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Author: Tinku Tara

advanced-calculus-evaluate-Im-0-pi-2-li-2-sin-x-li-2-csc-x-dx-

Question Number 136060 by mnjuly1970 last updated on 18/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:…{advanced}\:\:\:{calculus}…. \\ $$$$\:\:\:\:{evaluate}:: \\ $$$$\:\:\:\:\boldsymbol{\phi}=\mathrm{Im}\left(\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} {li}_{\mathrm{2}} \left({sin}\left({x}\right)\right)+{li}_{\mathrm{2}} \left({csc}\left({x}\right)\right){dx}\right) \\ $$$$ \\ $$ Answered by mindispower…

If-x-y-z-is-a-primitive-Pythagorean-triple-prove-that-x-y-and-x-y-are-congruent-modulo-8-to-either-1-or-7-

Question Number 70525 by Rasheed.Sindhi last updated on 05/Oct/19 $${If}\:{x},{y},{z}\:{is}\:{a}\:{primitive}\:{Pythagorean} \\ $$$${triple},{prove}\:{that}\:{x}+{y}\:{and}\:{x}−{y}\:{are} \\ $$$${congruent}\:{modulo}\:\mathrm{8}\:{to}\:{either}\:\mathrm{1}\:{or}\:\mathrm{7}. \\ $$ Answered by mind is power last updated on 07/Oct/19…

If-a-3-b-3-513-and-ab-54-then-find-a-b-

Question Number 70518 by Shamim last updated on 05/Oct/19 $$\mathrm{If}\:\mathrm{a}^{\mathrm{3}} −\mathrm{b}^{\mathrm{3}} =\:\mathrm{513}\:\mathrm{and}\:\mathrm{ab}=\:\mathrm{54}\:\mathrm{then}\:\mathrm{find}\: \\ $$$$\mathrm{a}−\mathrm{b}=\:? \\ $$ Commented by Prithwish sen last updated on 05/Oct/19 $$\boldsymbol{\mathrm{use}}\:\:\:\left(\boldsymbol{\mathrm{a}}−\boldsymbol{\mathrm{b}}\right)^{\mathrm{3}}…

Question-70519

Question Number 70519 by TawaTawa last updated on 05/Oct/19 Commented by mr W last updated on 05/Oct/19 $${B}+{D}=\mathrm{180}° \\ $$$$\frac{{B}}{{D}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${B}+\frac{\mathrm{3}}{\mathrm{2}}{B}=\mathrm{180} \\ $$$$\frac{\mathrm{5}}{\mathrm{2}}{B}=\mathrm{180} \\…

Question-136054

Question Number 136054 by azadsir last updated on 18/Mar/21 Commented by mr W last updated on 18/Mar/21 $${a}=\mathrm{log}_{{x}} \:{xyz}=\frac{\mathrm{1}}{\mathrm{log}_{{xyz}} \:{x}} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{a}}=\mathrm{log}_{{xyz}} \:{x} \\ $$$$\Rightarrow\frac{\mathrm{1}}{{a}}+\frac{\mathrm{1}}{{b}}+\frac{\mathrm{1}}{{c}}=\mathrm{log}_{{xyz}}…