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Author: Tinku Tara

I-m-having-trouble-understanding-why-2-1-3-mod-5-Can-someone-explain-please-Thank-you-

Question Number 5738 by FilupSmith last updated on 26/May/16 $$\mathrm{I}'\mathrm{m}\:\mathrm{having}\:\mathrm{trouble}\:\mathrm{understanding}\:\mathrm{why}: \\ $$$$\mathrm{2}^{−\mathrm{1}} \equiv\mathrm{3}\left(\mathrm{mod}\:\mathrm{5}\right) \\ $$$$ \\ $$$$\mathrm{Can}\:\mathrm{someone}\:\mathrm{explain},\:\mathrm{please}?\:\mathrm{Thank}\:\mathrm{you}! \\ $$ Commented by Rasheed Soomro last updated…

Question-136806

Question Number 136806 by mnjuly1970 last updated on 26/Mar/21 Answered by Dwaipayan Shikari last updated on 26/Mar/21 $$\mathrm{2}\int_{\mathrm{0}} ^{\infty} \frac{{sin}\left(\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right)}{\:\sqrt[{\mathrm{3}}]{{x}}}{dx}\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{{x}^{\mathrm{3}} }={u}\Rightarrow−\frac{\mathrm{3}}{{x}^{\mathrm{4}} }=\frac{{du}}{{dx}} \\ $$$$=\frac{\mathrm{2}}{\mathrm{3}}\int_{\mathrm{0}}…

Advanced-Calculus-sin-1-x-3-x-dx-solution-1-x-t-2-0-sin-t-3-1-t-dt-t

Question Number 136803 by mnjuly1970 last updated on 26/Mar/21 $$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:…..\mathscr{A}{dvanced}\:\:\:\:\blacktriangleleft………….\blacktriangleright\:\:\:\mathscr{C}{alculus}….. \\ $$$$\:\:\:\:\:\boldsymbol{\phi}=\int_{−\infty} ^{\:\infty} \frac{{sin}\left(\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right)}{{x}}{dx}=……??? \\ $$$$\:\:\:\:\:{solution}:: \\ $$$$\:\:\:\:\:\:\boldsymbol{\phi}\overset{\frac{\mathrm{1}}{{x}}\:={t}} {=}\:\mathrm{2}\int_{\mathrm{0}} ^{\:\infty} \frac{{sin}\left({t}^{\mathrm{3}} \right)}{\frac{\mathrm{1}}{{t}}}.\frac{{dt}}{{t}^{\mathrm{2}}…

Question-71265

Question Number 71265 by ajfour last updated on 13/Oct/19 Commented by ajfour last updated on 13/Oct/19 $${Find}\:{radius}\:{of}\:{yellow}\:{sphere}\:{x}, \\ $$$${that}\:{touches}\:{the}\:{other}\:{sphere}, \\ $$$${lateral}\:{surface}\:{of}\:{cone}\:{and}\: \\ $$$${cone}\:{cover}\:{plate}. \\ $$…

Question-136793

Question Number 136793 by JulioCesar last updated on 26/Mar/21 Answered by Dwaipayan Shikari last updated on 26/Mar/21 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{x}^{{sin}\left({ax}\right)} }{{x}^{{tan}\left({bx}\right)} }\right)={y} \\ $$$$\Rightarrow\left({sin}\left({ax}\right)−{tan}\left({bx}\right)\right){log}\left({x}\right)={log}\left({y}\right) \\ $$$$\Rightarrow\left({acos}\left({ax}\right)−{bsec}^{\mathrm{2}}…