 29/Mar/21 Commented by radians last updated on 30/Mar/21 $${lazy}\:{man} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 137100 by BHOOPENDRA last updated on 29/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137103 by Boucatchou last updated on 29/Mar/21 $$\:\:\:\:\:\:\:\:\:{Solve}\:\:\mathrm{3}{cos}\mathrm{5}{x}−\mathrm{4}{sin}\mathrm{4}{x}−\mathrm{3}=\mathrm{0}\:\:{in}\:\mathbb{R} \\ $$ Answered by MJS_new last updated on 30/Mar/21 $$\mathrm{obviously}\:{x}=\mathrm{2}{n}\pi\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution} \\ $$$$\mathrm{the}\:\mathrm{others}\:\mathrm{can}\:\mathrm{only}\:\mathrm{be}\:\mathrm{approximated} \\ $$$${x}\approx.\mathrm{966119}+\mathrm{2}{n}\pi \\…
Question Number 71564 by 20190927 last updated on 17/Oct/19 $$\left(\mathrm{z}−\mathrm{i}\right)^{\mathrm{4}} =−\mathrm{7}+\mathrm{24i} \\ $$ Commented by mathmax by abdo last updated on 18/Oct/19 $${we}\:{have}\:\mid−\mathrm{7}+\mathrm{24}{i}\mid=\sqrt{\mathrm{7}^{\mathrm{2}} \:+\mathrm{24}^{\mathrm{2}} }=\sqrt{\mathrm{49}+\mathrm{576}}=\sqrt{\mathrm{625}}=\mathrm{25}\:\Rightarrow…