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Question-135868

Question Number 135868 by liberty last updated on 16/Mar/21 Answered by EDWIN88 last updated on 16/Mar/21 $$\mathrm{we}\:\mathrm{know}\:\mathrm{that}\:−\mathrm{1}\leqslant\mathrm{cos}\:\mathrm{x}\leqslant\mathrm{1}\:\mathrm{for}\:\mathrm{x}\:\mathrm{in}\:\mathrm{the}\:\mathrm{interval} \\ $$$$\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{2}\pi\:;\:\mathrm{so}\:\mathrm{we}\:\mathrm{find}\:\mathrm{cos}\:\mathrm{x}\:=\:\frac{−\mathrm{x}^{\mathrm{3}} −\mathrm{2x}^{\mathrm{2}} −\mathrm{5x}}{\mathrm{2}} \\ $$$$\mathrm{then}\:−\mathrm{2}\leqslant−\mathrm{x}^{\mathrm{3}} −\mathrm{2x}^{\mathrm{2}} −\mathrm{5x}\leqslant\mathrm{2}\:\mathrm{or}\:…

Function-is-a-b-a-b-AB-a-b-4-b-4-4-b-b-a-1-a-1-2-b-2-a-3-Function-is-a-b-sin-a-b-a-b-sin-a-b-a-b-1-b-5-a-4-9-a-b-9-b-a-Funcion-is-sin-a-sin-b-sin-1-a-sin-1-b-a-b-sin-a-sin-b-

Question Number 4790 by Dnilka228 last updated on 10/Mar/16 $${Function}\:\Gamma\:{is}\:{a}+{b} \\ $$$${a}+{b}={AB} \\ $$$${a}\neq{b}−\mathrm{4} \\ $$$${b}−\mathrm{4}=\mathrm{4}+{b} \\ $$$${b}={a}−\mathrm{1} \\ $$$${a}−\mathrm{1}=\mathrm{2} \\ $$$${b}=\mathrm{2} \\ $$$${a}=\mathrm{3} \\…

cos-cos-cos-cos-1-cos-1-sin-a-b-sin-a-sin-b-sin-1-a-sin-1-b-a-b-tan-a-a-b-k-tan-a-b-k-tan-1-a-b-k-

Question Number 4783 by Dnilka228 last updated on 10/Mar/16 $$\mathrm{cos}\:\alpha+\beta\:\approx\left(\frac{\mathrm{cos}\:\alpha+\mathrm{cos}\:\beta}{\mathrm{cos}^{−\mathrm{1}} \alpha+\mathrm{cos}^{−\mathrm{1}} \beta}\right)^{\alpha+\beta} \\ $$$$\mathrm{sin}\:{a}+{b}\approx\left(\frac{\mathrm{sin}\:{a}+\mathrm{sin}\:{b}}{\mathrm{sin}^{−\mathrm{1}} {a}+\mathrm{sin}^{−\mathrm{1}} {b}}\right)^{{a}+{b}} \\ $$$$\mathrm{tan}\:\left({a}+\frac{{a}}{{b}}\right)^{{k}} \approx\left(\frac{\mathrm{tan}\:\left({a}+{b}\right)×{k}}{\mathrm{tan}^{−\mathrm{1}} \left({a}+{b}\right)×{k}}\right) \\ $$ Commented by Dnilka228…

What-are-the-possible-value-of-cos-sin-if-sin-cos-1-2-

Question Number 135855 by liberty last updated on 16/Mar/21 $${What}\:{are}\:{the}\:{possible}\:{value}\:{of} \\ $$$$\mathrm{cos}\:\alpha×\mathrm{sin}\:\beta\:\:{if}\:\mathrm{sin}\:\alpha×\mathrm{cos}\:\beta=−\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by EDWIN88 last updated on 16/Mar/21 $$\mathrm{We}\:\mathrm{have}\:−\mathrm{1}\leqslant\mathrm{sin}\:\left(\alpha+\beta\right)\leqslant\mathrm{1}\:\mathrm{and}\:−\mathrm{1}\leqslant\mathrm{sin}\:\left(\alpha−\beta\right)\leqslant\mathrm{1} \\ $$$$\mathrm{now}\:\mathrm{from}\:−\mathrm{1}\leqslant\mathrm{sin}\:\left(\alpha+\beta\right)\leqslant\mathrm{1}\:\mathrm{we}\:\mathrm{get}\: \\…