Question Number 47727 by Mawitea Cck last updated on 14/Nov/18 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:{a}\:\mathrm{for} \\ $$$$\:\:\:\:\:{a}\::\:\mathrm{4}\::\::\:\mathrm{5}\::\:\mathrm{10} \\ $$ Answered by ajfour last updated on 14/Nov/18 $$\Rightarrow\:\frac{{a}}{\mathrm{4}}\:=\:\frac{\mathrm{5}}{\mathrm{10}}\:\:\:\:\:\Rightarrow\:\:\frac{{a}/\mathrm{4}}{\mathrm{1}}=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\:\:\:\frac{{a}}{\mathrm{4}}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\Rightarrow\:\:{a}=\frac{\mathrm{4}}{\mathrm{2}}\:=\:\mathrm{2}\:.…
Question Number 47593 by shivshant0409 last updated on 12/Nov/18 $$\mathrm{Which}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{statements}\: \\ $$$$\mathrm{are}/\mathrm{is}\:\mathrm{true}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 47581 by EagleEye1 last updated on 11/Nov/18 $$\mathrm{The}\:\mathrm{root}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\: \\ $$$$\frac{\mathrm{2}}{{x}−\mathrm{1}}\:+\:\frac{\mathrm{1}}{{x}+\mathrm{2}}\:+\:\frac{\mathrm{3}{x}\left({x}+\mathrm{1}\right)}{\left({x}−\mathrm{1}\right)\left({x}+\mathrm{2}\right)}\:=\:\mathrm{0}\:\: \\ $$$$\mathrm{among}\:\mathrm{the}\:\mathrm{following}\:\mathrm{is} \\ $$ Commented by maxmathsup by imad last updated on 12/Nov/18…
Question Number 47481 by limite last updated on 10/Nov/18 $$\mathrm{Three}\:\mathrm{six}−\mathrm{faced}\:\mathrm{dice}\:\mathrm{are}\:\mathrm{thrown} \\ $$$$\mathrm{together}.\:\mathrm{The}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}\:\mathrm{appearing}\:\mathrm{on}\:\mathrm{the}\:\mathrm{dice} \\ $$$$\mathrm{is}\:\:{k}\:\left(\mathrm{3}\leqslant\:{k}\:\leqslant\:\mathrm{8}\right)\:\mathrm{is} \\ $$ Answered by ajfour last updated on 10/Nov/18…
Question Number 47301 by myear last updated on 08/Nov/18 $$\mathrm{If}\:\mathrm{the}\:\mathrm{equation}\:{x}^{\mathrm{2}} +{px}+{q}\:=\mathrm{0}\:\mathrm{has}\:\mathrm{roots} \\ $$$${a}\:\mathrm{and}\:{b}\:\mathrm{where}\:{p},\:{q}\:\mathrm{are}\:\mathrm{non}−\mathrm{zero}\: \\ $$$$\mathrm{constants}.\:\mathrm{Then} \\ $$ Answered by Kunal12588 last updated on 08/Nov/18 $$\left({x}−{a}\right)\left({x}−{b}\right)={x}^{\mathrm{2}}…
Question Number 46925 by 786786AM last updated on 02/Nov/18 $$\mathrm{The}\:\mathrm{third}\:\mathrm{term}\:\mathrm{of}\:\mathrm{a}\:\mathrm{GP}\:\mathrm{is}\:\mathrm{4}.\:\mathrm{The}\:\mathrm{product} \\ $$$$\mathrm{of}\:\mathrm{first}\:\mathrm{five}\:\mathrm{terms}\:\mathrm{is} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 02/Nov/18 $$\frac{{a}}{{r}},{a},{ar},{ar}^{\mathrm{2}} ,{ar}^{\mathrm{3}} \\ $$$${given}\:\:{ar}=\mathrm{4}…
Question Number 46924 by 786786AM last updated on 02/Nov/18 $$\mathrm{If}\:\:\frac{{a}−{x}}{{px}}\:=\:\frac{{a}−{y}}{{qy}}\:=\:\frac{{a}−{z}}{{rz}}\:\mathrm{and}\:{p},\:{q},\:{r}\:\:\mathrm{are} \\ $$$$\mathrm{in}\:\mathrm{AP},\:\mathrm{then}\:{x},\:{y},\:{z}\:\:\mathrm{will}\:\mathrm{be}\:\mathrm{in} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 02/Nov/18 $$\frac{{a}−{x}}{{px}}=\frac{{a}−{y}}{{qy}}=\frac{{a}−{z}}{{rz}}=\frac{\mathrm{1}}{{k}}\left({say}\right) \\ $$$${px}={k}\left({a}−{x}\right) \\…
Question Number 46923 by 786786AM last updated on 02/Nov/18 $${a},\:{b},\:{c}\:\mathrm{are}\:\mathrm{in}\:\mathrm{AP}\:\mathrm{or}\:\mathrm{GP}\:\mathrm{or}\:\mathrm{HP}\:\mathrm{according} \\ $$$$\mathrm{as}\:\frac{{a}−{b}}{{b}−{c}}\:\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 02/Nov/18 $$ \\ $$$$\left.\mathrm{1}\right)\:{when}\:{a},{b},{c}\:{are}\:{in}\:{A}.{P} \\…
Question Number 46922 by 786786AM last updated on 02/Nov/18 $$\mathrm{Thr}\:\mathrm{6th}\:\mathrm{term}\:\mathrm{of}\:\mathrm{an}\:\mathrm{AP}\:\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{2},\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{common}\:\mathrm{difference}\:\mathrm{of}\:\mathrm{the}\:\mathrm{AP}. \\ $$$$\mathrm{Which}\:\mathrm{makes}\:\mathrm{the}\:\mathrm{product}\:{a}_{\mathrm{1}} \:{a}_{\mathrm{4}} \:{a}_{\mathrm{5}} \:\mathrm{least} \\ $$$$\mathrm{is}\:\mathrm{given}\:\:\mathrm{by} \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 46921 by 786786AM last updated on 02/Nov/18 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{first}\:\mathrm{two}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{an}\:\mathrm{infinite} \\ $$$$\mathrm{GP}\:\mathrm{is}\:\mathrm{1}\:\mathrm{and}\:\mathrm{every}\:\mathrm{term}\:\mathrm{is}\:\mathrm{twice}\:\mathrm{the}\:\mathrm{sum} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{successive}\:\mathrm{terms}.\:\mathrm{Its}\:\mathrm{first}\:\mathrm{term}\:\mathrm{is} \\ $$ Answered by peter frank last updated on 02/Nov/18 $$\mathrm{a}+\mathrm{ar}=\mathrm{1}…..\left(\mathrm{1}\right)…