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Author: Tinku Tara

A-sphere-of-radius-r-contains-a-cube-inside-it-All-the-vertices-of-the-cube-touch-the-surface-of-sphere-What-is-the-volume-of-the-cube-

Question Number 5319 by Rasheed Soomro last updated on 07/May/16 $$\mathrm{A}\:\boldsymbol{\mathrm{sphere}}\:\mathrm{of}\:\mathrm{radius}\:\boldsymbol{\mathrm{r}}\:\mathrm{contains}\:\mathrm{a}\:\boldsymbol{\mathrm{cube}} \\ $$$$\mathrm{inside}\:\mathrm{it}.\:\mathrm{All}\:\mathrm{the}\:\boldsymbol{\mathrm{vertices}}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cube} \\ $$$$\mathrm{touch}\:\mathrm{the}\:\boldsymbol{\mathrm{surface}}\:\mathrm{of}\:\mathrm{sphere}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\boldsymbol{\mathrm{volume}}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cube}? \\ $$ Answered by Rasheed Soomro last updated…

My-mother-is-making-a-game-for-children-that-involves-words-on-cards-e-g-card-one-hase-words-a-and-b-for-whatever-a-and-b-might-be-She-has-a-list-of-20-words-and-she-wants-cards-that-are-t-duplic

Question Number 5315 by FilupSmith last updated on 07/May/16 $$\mathrm{My}\:\mathrm{mother}\:\mathrm{is}\:\mathrm{making}\:\mathrm{a}\:\mathrm{game}\:\mathrm{for}\:\mathrm{children} \\ $$$$\mathrm{that}\:\mathrm{involves}\:\mathrm{words}\:\mathrm{on}\:\mathrm{cards}. \\ $$$$\mathrm{e}.\mathrm{g}.\:\mathrm{card}\:\mathrm{one}\:\mathrm{hase}\:\mathrm{words}\:{a}\:\mathrm{and}\:{b}, \\ $$$$\mathrm{for}\:\mathrm{whatever}\:{a}\:\mathrm{and}\:{b}\:\mathrm{might}\:\mathrm{be}. \\ $$$$ \\ $$$$\mathrm{She}\:\mathrm{has}\:\mathrm{a}\:\mathrm{list}\:\mathrm{of}\:\mathrm{20}\:\mathrm{words}\:\mathrm{and}\:\mathrm{she}\:\mathrm{wants}\:\mathrm{cards} \\ $$$$\mathrm{that}\:\mathrm{are}'\mathrm{t}\:\mathrm{duplicate}.\:\mathrm{That}\:\mathrm{is},\:{a}\:{b}\:\mathrm{and}\:{b}\:{a} \\ $$$$\mathrm{are}\:\mathrm{duplicates}. \\…

Question-5314

Question Number 5314 by sanusihammed last updated on 06/May/16 Commented by prakash jain last updated on 08/May/16 $$\mathrm{R}_{\mathrm{2}} \:\mathrm{and}\:\mathrm{R}_{\mathrm{3}} \:\mathrm{are}\:\mathrm{in}\:\mathrm{parallel},\:\mathrm{so}\:\mathrm{equivalent} \\ $$$$\mathrm{resistance}\:=\frac{\mathrm{R}_{\mathrm{2}} ×\mathrm{R}_{\mathrm{3}} }{\mathrm{R}_{\mathrm{2}} +\mathrm{R}_{\mathrm{3}}…

sdvanced-cslculus-if-x-R-and-x-0-x-e-t-1-t-ln-x-t-dt-then-prove-that-0-e-x-x-dx-2-

Question Number 136381 by mnjuly1970 last updated on 21/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:……{sdvanced}\:\:\:{cslculus}…… \\ $$$$\:{if}\:\:{x}\in\mathbb{R}^{+} \:{and}::\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\phi}\left({x}\right)=\int_{\mathrm{0}} ^{\:{x}} \frac{{e}^{{t}} −\mathrm{1}}{{t}}{ln}\left(\frac{{x}}{{t}}\right){dt} \\ $$$$\:\:{then}\:{prove}\:\:{that}\::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\Psi=\int_{\mathrm{0}} ^{\:\infty} {e}^{−{x}} \boldsymbol{\phi}\left({x}\right){dx}=\zeta\left(\mathrm{2}\right)…

Question-70847

Question Number 70847 by A8;15: last updated on 08/Oct/19 Answered by mind is power last updated on 08/Oct/19 $$\begin{cases}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{2}}\\{\mathrm{2}{x}^{\mathrm{4}} +{xy}^{\mathrm{3}} +{x}^{\mathrm{2}} {y}^{\mathrm{2}} −{x}^{\mathrm{3}}…

Question-136382

Question Number 136382 by ajfour last updated on 21/Mar/21 Commented by ajfour last updated on 21/Mar/21 $${On}\:{a}\:{rough}\:{horizontal},\:{is}\:{placed} \\ $$$${a}\:{fixed}\:{V}\:{rail}\:{with}\:\angle=\alpha. \\ $$$${A}\:{solid}\:{double}\:{cone}\:{object}\:{of} \\ $$$${radius}\:{a}\:{and}\:{length}\:\mathrm{2}{b}\:{is} \\ $$$${now}\:{placed}\:{symmetricaly}\:{over}…

3-points-with-the-restriction-that-they-should-be-non-collinear-determine-circle-What-number-of-points-with-what-restriction-determine-sphere-

Question Number 5308 by Rasheed Soomro last updated on 06/May/16 $$\mathrm{3}\:\mathrm{points}\:\mathrm{with}\:\mathrm{the}\:\mathrm{restriction}\:\mathrm{that} \\ $$$$\mathrm{they}\:\mathrm{should}\:\mathrm{be}\:\mathrm{non}-\mathrm{collinear}\:\mathrm{determine} \\ $$$$\mathrm{circle}. \\ $$$$\mathrm{What}\:\mathrm{number}\:\mathrm{of}\:\mathrm{points}\:\mathrm{with}\:\mathrm{what} \\ $$$$\mathrm{restriction}\:\mathrm{determine}\:\mathrm{sphere}? \\ $$ Terms of Service Privacy…

Question-136377

Question Number 136377 by MJS_new last updated on 21/Mar/21 Commented by MJS_new last updated on 21/Mar/21 $$\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:“\mathrm{square}''\:\mathrm{is}\:\left(\frac{\pi}{\mathrm{3}}+\mathrm{1}−\sqrt{\mathrm{3}}\right){a}^{\mathrm{2}} \:\mathrm{but} \\ $$$$\mathrm{how}\:\mathrm{to}\:\mathrm{get}\:\mathrm{this}\:{without}\:\mathrm{integration}? \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{afraid}\:\mathrm{I}'\mathrm{m}\:\mathrm{a}\:\mathrm{blockhead}… \\ $$ Answered…