Question Number 4025 by 123456 last updated on 26/Dec/15 $${f}_{{n}+\mathrm{1}} \left({x}\right)={x}^{{f}_{{n}} \left({x}\right)} \\ $$$${g}_{{n}+\mathrm{1}} \left({x}\right)=\left[{g}_{{n}} \left({x}\right)\right]^{{x}} \\ $$$${h}_{{n}+\mathrm{1}} \left({x}\right)=\left[{h}_{{n}} \left({x}\right)\right]^{{h}_{{n}} \left({x}\right)} \\ $$$${f}_{\mathrm{0}} \left({x}\right)={g}_{\mathrm{0}} \left({x}\right)={h}_{\mathrm{0}}…
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Question Number 69557 by aliesam last updated on 24/Sep/19 Answered by MJS last updated on 24/Sep/19 $${x}=\mathrm{72} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 135091 by mohammad17 last updated on 10/Mar/21 $${find} \\ $$$$\left(\mathrm{1}\right)\int_{{C}} {ZImZ}^{\mathrm{2}} {dz}\:\:{if}\:{C}=\left\{\mid{Z}\mid=\mathrm{1}:−\pi\leqslant\theta\leqslant\mathrm{0}\right\} \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\int_{{C}} \frac{{dz}}{{Z}^{\mathrm{4}} +\mathrm{1}}\:\:\:{if}\:{C}=\mid{z}−\mathrm{1}+\mathrm{2}{i}\mid=\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$ \\ $$$${help}\:{me}\:{sir} \\…
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Question Number 4013 by Yozzii last updated on 26/Dec/15 $${Find}\:{x}\:{such}\:{that}\:\left({x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{5}\right)^{{x}^{\mathrm{2}} −\mathrm{21}{x}+\mathrm{10}} =\mathrm{1}. \\ $$ Commented by 123456 last updated on 26/Dec/15 $${x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{5}=\mathrm{1}\Leftrightarrow{x}^{\mathrm{2}} +\mathrm{5}{x}+\mathrm{4}=\mathrm{0}…
Question Number 69545 by TawaTawa last updated on 24/Sep/19 Commented by mr W last updated on 24/Sep/19 $$\mathrm{30}×\mathrm{20}−\mathrm{28}×\mathrm{18}=\mathrm{96}\:{m}^{\mathrm{2}} \\ $$$$\mathrm{96}×\mathrm{0}.\mathrm{08}=\mathrm{7}.\mathrm{68}\:{m}^{\mathrm{3}} \\ $$$$\frac{\mathrm{7}.\mathrm{68}}{\mathrm{1}}=\mathrm{7}.\mathrm{68}\:\Rightarrow\:\mathrm{8}\:\:{bags} \\ $$$$\mathrm{8}×\mathrm{600}=\mathrm{4800}\:{N} \\…
Question Number 69538 by mind is power last updated on 24/Sep/19 $${Hello}\:{Verry}\:{Nice}\:{Day}\:{for}\:\:{You} \\ $$$${Find}\:\underset{{k}\geqslant\mathrm{0}} {\sum}\frac{\mathrm{1}}{\left(\mathrm{8}{k}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 3999 by Tinku Tara last updated on 26/Dec/15 $$\mathrm{Pleas}\:\mathrm{update}\:\mathrm{the}\:\mathrm{app}\:\mathrm{to}\:\mathrm{latest}\:\mathrm{version}. \\ $$$$\mathrm{New}\:\mathrm{version}\:\mathrm{added}\:\mathrm{image}\:\mathrm{upload}\:\mathrm{and}\:\mathrm{few} \\ $$$$\mathrm{extra}\:\mathrm{characters}\:\left(\mathrm{hyphen}\right). \\ $$$$\mathrm{Only}\:\mathrm{users}\:\mathrm{with}\:\mathrm{latest}\:\mathrm{version}\:\mathrm{will}\:\mathrm{be}\:\mathrm{able} \\ $$$$\mathrm{to}\:\mathrm{see}\:\mathrm{post}\:\mathrm{containg}\:\mathrm{images}. \\ $$ Commented by Tinku Tara…
Question Number 69535 by naka3546 last updated on 24/Sep/19 Commented by naka3546 last updated on 24/Sep/19 $${without}\:\:{u} \\ $$ Answered by MJS last updated on…