Question Number 6373 by sanusihammed last updated on 25/Jun/16 $${If}\:\:\:\:\mathrm{9}{log}_{{a}} ^{\mathrm{5}} \:\:=\:\:{log}_{\mathrm{5}} ^{{a}} \\ $$$${find}\:{the}\:{value}\:{of}\:{a}\: \\ $$$$\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{SOLUTION} \\ $$$$ \\ $$$$\mathrm{9}{log}_{{a}} ^{\mathrm{5}} \:\:=\:\:{log}_{\mathrm{5}}…
Question Number 6370 by sanusihammed last updated on 25/Jun/16 $${If}\:\:{x}\:=\:\frac{\mathrm{3}{sin}\theta}{\:\sqrt{{x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:}}\:\:\:{and}\:\:{y}\:=\:\mathrm{4}{cos}\theta \\ $$$${find}\:\:{cos}\theta \\ $$ Commented by nburiburu last updated on 25/Jun/16 $${cos}\theta={y}/\mathrm{4}\:{with}\:\mathrm{16}{x}^{\mathrm{2}} \left({x}^{\mathrm{2}}…
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Question Number 137437 by I want to learn more last updated on 02/Apr/21 Answered by mr W last updated on 02/Apr/21 $$\frac{{r}−\mathrm{2}}{{r}+\mathrm{2}}=\frac{\mathrm{6}−{r}}{\mathrm{6}+{r}} \\ $$$${r}^{\mathrm{2}} =\mathrm{12}…
Question Number 71903 by naka3546 last updated on 21/Oct/19 $${ax}\:+\:{by}\:\:=\:\:\mathrm{3} \\ $$$${ax}^{\mathrm{2}} \:+\:{by}^{\mathrm{2}} \:\:=\:\:\mathrm{7} \\ $$$${ax}^{\mathrm{3}} \:+\:{by}^{\mathrm{3}} \:\:=\:\:\mathrm{16} \\ $$$${ax}^{\mathrm{4}} \:+\:{by}^{\mathrm{4}} \:\:=\:\:\mathrm{42} \\ $$$${ax}^{\mathrm{5}} \:+\:{by}^{\mathrm{5}}…
Question Number 137439 by mnjuly1970 last updated on 02/Apr/21 $$\:\:\:\:\:\:\:\:\:\:\:\:……{nice}\:\:{calculus}….. \\ $$$$\:\:\:\:{prove}\:{that}:: \\ $$$$\:\:\:\:\:\:\boldsymbol{\chi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{{ln}\left({x}+\sqrt{\mathrm{1}−{x}^{\mathrm{2}} \:}\:\right)}{{x}}{dx}=\frac{\pi^{\mathrm{2}} }{\mathrm{16}}\:…. \\ $$ Answered by mindispower last updated…
Question Number 137435 by SLVR last updated on 02/Apr/21 Commented by SLVR last updated on 02/Apr/21 $${please}\:{help}\:{me}…. \\ $$ Commented by SLVR last updated on…
Question Number 137429 by physicstutes last updated on 02/Apr/21 $$\mathrm{A}\:\mathrm{nuclide}\:_{\mathrm{81}} ^{\mathrm{210}} {X}\:\mathrm{decays}\:\mathrm{to}\:\mathrm{another}\:\mathrm{nuclide}\:_{\mathrm{80}} ^{{A}} {Y}\:\mathrm{in}\: \\ $$$$\mathrm{four}\:\mathrm{successive}\:\mathrm{radioactive}\:\mathrm{decays}.\:\mathrm{Each}\:\mathrm{decay} \\ $$$$\mathrm{involves}\:\mathrm{the}\:\mathrm{emmision}\:\mathrm{of}\:\mathrm{either}\:\mathrm{an}\:\mathrm{alpha}\:\mathrm{particle} \\ $$$$\mathrm{or}\:\mathrm{a}\:\mathrm{beta}\:\mathrm{particle}.\:\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:{A}\:\mathrm{is}: \\ $$$$\mathrm{A}.\:\mathrm{120}\:\:\:\:\:\:\:\:\:\:\:\mathrm{B}.\:\mathrm{206} \\ $$$$\mathrm{C}.\:\mathrm{208}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{D}.\:\mathrm{212} \\…
Question Number 71894 by 20190927 last updated on 21/Oct/19 $$\underset{{x}\rightarrow\frac{\pi}{\mathrm{2}}} {\mathrm{lim}}\left(\mathrm{sin}\:\mathrm{x}\right)^{\mathrm{tanx}} \\ $$ Commented by kaivan.ahmadi last updated on 21/Oct/19 $$={e}^{{lim}_{{x}\rightarrow\frac{\pi}{\mathrm{2}}} \left({sinx}−\mathrm{1}\right){tanx}} ={e}^{{lim}_{{x}\rightarrow\frac{\pi}{\mathrm{2}}} \frac{{sinx}−\mathrm{1}}{{cotx}}} =\:\:…
Question Number 6354 by sanusihammed last updated on 24/Jun/16 $${i}\:=\:{n}−\mathrm{1} \\ $$$$\Sigma\:\:\mathrm{3}{i}\:\:\:\:\:=\:\:\:\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{3}^{{n}} \:−\:\mathrm{1}\right) \\ $$$${i}\:=\:\mathrm{0} \\ $$ Commented by nburiburu last updated on 24/Jun/16 $${doesn}'{t}\:{seem}\:{well}\:{writen}:…