Question Number 41138 by Kishan Daroga last updated on 02/Aug/18 $$\mathrm{A}\:\mathrm{parallelogram},\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{whose}\: \\ $$$$\mathrm{sides}\:\mathrm{are}\:\mathrm{12}\:\mathrm{cm}\:\mathrm{and}\:\mathrm{8}\:\mathrm{cm},\:\mathrm{has}\:\mathrm{one}\: \\ $$$$\mathrm{diagonal}\:\:\:\mathrm{10}\:\mathrm{cm}\:\mathrm{long}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{length} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{diagonal}. \\ $$ Commented by ajfour last updated on…
Question Number 106666 by deep last updated on 06/Aug/20 $$\mathrm{In}\:\mathrm{2}{x}+\mathrm{3}{y}=\mathrm{8}\:\mathrm{and}\:\:\mathrm{5}{x}+{Ky}=\mathrm{3},\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{value}\:\mathrm{of}\:{K}\:\mathrm{so}\:\mathrm{that}\:\mathrm{the}\:\mathrm{given}\:\mathrm{system} \\ $$$$\mathrm{of}\:\mathrm{equation}\:\mathrm{has}\:\mathrm{infinte}\:\mathrm{solution}. \\ $$ Commented by bemath last updated on 06/Aug/20 $$\begin{pmatrix}{\mathrm{2}\:\:\:\:\:\:\mathrm{3}}\\{\mathrm{5}\:\:\:\:\:\:\mathrm{k}}\end{pmatrix}\:\begin{pmatrix}{\mathrm{x}}\\{\mathrm{y}}\end{pmatrix}\:=\:\begin{pmatrix}{\mathrm{8}}\\{\mathrm{3}}\end{pmatrix} \\…
Question Number 106664 by deep last updated on 06/Aug/20 $$\mathrm{Factorise}:\:\:\:{x}^{\mathrm{6}} \:+\:\mathrm{64}{y}^{\mathrm{6}} \\ $$ Answered by som(math1967) last updated on 06/Aug/20 $$\left(\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{3}} +\left(\mathrm{4y}^{\mathrm{2}} \right)^{\mathrm{3}} \\…
Question Number 106665 by deep last updated on 06/Aug/20 $$\:\mathrm{Find}\:\mathrm{a}\:\mathrm{fourth}\:\mathrm{proportional}\:\mathrm{to} \\ $$$$\:\mathrm{3},\:\mathrm{12}\:\mathrm{and}\:\mathrm{15} \\ $$ Answered by nimnim last updated on 06/Aug/20 $${Let}\:{x}\:{be}\:{the}\:{fourth}\:{proportional}. \\ $$$$\therefore\:\:\:\:\:\:\mathrm{3}:\mathrm{12}::\mathrm{15}:{x} \\…
Question Number 41079 by nadeem last updated on 01/Aug/18 $$\mathrm{In}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{two} \\ $$$$\mathrm{larger}\:\mathrm{sides}\:\mathrm{are}\:\mathrm{24}\:\mathrm{and}\:\mathrm{22},\:\mathrm{respectively}. \\ $$$$\mathrm{If}\:\mathrm{the}\:\mathrm{angles}\:\mathrm{are}\:\mathrm{in}\:\mathrm{AP},\:\mathrm{then}\:\mathrm{the}\:\mathrm{third} \\ $$$$\mathrm{side}\:\mathrm{is} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 01/Aug/18…
Question Number 40321 by faaiz last updated on 19/Jul/18 $$\mathrm{If}\:{abc}=\mathrm{8}\:\mathrm{and}\:\frac{\mathrm{1}}{{a}}\:+\:\frac{\mathrm{1}}{{b}}\:+\:\frac{\mathrm{1}}{{c}}\:=\:\frac{\mathrm{3}}{\mathrm{2}}\:\mathrm{then} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:{ab}+{bc}+{ca}. \\ $$ Commented by math khazana by abdo last updated on 19/Jul/18 $$\Rightarrow{abc}\left(\frac{\mathrm{1}}{{a}}+\:\frac{\mathrm{1}}{{b}}\:+\frac{\mathrm{1}}{{c}}\right)=\frac{\mathrm{3}}{\mathrm{2}}{abc}\Rightarrow…
Question Number 39975 by sanjar last updated on 14/Jul/18 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\left(\underset{\:\mathrm{0}} {\overset{{x}} {\int}}\:\:{e}^{{x}} \:{dx}\right)^{\mathrm{2}} }{\underset{\:\mathrm{0}} {\overset{{x}} {\int}}\:\:{e}^{\mathrm{2}{x}^{\mathrm{2}} } \:{dx}}\:\:= \\ $$ Commented by tanmay.chaudhury50@gmail.com last…
Question Number 104275 by mubarakagulamhusain last updated on 20/Jul/20 $$\mathrm{The}\:\mathrm{HCF}\:\mathrm{of}\:\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} −\mathrm{4}\right)\:\mathrm{and}\: \\ $$$$\left({x}^{\mathrm{2}} −\mathrm{1}\right)\left({x}+\mathrm{2}\right)\:\:\mathrm{is} \\ $$ Commented by 1549442205PVT last updated on 20/Jul/20 $$\mathrm{you}\:\mathrm{can}\:\mathrm{tell}\:\mathrm{me}\:\mathrm{what}\:\mathrm{is}\:\mathrm{brief}\:\mathrm{word}\:''\mathrm{HCF}''? \\…
Question Number 38222 by sir themes last updated on 23/Jun/18 $$\mathrm{If}\:\mathbb{U}=\left\{−\mathrm{5},\:−\mathrm{4},\:−\mathrm{3},\:−\mathrm{2},\:−\mathrm{1},\:\mathrm{0},\:\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{4},\:\mathrm{5}\right\} \\ $$$$\mathrm{A}=\left\{{x}/{x}^{\mathrm{2}} =\mathrm{25},\:{x}\:\in\:\mathrm{Z}\right\} \\ $$$$\mathrm{B}=\left\{{x}/{x}^{\mathrm{2}} +\mathrm{5}=\mathrm{9},\:{x}\:\in\:\mathrm{Z}\right\}\:\mathrm{and} \\ $$$$\mathrm{C}=\left\{{x}/−\mathrm{2}\leqslant\:{x}\:\leqslant\:\mathrm{2},\:{x}\:\in\:\mathrm{Z}\right\}\:\mathrm{then} \\ $$$$\left(\mathrm{A}\:\cap\:\mathrm{B}\:\cap\:\mathrm{C}\right)^{\mathrm{c}} \:\cap\:\left(\mathrm{A}\bigtriangleup\mathrm{B}\right)^{\mathrm{c}} =? \\ $$…
Question Number 103155 by 9027201563 last updated on 13/Jul/20 $$\mathrm{If}\:\mathrm{cos}^{−\mathrm{1}} {x}+\mathrm{cos}^{−\mathrm{1}} {y}+\mathrm{cos}^{−\mathrm{1}} {z}+\mathrm{cos}^{−\mathrm{1}} {u}=\mathrm{2}\pi, \\ $$$$\mathrm{then}\:\:{x}^{\mathrm{1999}} +{y}^{\mathrm{2000}} +{z}^{\mathrm{2001}} +{u}^{\mathrm{2002}} = \\ $$ Commented by 9027201563…