Question Number 113841 by deepraj123 last updated on 15/Sep/20 $$\mathrm{In}\:\mathrm{any}\:\bigtriangleup{ABC},\:\:{b}^{\mathrm{2}} \mathrm{sin}\:\mathrm{2}{C}+{c}^{\mathrm{2}} \mathrm{sin}\:\mathrm{2}{B}\:= \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 113824 by deepraj123 last updated on 15/Sep/20 $$\mathrm{If}\:\mathrm{4}\:\mathrm{sin}^{−\mathrm{1}} {x}+\mathrm{cos}^{−\mathrm{1}} {x}=\:\pi,\:\mathrm{then}\:{x}\:\mathrm{equals} \\ $$ Answered by $@y@m last updated on 15/Sep/20 $${Let}\:\mathrm{sin}\:^{−\mathrm{1}} {x}=\alpha\:\Rightarrow\mathrm{sin}\:\alpha={x}\:…\left(\mathrm{1}\right) \\ $$$${Let}\:\mathrm{cos}\:\:^{−\mathrm{1}}…
Question Number 113825 by deepraj123 last updated on 15/Sep/20 $$\mathrm{The}\:\mathrm{greatest}\:\mathrm{and}\:\mathrm{least}\:\mathrm{values}\:\mathrm{of} \\ $$$$\left(\mathrm{sin}^{−\mathrm{1}} {x}\right)^{\mathrm{3}} +\:\left(\mathrm{cos}^{−\mathrm{1}} {x}\right)^{\mathrm{3}} \:\:\mathrm{are} \\ $$ Answered by MJS_new last updated on 15/Sep/20…
Question Number 113822 by deepraj123 last updated on 15/Sep/20 $$\mathrm{If}\:\:\mathrm{in}\:\mathrm{a}\:\bigtriangleup{ABC},\:\mathrm{3}{a}={b}+{c},\:\mathrm{then}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\:\mathrm{cot}\:\frac{{B}}{\mathrm{2}}\:\mathrm{cot}\:\frac{{B}}{\mathrm{2}}\:\mathrm{is} \\ $$ Answered by $@y@m last updated on 15/Sep/20 $$\mathrm{cot}\:^{\mathrm{2}} \frac{{B}}{\mathrm{2}}=\frac{{s}\left({s}−{b}\right)}{\left({s}−{a}\right)\left({s}−{c}\right)}\:\: {Formula} \\…
Question Number 113823 by deepraj123 last updated on 15/Sep/20 $$\mathrm{A}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{1}+{x}\right)+\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{1}−{x}\right)\:=\:\frac{\pi}{\mathrm{2}}\:\:\mathrm{is} \\ $$ Answered by MJS_new last updated on 15/Sep/20 $${x}=\mathrm{0}\:\mathrm{because}\:\mathrm{arctan}\:\mathrm{1}\:=\frac{\pi}{\mathrm{4}} \\…
Question Number 113808 by deepraj123 last updated on 15/Sep/20 $$\mathrm{In}\:\mathrm{a}\:\bigtriangleup{ABC}\:,\:\angle{B}=\frac{\pi}{\mathrm{3}}\:\mathrm{and}\:\angle{C}=\frac{\pi}{\mathrm{4}}.\:\mathrm{Let} \\ $$$${D}\:\mathrm{divide}\:{BC}\:\mathrm{internally}\:\mathrm{in}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{1}\::\:\mathrm{3}.\:\mathrm{Then}\:\frac{\mathrm{sin}\:\angle{BAD}}{\mathrm{sin}\:\angle{CAD}}\:\mathrm{equals} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 113807 by deepraj123 last updated on 15/Sep/20 $$\mathrm{In}\:\mathrm{any}\:\bigtriangleup{ABC},\:\mathrm{if}\:\mathrm{the}\:\mathrm{angles}\:\mathrm{are}\:\mathrm{in}\: \\ $$$$\mathrm{the}\:\mathrm{ratio}\:\mathrm{1}\::\:\mathrm{2}\::\:\mathrm{3},\:\mathrm{then}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{corresponding}\:\mathrm{sides}\:\mathrm{is} \\ $$ Answered by bemath last updated on 15/Sep/20 $$\angle{A}\:=\:{k}\:,\angle{B}=\mathrm{2}{k}\:,\angle{C}=\mathrm{3}{k} \\…
Question Number 48105 by lhfgfgjokf last updated on 19/Nov/18 $$\underset{−\mathrm{1}} {\overset{\mathrm{1}} {\int}}\:\left(\sqrt{\mathrm{1}+{x}+{x}^{\mathrm{2}} }−\:\sqrt{\mathrm{1}−{x}−{x}^{\mathrm{2}} }\:\right){dx}\:= \\ $$ Commented by maxmathsup by imad last updated on 19/Nov/18…
Question Number 113557 by Aina Samuel Temidayo last updated on 14/Sep/20 $$\mathrm{If}\:\mathrm{the}\:\mathrm{numerically}\:\mathrm{smaller}\:\mathrm{root}\:\mathrm{of}\: \\ $$$${x}^{\mathrm{2}} +{mx}=\mathrm{2}\:\mathrm{is}\:\mathrm{more}\:\mathrm{than}\:\mathrm{the}\:\mathrm{other}\:\mathrm{one}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{m}. \\ $$ Answered by mr W last updated…
Question Number 47874 by regineregencia last updated on 16/Nov/18 $$\mathrm{An}\:\mathrm{elevator}\:\mathrm{starts}\:\mathrm{with}\:{m}\:\mathrm{passengers} \\ $$$$\mathrm{and}\:\mathrm{stops}\:\mathrm{at}\:{n}\:\mathrm{floors}\:\left({m}\leqslant{n}\right).\:\mathrm{The}\: \\ $$$$\mathrm{probability}\:\mathrm{that}\:\mathrm{no}\:\mathrm{passengers}\:\mathrm{alight} \\ $$$$\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{floor}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com