Question Number 4066 by Filup last updated on 27/Dec/15 $$\mathrm{Can}\:\mathrm{we}\:\mathrm{prove}\:\pi\:\mathrm{is}\:\mathrm{tracendental}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 69597 by ozodbek last updated on 25/Sep/19 Commented by mathmax by abdo last updated on 25/Sep/19 $${generally}\:{let}\:{find}\:{f}\left({a}\right)\:=\int\sqrt{{x}^{\mathrm{2}} +{a}^{\mathrm{2}} }{dx}\:\:{with}\:{a}>\mathrm{0} \\ $$$${changement}\:{x}\:={ash}\left({t}\right)\:{give}\:{f}\left({a}\right)=\int{ach}\left({t}\right){ach}\left({t}\right){dt} \\ $$$$={a}^{\mathrm{2}}…
Question Number 69594 by ahmadshahhimat775@gmail.com last updated on 25/Sep/19 Answered by MJS last updated on 25/Sep/19 $$\mathrm{2}\leqslant{n}\leqslant\mathrm{4}:\:\mathrm{2}^{{n}!} <\mathrm{2}^{{n}} ! \\ $$$$\mathrm{5}\leqslant{n}:\:\mathrm{2}^{{n}!} >\mathrm{2}^{{n}} ! \\ $$$$\mathrm{ln}\:\mathrm{2}^{{n}!}…
Question Number 135128 by bramlexs22 last updated on 10/Mar/21 Commented by mr W last updated on 10/Mar/21 $${is}\:{ABCD}\:{a}\:{square}? \\ $$ Commented by mr W last…
Question Number 69593 by ahmadshahhimat775@gmail.com last updated on 25/Sep/19 Commented by mathmax by abdo last updated on 25/Sep/19 $${let}\:{f}\left({x}\right)\:=\frac{\sqrt{\mathrm{6}−{x}}−\mathrm{2}}{\mathrm{3}−\sqrt{\mathrm{11}−{x}}}\:\Rightarrow \\ $$$${lim}_{{x}\rightarrow\mathrm{2}} \:{f}\left({x}\right)\:={lim}_{{x}\rightarrow\mathrm{2}} \:\:\:\:\:\frac{\left(\sqrt{\mathrm{6}−{x}}−\mathrm{2}\right)\left(\sqrt{\mathrm{6}−{x}}+\mathrm{2}\right)\left(\mathrm{3}+\sqrt{\mathrm{11}−{x}}\right)}{\left(\mathrm{3}−\sqrt{\mathrm{11}−{x}}\right)\left(\mathrm{3}+\sqrt{\mathrm{11}−{x}}\right)\left(\sqrt{\mathrm{6}−{x}}+\mathrm{2}\right)} \\ $$$$={lim}_{{x}\rightarrow\mathrm{2}}…
Question Number 135127 by Dwaipayan Shikari last updated on 10/Mar/21 $$\int_{\mathrm{0}} ^{\mathrm{1}} {log}^{\mathrm{2}} \left(\Gamma\left({x}\right)\right){dx} \\ $$ Answered by mathmax by abdo last updated on 11/Mar/21…
Question Number 69589 by ajfour last updated on 25/Sep/19 $${x}^{\mathrm{3}} +{px}−{ry}+{qz}+{a}=\mathrm{0} \\ $$$${y}^{\mathrm{3}} +{rx}+{qy}−{pz}+{b}=\mathrm{0} \\ $$$${z}^{\mathrm{3}} −{qx}+{py}+{rz}+{c}=\mathrm{0} \\ $$$${solve}\:{for}\:{x},{y},{z},\:{in}\:{terms}\:{of} \\ $$$${p},{q},{r},\:{a},{b},{c}. \\ $$ Terms of…
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Question Number 69586 by ajfour last updated on 25/Sep/19 $${x}^{\mathrm{5}} −{x}^{\mathrm{4}} −{x}^{\mathrm{3}} −{x}^{\mathrm{2}} −{x}−\mathrm{1}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 135120 by oooooooo last updated on 10/Mar/21 Terms of Service Privacy Policy Contact: info@tinkutara.com