Question Number 71572 by TawaTawa last updated on 17/Oct/19 Commented by TawaTawa last updated on 17/Oct/19 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\:\mathrm{How}\:? \\ $$ Answered by Kunal12588 last updated on…
Question Number 71570 by TawaTawa last updated on 17/Oct/19 $$\mathrm{Solve}:\:\:\:\:\:\left(\mathrm{2x}\:+\:\mathrm{x}^{\mathrm{2}} \right)\mathrm{y}''\:−\:\mathrm{2}\left(\mathrm{1}\:+\:\mathrm{x}\right)\mathrm{y}'\:+\:\mathrm{2y}\:\:=\:\:\mathrm{0} \\ $$$$\mathrm{Given}\:\:\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} \:\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution}. \\ $$ Answered by mind is power last updated on 17/Oct/19…
Question Number 137106 by mohammad17 last updated on 29/Mar/21 Commented by radians last updated on 30/Mar/21 $${lazy}\:{man} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 137100 by BHOOPENDRA last updated on 29/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 137103 by Boucatchou last updated on 29/Mar/21 $$\:\:\:\:\:\:\:\:\:{Solve}\:\:\mathrm{3}{cos}\mathrm{5}{x}−\mathrm{4}{sin}\mathrm{4}{x}−\mathrm{3}=\mathrm{0}\:\:{in}\:\mathbb{R} \\ $$ Answered by MJS_new last updated on 30/Mar/21 $$\mathrm{obviously}\:{x}=\mathrm{2}{n}\pi\:\mathrm{is}\:\mathrm{a}\:\mathrm{solution} \\ $$$$\mathrm{the}\:\mathrm{others}\:\mathrm{can}\:\mathrm{only}\:\mathrm{be}\:\mathrm{approximated} \\ $$$${x}\approx.\mathrm{966119}+\mathrm{2}{n}\pi \\…
Question Number 71564 by 20190927 last updated on 17/Oct/19 $$\left(\mathrm{z}−\mathrm{i}\right)^{\mathrm{4}} =−\mathrm{7}+\mathrm{24i} \\ $$ Commented by mathmax by abdo last updated on 18/Oct/19 $${we}\:{have}\:\mid−\mathrm{7}+\mathrm{24}{i}\mid=\sqrt{\mathrm{7}^{\mathrm{2}} \:+\mathrm{24}^{\mathrm{2}} }=\sqrt{\mathrm{49}+\mathrm{576}}=\sqrt{\mathrm{625}}=\mathrm{25}\:\Rightarrow…
Question Number 6028 by FilupSmith last updated on 10/Jun/16 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{please}\:\mathrm{show}\:\mathrm{me}\:\mathrm{how}\:\mathrm{to}\:\mathrm{solve}: \\ $$$${L}=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{{x}^{{n}} }{{n}!} \\ $$ Commented by Yozzii last updated on 10/Jun/16 $${Assume}\:{x}>\mathrm{0}. \\…
Question Number 137097 by JulioCesar last updated on 29/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 6027 by FilupSmith last updated on 10/Jun/16 $${x}^{{x}} ={e}^{{x}\mathrm{ln}\:{x}} \\ $$$${e}^{{x}} =\mathrm{1}+{x}+\frac{{x}^{\mathrm{2}} }{\mathrm{2}!}+\frac{{x}^{\mathrm{3}} }{\mathrm{3}!}+… \\ $$$$\therefore\:{e}^{{x}\mathrm{ln}\:{x}} \:=\:\mathrm{1}+{x}\mathrm{ln}\left({x}\right)+\frac{\left({x}\mathrm{ln}\:{x}\right)^{\mathrm{2}} }{\mathrm{2}!}+… \\ $$$${e}^{{x}\mathrm{ln}\:{x}} \:=\:\frac{\left({x}\mathrm{ln}\:{x}\right)^{\mathrm{0}} }{\mathrm{0}!}+\frac{\left({x}\mathrm{ln}\:{x}\right)^{\mathrm{1}} }{\mathrm{1}!}+\frac{\left({x}\mathrm{ln}\:{x}\right)^{\mathrm{2}}…
Question Number 71563 by gunawan last updated on 17/Oct/19 $$\mathrm{find}\:\mathrm{maximum}\:\mathrm{and}\:\mathrm{minimum} \\ $$$$\mathrm{cos}\:{x}+\sqrt{\mathrm{3}}\:\mathrm{sin}\:{x} \\ $$$${for} \\ $$$$\frac{\pi}{\mathrm{6}}\leqslant{x}\leqslant\pi \\ $$ Answered by MJS last updated on 17/Oct/19…