Question Number 115403 by EvoneAkashi last updated on 25/Sep/20 $$\int\:{e}^{{x}} \:\frac{\mathrm{1}+{n}\:{x}^{{n}−\mathrm{1}} −{x}^{\mathrm{2}{n}} }{\left(\mathrm{1}−{x}\right)^{{n}} \:\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}{n}} }}\:{dx}\:= \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 115399 by EvoneAkashi last updated on 25/Sep/20 $$\mathrm{The}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{the}\:\mathrm{term}\:\mathrm{independent} \\ $$$$\mathrm{of}\:{x}\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of} \\ $$$$\left(\frac{{x}+\mathrm{1}}{{x}^{\mathrm{2}/\mathrm{3}} −\:{x}^{\mathrm{1}/\mathrm{3}} +\:\mathrm{1}}\:−\:\frac{{x}−\mathrm{1}}{{x}−{x}^{\mathrm{1}/\mathrm{2}} }\right)^{\mathrm{10}} \:\:\mathrm{is} \\ $$ Answered by Dwaipayan Shikari last…
Question Number 49751 by Pk1167156@gmail.com last updated on 10/Dec/18 $$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}}\:+\:\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{3}}\:\:\mathrm{is} \\ $$ Commented by maxmathsup by imad last updated on 10/Dec/18 $${we}\:{have}\:{tan}\left({arctan}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)+{arctan}\left(\frac{\mathrm{1}}{\mathrm{3}}\right)\right)= \\…
Question Number 49692 by Micky24 last updated on 09/Dec/18 $$\mathrm{The}\:\mathrm{vectors}\:\boldsymbol{\mathrm{a}}={x}\boldsymbol{\mathrm{i}}+\left({x}+\mathrm{1}\right)\boldsymbol{\mathrm{j}}+\left({x}+\mathrm{2}\right)\boldsymbol{\mathrm{k}}, \\ $$$$\boldsymbol{\mathrm{b}}=\left({x}+\mathrm{3}\right)\boldsymbol{\mathrm{i}}+\left({x}+\mathrm{4}\right)\boldsymbol{\mathrm{j}}+\left({x}+\mathrm{5}\right)\boldsymbol{\mathrm{k}}\:\:\:\mathrm{and} \\ $$$$\boldsymbol{\mathrm{c}}=\left({x}+\mathrm{6}\right)\boldsymbol{\mathrm{i}}+\left({x}+\mathrm{7}\right)\boldsymbol{\mathrm{j}}+\left({x}+\mathrm{8}\right)\boldsymbol{\mathrm{k}}\:\mathrm{are}\:\mathrm{coplanar} \\ $$$$\mathrm{for} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 09/Dec/18…
Question Number 49464 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{If}\:\:\mathrm{9}\sqrt{{x}}=\sqrt{\mathrm{12}}+\sqrt{\mathrm{147}},\:\mathrm{then}\:\mathrm{the}\:\mathrm{value} \\ $$$$\mathrm{of}\:{x}\:\mathrm{is} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 07/Dec/18 $${pls}\:{activate}\:{your}\:{mind}\:{by}\:{trying}\:{to}\:{solve}\:{problems} \\ $$$${by}\:{yourself}…{later}\:{post}\:{in}\:{forum}\:{if}\:{results}\:{not} \\…
Question Number 49463 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{If}\:\:\:\mathrm{7}^{\mathrm{log}\:_{\mathrm{7}} \left({x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{5}\right)} =\:{x}−\mathrm{1},\:\:{x}\:\mathrm{may}\:\mathrm{have} \\ $$$$\mathrm{values} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 07/Dec/18 $${a}^{{x}}…
Question Number 49462 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{2}\mid{x}\mid^{\mathrm{2}} −\:\mathrm{7}\mid{x}\mid\:+\:\mathrm{6}=\mathrm{0}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 07/Dec/18 $$\mid{x}\mid={x}\:\:{when}\:{x}>\mathrm{0} \\ $$$$\:\:\:\:\:=−{x}\:\:{when}\:{x}<\mathrm{0}…
Question Number 49461 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{solutions}\:\mathrm{for}\:{x}\:\mathrm{from} \\ $$$$\mathrm{the}\:\mathrm{equation}\:{x}^{\mathrm{2}} −\mid{x}\mid−\mathrm{2}=\mathrm{0}\:\:\mathrm{is} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 07/Dec/18 $$\mid{x}\mid={x}\:\:{x}>\mathrm{0} \\ $$$$\:\:\:\:\:=−{x}\:{x}<\mathrm{0}…
Question Number 49460 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{If}\:\:{x}=\mathrm{1}+{i}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$${x}^{\mathrm{3}} −{ix}+\mathrm{1}−{i}=\mathrm{0}\:,\:\mathrm{then}\:\mathrm{the}\:\mathrm{other}\:\mathrm{real} \\ $$$$\mathrm{root}\:\mathrm{is} \\ $$ Commented by Kunal12588 last updated on 07/Dec/18 $${i}\:{do}\:{it}\:{with}\:{normal}\:{real}\:{way}.\:{so}\:{it}…
Question Number 49459 by Pk1167156@gmail.com last updated on 07/Dec/18 $$\mathrm{If}\:\mathrm{tan}\:\theta=\frac{\mathrm{cos}\:\mathrm{9}°+\mathrm{sin}\:\mathrm{9}°}{\mathrm{cos}\:\mathrm{9}°−\mathrm{sin}\:\mathrm{9}°}\:\mathrm{then}\:\theta\:=\:\_\_\_ \\ $$ Answered by math1967 last updated on 07/Dec/18 $${tan}\theta=\frac{{cos}\mathrm{9}+{cos}\left(\mathrm{90}−\mathrm{9}\right)}{{cos}\mathrm{9}−{cos}\left(\mathrm{90}−\mathrm{9}\right)} \\ $$$${tan}\theta=\frac{{cos}\mathrm{9}+{cos}\mathrm{81}}{{cos}\mathrm{9}−{cos}\mathrm{81}} \\ $$$${tan}\theta=\frac{\mathrm{2}{cos}\mathrm{45}.{cos}\mathrm{36}}{\mathrm{2}{sin}\mathrm{45}.{sin}\mathrm{36}} \\…