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Author: Tinku Tara

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Question Number 5466 by 3 last updated on 15/May/16 $$\sqrt{\mathrm{8}} \\ $$ Answered by FilupSmith last updated on 15/May/16 $$\sqrt{\mathrm{8}}=\sqrt{\mathrm{4}×\mathrm{2}} \\ $$$$=\sqrt{\mathrm{4}}\sqrt{\mathrm{2}} \\ $$$$\therefore\sqrt{\mathrm{8}}=\mathrm{2}\sqrt{\mathrm{2}} \\…

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Where-f-x-4x-2-1-2x-1-defined-in-R-1-2-determine-lim-x-1-2-f-x-

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Question Number 71000 by Maclaurin Stickker last updated on 10/Oct/19 $${Where}\:{f}\left({x}\right)=\frac{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{x}−\mathrm{1}}\:{defined}\:{in}\: \\ $$$$\mathbb{R}−\left\{\frac{\mathrm{1}}{\mathrm{2}}\right\},\:{determine}\:\underset{{x}\rightarrow\frac{\mathrm{1}}{\mathrm{2}}} {\mathrm{lim}}{f}\left({x}\right). \\ $$ Commented by mathmax by abdo last updated on…

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Question-70996

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Question Number 70996 by A8;15: last updated on 10/Oct/19 Commented by mathmax by abdo last updated on 10/Oct/19 $${let}\:{take}\:{a}\:{try}\:\left({e}\right)\:\Rightarrow\sqrt{{x}^{\mathrm{3}} +\mathrm{24}}−\sqrt{{x}^{\mathrm{3}} \:+\mathrm{12}}=\mathrm{3}{x}+\mathrm{8}\:\Rightarrow \\ $$$$\left(\sqrt{{x}^{\mathrm{3}} +\mathrm{24}}−\sqrt{{x}^{\mathrm{3}} +\mathrm{12}}\right)^{\mathrm{2}}…

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Question-70997

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Question Number 70997 by A8;15: last updated on 10/Oct/19 Answered by MJS last updated on 10/Oct/19 $$\mathrm{trying}\:\mathrm{first} \\ $$$$\mathrm{for}\:\mathrm{an}\:\mathrm{easy}\:\mathrm{solution}\:\mathrm{both}\:{a}+\mathrm{24}\:\mathrm{and}\:{a}+\mathrm{12} \\ $$$$\mathrm{must}\:\mathrm{be}\:\mathrm{square}\:\mathrm{numbers} \\ $$$$\Rightarrow\:{a}=−\mathrm{8}\:\Rightarrow\:{x}=−\mathrm{2} \\ $$…

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