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Question Number 137973 by mnjuly1970 last updated on 08/Apr/21 $$\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:…….{Advanced}\:…\:…\:…\:…\:{Calculus}……. \\ $$$$\:\:\:\:{prove}\:{that}::: \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left(\mathrm{1}−{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx}=\frac{\pi}{\mathrm{8}}{ln}\left(\mathrm{2}\right)−{G}\:…\checkmark \\ $$$$\:\:\:\:{where}\:\:{G}\:{is}\:{catalan}\:{number}… \\ $$$$\:\:\: \\ $$…
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Question Number 72439 by Maclaurin Stickker last updated on 28/Oct/19 Commented by Maclaurin Stickker last updated on 28/Oct/19 $${Prove}\:{that}\:{the}\:{radius}\:{of}\:{the}\: \\ $$$${circumferences}\:{is}: \\ $$$$\frac{\mathrm{2}}{\mathrm{1}−{cos}\:\mathrm{2}\alpha}\:{and}\:\frac{\mathrm{2}}{\mathrm{1}−{sin}\:\mathrm{2}\alpha}\:. \\ $$$${and}\:{find}\:{tan}\left(\alpha\right)…
Question Number 6902 by Tawakalitu. last updated on 02/Aug/16 $$\mathrm{1}^{\mathrm{6}} \:+\:\mathrm{3}^{\mathrm{6}} \:+\:\mathrm{5}^{\mathrm{6}} \:+\:…\:+\:\left(\mathrm{2}{n}\:−\:\mathrm{1}\right)^{\mathrm{6}} \:\:=\:\:{B} \\ $$$$ \\ $$$${Solve}\:{for}\:{B}. \\ $$ Commented by Yozzii last updated…
Question Number 137969 by rs4089 last updated on 08/Apr/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} \int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }{dx}\:{dy} \\ $$ Answered by EnterUsername last updated on 08/Apr/21…
Question Number 72434 by aliesam last updated on 28/Oct/19 Answered by mind is power last updated on 28/Oct/19 $$\frac{\mathrm{c}}{\mathrm{sin}\left(\mathrm{x}\right)}=\frac{\mathrm{d}}{\mathrm{sin}\left(\mathrm{y}\right)}=\frac{\mathrm{BD}}{\mathrm{sin}\left(\mathrm{40}\right)} \\ $$$$\mathrm{BD}^{\mathrm{2}} =\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} −\mathrm{2abcos}\left(\mathrm{40}\right) \\…
Question Number 72435 by ajfour last updated on 28/Oct/19 Commented by ajfour last updated on 28/Oct/19 $${The}\:{parabolic}\:{surface}\:{is}\:{y}={x}^{\mathrm{2}} . \\ $$$${Find}\:{time}\:{period}\:{of}\:{small}\: \\ $$$${oscillations}\:{of}\:{the}\:{rod}.\: \\ $$$$\left({the}\:{end}\:{wheels}\:{are}\:{small}\right). \\…
Question Number 137971 by EnterUsername last updated on 08/Apr/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\int_{\mathrm{0}} ^{\mathrm{x}} \left(\mathrm{x}−\mathrm{t}\right)\mathrm{t}^{\mathrm{2}} \sqrt[{\mathrm{3}}]{\mathrm{y}\left(\mathrm{t}\right)}\mathrm{dt}+\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}} ^{\mathrm{x}} \left(\mathrm{5x}−\mathrm{6t}\right)\mathrm{y}\left(\mathrm{t}\right)\mathrm{dt}+\mathrm{2x}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 137970 by Dwaipayan Shikari last updated on 08/Apr/21 $${Prove}\:{that}\: \\ $$$$\bigtriangledown^{\mathrm{2}} \boldsymbol{\phi}=−\mathrm{4}\boldsymbol{\pi{G}}\rho\:\: \\ $$$$\phi={Potential}\:{of}\:{Gravitational}\:{field} \\ $$$$\rho={Density}\:\:\:\boldsymbol{{G}}={Universal}\:{Gravitational}\:{Constant} \\ $$ Answered by ajfour last updated…