Question Number 70617 by Rio Michael last updated on 06/Oct/19 $${given}\:{that}\:\:\alpha\:{and}\:\beta\:{are}\:{roots}\:{of}\:{the}\:{equation}\:{x}^{\mathrm{2}} −\mathrm{5}{x}\:+\:\mathrm{4}\:=\mathrm{0}\: \\ $$$$\alpha>\mathrm{0}\:{and}\:\beta\:>\mathrm{0} \\ $$$${find}\:{an}\:{equation}\:{whose}\:{roots}\:{are}\:\sqrt{\alpha}\:{and}\:\sqrt{\beta}\: \\ $$$$ \\ $$$${how}\:{do}\:{i}\:{find}\:\:\sqrt{\alpha\:}\:+\:\sqrt{\beta}\: \\ $$ Answered by mr…
Question Number 5080 by FilupSmith last updated on 10/Apr/16 $$\boldsymbol{{N}}\:=\:\left\{\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:…\right\} \\ $$$$\mid\boldsymbol{{N}}\mid\:=\:\aleph_{\mathrm{0}} \\ $$$$ \\ $$$$\mathrm{I}\:\mathrm{know}\:\mathrm{that}: \\ $$$$\mathrm{if}\:\:\boldsymbol{{S}}\:=\:\left\{{k},\:\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:…\right\} \\ $$$$\therefore\:\mid\boldsymbol{{S}}\mid\:=\:\mid\boldsymbol{{N}}\mid\:=\:\aleph_{\mathrm{0}} \\ $$$$\mathrm{Because}\:\mathrm{you}\:\mathrm{can}\:\mathrm{forever}\:\mathrm{pair}\:\mathrm{one}\:\mathrm{value} \\ $$$$\mathrm{from}\:\mathrm{one}\:\mathrm{set}\:\mathrm{to}\:\mathrm{another}. \\…
Question Number 136151 by bramlexs22 last updated on 19/Mar/21 $${If}\:{A}\:{and}\:{B}\:{toss}\:{n}+\mathrm{1}\:{and}\:{n}\:{fairs} \\ $$$${coins}\:{respectively},\:{what}\:{is}\:{the} \\ $$$${probability}\:{P}_{{n}} \:{that}\:{A}\:{gets}\:{more} \\ $$$${heads}\:{than}\:{B} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 136137 by BHOOPENDRA last updated on 19/Mar/21 Answered by mr W last updated on 19/Mar/21 Commented by mr W last updated on 19/Mar/21…
Question Number 70602 by oyemi kemewari last updated on 06/Oct/19 $$\mathrm{I}=\int_{\mathrm{0}} ^{\infty} \mathrm{ln}\left(\sqrt{\mathrm{1}−\mathrm{x}}\:+\sqrt{\mathrm{1}+\mathrm{x}}\right)\mathrm{dx} \\ $$ Commented by mathmax by abdo last updated on 06/Oct/19 $${error}\:{in}\:{the}\:{question}\:{the}\:{function}\:{x}\rightarrow\sqrt{\mathrm{1}−{x}}+\sqrt{\mathrm{1}+{x}}\:{is}\:{defined}\:{on}…
Question Number 136136 by BHOOPENDRA last updated on 19/Mar/21 Answered by mr W last updated on 19/Mar/21 $${a}=\frac{{F}}{{m}}=\frac{\mathrm{150}}{\mathrm{10}}=\mathrm{15}\:{m}/{s}^{\mathrm{2}} \\ $$$${at}\:{t}=\mathrm{12}\:{s}: \\ $$$${v}={at}=\mathrm{15}×\mathrm{12}=\mathrm{180}\:{m}/{s} \\ $$$${s}=\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{15}×\mathrm{12}^{\mathrm{2}}…
Question Number 5065 by gourav~ last updated on 07/Apr/16 $$\int\sqrt{\mathrm{16}{x}^{\mathrm{2}} +\mathrm{25}}\:\:{dx}\:=? \\ $$ Answered by Yozzii last updated on 08/Apr/16 $${Let}\:{x}=\frac{\mathrm{5}}{\mathrm{4}}{sinh}\theta\Rightarrow{dx}=\frac{\mathrm{5}}{\mathrm{4}}{cosh}\theta{d}\theta \\ $$$$\sqrt{\mathrm{16}{x}^{\mathrm{2}} +\mathrm{25}}=\sqrt{\mathrm{16}×\frac{\mathrm{25}}{\mathrm{16}}{sinh}^{\mathrm{2}} \theta+\mathrm{25}}…