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Question-5825

Question Number 5825 by Rasheed Soomro last updated on 30/May/16 Commented by Rasheed Soomro last updated on 30/May/16 $$\mathrm{A}\:\mathrm{is}\:\mathrm{the}\:\mathrm{center}\:\mathrm{of}\:\mathrm{arc}\:\mathrm{BC}. \\ $$$$\mathrm{AB}=\mathrm{AE}=\mathrm{AG}=\mathrm{AC} \\ $$$$\mathrm{AB}\:{m}\mathrm{eans}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B} \\ $$$$\mathrm{Similarly}\:\mathrm{AE},\mathrm{AG},\mathrm{AC}\:\mathrm{are}\:\mathrm{also}\:\mathrm{distances}.…

Prove-that-among-all-triangles-which-have-same-circum-radius-the-equilateral-triangle-has-maximum-area-

Question Number 5822 by Rasheed Soomro last updated on 30/May/16 $$\mathcal{P}{rove}\:{that}\:{among}\:{all}\:\boldsymbol{{triangles}}, \\ $$$${which}\:{have}\:{same}\:\boldsymbol{{circum}}-\boldsymbol{{radius}}, \\ $$$${the}\:\boldsymbol{{equilateral}}\:\boldsymbol{{triangle}}\:{has} \\ $$$$\boldsymbol{{maximum}}\:\boldsymbol{{area}}. \\ $$ Terms of Service Privacy Policy Contact:…

L-lim-x-0-x-x-

Question Number 5821 by FilupSmith last updated on 30/May/16 $${L}=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:{x}^{{x}} \\ $$ Answered by bahmanfeshki last updated on 27/Feb/17 $$\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\:{e}^{{x}\mathrm{ln}\:{x}} =\underset{{x}\rightarrow\mathrm{0}^{+} }…

Prove-that-among-all-cyclic-n-gons-which-have-same-radius-regular-n-gon-has-maximum-area-

Question Number 5816 by Rasheed Soomro last updated on 29/May/16 $$\mathcal{P}{rove}\:{that}\:{among}\:{all}\:{cyclic}\:\:{n}-{gons},\: \\ $$$${which}\:{have}\:{same}\:{radius},\:{regular}\:{n}-{gon} \\ $$$${has}\:{maximum}\:{area}. \\ $$ Commented by Yozzii last updated on 29/May/16 $${Is}\:{induction}\:{possible}\:{for}\:{n}\geqslant\mathrm{3}?…

Question-136885

Question Number 136885 by BHOOPENDRA last updated on 27/Mar/21 Answered by bramlexs22 last updated on 27/Mar/21 $$\lambda^{\mathrm{3}} −\left(\mathrm{trace}\:\mathrm{A}\right)\lambda^{\mathrm{2}} +\:\begin{pmatrix}{\mathrm{minor}\:\mathrm{of}\:\mathrm{the}\:\mathrm{terms}}\\{\mathrm{on}\:\mathrm{the}\:\mathrm{leading}\:\mathrm{diag}\:\mathrm{A}\:}\end{pmatrix}\lambda−\mathrm{det}\left(\mathrm{A}\right)=\mathrm{0} \\ $$$$\lambda^{\mathrm{3}} −\mathrm{3}\lambda^{\mathrm{2}} +\left(\begin{vmatrix}{\mathrm{1}\:\:\mathrm{2}}\\{\mathrm{2}\:\:\mathrm{1}}\end{vmatrix}+\begin{vmatrix}{\mathrm{1}\:\:\:\mathrm{0}}\\{\mathrm{1}\:\:\:\mathrm{1}}\end{vmatrix}+\begin{vmatrix}{\:\:\mathrm{1}\:\:\:\:\:\mathrm{2}}\\{−\mathrm{1}\:\:\:\mathrm{1}}\end{vmatrix}\right)\lambda−\mathrm{3}\:=\mathrm{0} \\ $$$$\lambda^{\mathrm{3}}…

Given-log-5-7-a-2-log-7-5-a-2-Find-the-value-a-e-1-ln-x-x-x-x-x-dx-

Question Number 136883 by bramlexs22 last updated on 27/Mar/21 $$\mathrm{Given}\:\mathrm{log}\:_{\mathrm{5}} \left(\mathrm{7}^{{a}} −\mathrm{2}\right)=\:\mathrm{log}\:_{\mathrm{7}} \left(\mathrm{5}^{{a}} +\mathrm{2}\right) \\ $$$$.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\int_{{a}} ^{\mathrm{e}} \:\frac{\mathrm{1}+\mathrm{ln}\:\left(\mathrm{x}\right)}{\mathrm{x}^{\mathrm{x}} +\mathrm{x}^{−\mathrm{x}} }\:\mathrm{dx}\:. \\ $$ Answered by Olaf…