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Author: Tinku Tara

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Question Number 70021 by naka3546 last updated on 30/Sep/19 $$\sqrt[{\mathrm{3}}]{\sqrt{\sqrt{\mathrm{12345689654321233}\:+\:\mathrm{5333334096}\:\sqrt{\mathrm{12345679}}}}\:−\:\sqrt{\sqrt{\mathrm{12345689654321233}\:−\:\mathrm{5333334096}\:\sqrt{\mathrm{12345679}}}}}\:\:=\:\:… \\ $$ Commented by MJS last updated on 30/Sep/19 $$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{we}\:\mathrm{can}\:\mathrm{solve} \\ $$$$\sqrt{{a}+{b}\sqrt{{c}}}={p}+{q}\sqrt{{c}}\:\Leftrightarrow\:{a}={p}^{\mathrm{2}} +{cq}^{\mathrm{2}} \wedge{b}=\mathrm{2}{pq} \\…

Solution-log-8-x-log-4-x-log-2-x-11-1-log-x-8-1-log-x-4-1-log-x-2-11-1-log-x-2-3-1-log-x-2-2-1-log-x-2-11-1-3log-x-2-1-2log-x-2-1-log-x-2-11-1-3-1-2-1-

Question Number 70017 by Shamim last updated on 30/Sep/19 $$\mathrm{Solution}- \\ $$$$\mathrm{log}_{\mathrm{8}} \mathrm{x}+\mathrm{log}_{\mathrm{4}} \mathrm{x}+\mathrm{log}_{\mathrm{2}} \mathrm{x}=\mathrm{11} \\ $$$$\Rightarrow\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{x}} \mathrm{8}}+\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{x}} \mathrm{4}}+\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{x}} \mathrm{2}}=\mathrm{11} \\ $$$$\Rightarrow\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{x}} \mathrm{2}^{\mathrm{3}} }+\frac{\mathrm{1}}{\mathrm{log}_{\mathrm{x}} \mathrm{2}^{\mathrm{2}}…

Question-135544

Question Number 135544 by 0731619177 last updated on 13/Mar/21 Answered by Olaf last updated on 13/Mar/21 $${f}\left({x}\right)\:=\:\mathrm{sin}{x}+\mathrm{cos}{x}\:=\:\sqrt{\mathrm{2}}\mathrm{cos}\left(\frac{\pi}{\mathrm{4}}−{x}\right) \\ $$$${x}\in\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right]\:\Rightarrow\:{f}\left({x}\right)\in\left[\mathrm{1},\sqrt{\mathrm{2}}\right] \\ $$$$\Rightarrow\:\forall{x}\in\left[\mathrm{0},\frac{\pi}{\mathrm{4}}\right]\:\lfloor{f}\left({x}\right)\rfloor\:=\:\mathrm{1} \\ $$$$\Omega\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{cos}\left(\mathrm{2}{x}\right)×\mathrm{2}^{\mathrm{1}}…

Question-135540

Question Number 135540 by mohammad17 last updated on 13/Mar/21 Answered by Olaf last updated on 13/Mar/21 $$\left.\mathrm{Q1a}\right) \\ $$$$\mathrm{1}/\:\:\:\mathrm{S}_{{n}} \:=\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\left[\frac{\mathrm{1}}{\mathrm{5}^{{k}} }−\frac{\mathrm{1}}{{k}\left({k}+\mathrm{1}\right)}\right] \\ $$$$\mathrm{S}_{{n}}…

Question-135543

Question Number 135543 by 0731619177 last updated on 13/Mar/21 Answered by Olaf last updated on 13/Mar/21 $$\Omega\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{cos}\left(\mathrm{2}{x}\right)\mathrm{tan}\left(\frac{{x}}{\mathrm{2}}\right){dx} \\ $$$$\Omega\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \frac{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} {x}}{\mathrm{1}+\mathrm{tan}^{\mathrm{2}} {x}}\mathrm{tan}\left(\frac{{x}}{\mathrm{2}}\right){dx}…