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Author: Tinku Tara

Verify-that-the-following-functions-satisfies-the-mean-value-theorem-1-f-x-x-x-2-x-at-2-1-2-f-x-x-3-4x-2-2x-4-at-2-2-

Question Number 135929 by Engr_Jidda last updated on 17/Mar/21 $${Verify}\:{that}\:{the}\:{following}\:{functions}\:{satisfies} \\ $$$${the}\:{mean}\:{value}\:{theorem}. \\ $$$$\left(\mathrm{1}\right)\:\:\:{f}\left({x}\right)\:=\frac{{x}}{{x}^{\mathrm{2}} −{x}}\:\:\:{at}\:\left[−\mathrm{2},−\mathrm{1}\right] \\ $$$$\left(\mathrm{2}\right)\:\:{f}\left({x}\right)={x}^{\mathrm{3}} −\mathrm{4}{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{4}\:\:\:{at}\left[−\mathrm{2},\mathrm{2}\right] \\ $$ Terms of Service Privacy…

montrer-que-sinA-sinB-sinC-4cos-A-2-cos-B-2-cos-C-2-

Question Number 70394 by Cmr 237 last updated on 04/Oct/19 $$\mathrm{montrer}\:\mathrm{que} \\ $$$$\mathrm{sinA}+\mathrm{sinB}+\mathrm{sinC}=\mathrm{4cos}\frac{\mathrm{A}}{\mathrm{2}}\mathrm{cos}\frac{\mathrm{B}}{\mathrm{2}}\mathrm{cos}\frac{\mathrm{C}}{\mathrm{2}} \\ $$ Answered by $@ty@m123 last updated on 05/Oct/19 $${LHS}=\mathrm{2sin}\:\frac{{A}+{B}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{sin}\:{C} \\ $$$$=\mathrm{2sin}\:\frac{\pi−{C}}{\mathrm{2}}\mathrm{cos}\:\frac{{A}−{B}}{\mathrm{2}}+\mathrm{sin}\:{C}…

find-the-volume-of-the-solid-on-the-closed-region-0-x-1-and-0-y-1-under-the-surface-Z-5-x-2y-

Question Number 135931 by Engr_Jidda last updated on 17/Mar/21 $${find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{on}\:{the}\:{closed} \\ $$$${region}\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1}\:{and}\:\mathrm{0}\leqslant{y}\leqslant\mathrm{1}\:{under}\:{the} \\ $$$${surface}\:{Z}=\mathrm{5}−{x}−\mathrm{2}{y} \\ $$ Answered by dhgt last updated on 04/May/21 Terms of…

Given-that-f-x-3x-2-and-g-x-x-x-1-find-the-domain-and-range-of-the-following-1-f-1-g-g-1-f-2-f-g-x-1-

Question Number 135930 by Engr_Jidda last updated on 17/Mar/21 $${Given}\:{that}\:{f}\left({x}\right)=\:\mathrm{3}{x}−\mathrm{2}\:{and}\:{g}\left({x}\right)=\frac{{x}}{{x}−\mathrm{1}} \\ $$$${find}\:{the}\:{domain}\:{and}\:{range}\:{of}\:{the}\:{following}. \\ $$$$\left(\mathrm{1}\right)\:{f}^{−\mathrm{1}} \bullet{g}\bullet{g}^{−\mathrm{1}} \bullet{f}\:\:\:\:\:\left(\mathrm{2}\right)\:\left[{f}\left({g}\left({x}\right)\right)\right]^{−\mathrm{1}} \\ $$ Answered by dhgt last updated on 04/May/21…

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Question Number 4855 by Tinku Tara last updated on 18/Mar/16 $$\mathrm{We}\:\mathrm{have}\:\mathrm{released}\:\mathrm{an}\:\mathrm{update}\:\mathrm{with}\:\mathrm{following} \\ $$$$\mathrm{enhancements}: \\ $$$$\bullet\:\mathrm{A}\:\mathrm{new}\:\mathrm{section}\:\mathrm{quizzes}\:\mathrm{is}\:\mathrm{added}.\: \\ $$$$\:\:\:\:\mathrm{You}\:\mathrm{can}\:\mathrm{also}\:\mathrm{request}\:\mathrm{a}\:\mathrm{solution}\:\mathrm{for}\:\mathrm{quiz} \\ $$$$\:\:\:\:\mathrm{question}\:\mathrm{and}\:\mathrm{we}\:\mathrm{will}\:\mathrm{provide}\:\mathrm{a}\:\mathrm{solution}. \\ $$$$\:\:\:\:\mathrm{In}\:\mathrm{case}\:\mathrm{you}\:\mathrm{want}\:\mathrm{to}\:\mathrm{start}\:\mathrm{a}\:\mathrm{discussion}\:\mathrm{you} \\ $$$$\:\:\:\:\mathrm{can}\:\mathrm{post}\:\mathrm{the}\:\mathrm{same}\:\mathrm{question}\:\mathrm{to}\:\mathrm{forum}\:\mathrm{directly} \\ $$$$\:\:\:\:\mathrm{from}\:\mathrm{quiz}.…