Menu Close

Author: Tinku Tara

Question-70198

Question Number 70198 by smartsmith459@gmail.com last updated on 01/Oct/19 Answered by MJS last updated on 01/Oct/19 $${x}={a}^{\sqrt{\mathrm{log}_{{a}} \:{b}}} \\ $$$$\mathrm{ln}\:{x}\:=\sqrt{\frac{\mathrm{ln}\:{b}}{\mathrm{ln}\:{a}}}\mathrm{ln}\:{a}\:=\sqrt{\mathrm{ln}\:{a}\:×\mathrm{ln}\:{b}} \\ $$$$\Rightarrow\:\mathrm{5}^{\sqrt{\mathrm{log}_{\mathrm{5}} \:\mathrm{7}}} −\mathrm{7}^{\sqrt{\mathrm{log}_{\mathrm{7}} \:\mathrm{5}}}…

Question-70196

Question Number 70196 by smartsmith459@gmail.com last updated on 01/Oct/19 Answered by MJS last updated on 01/Oct/19 $${x}={a}^{\mathrm{log}_{{b}} \:{c}} ={a}^{\frac{\mathrm{ln}\:{c}}{\mathrm{ln}\:{b}}} \\ $$$$\mathrm{ln}\:{x}\:=\frac{\mathrm{ln}\:{c}}{\mathrm{ln}\:{b}}\mathrm{ln}\:{a}\:\Rightarrow\:{x}={a}^{\mathrm{log}_{{b}} \:{c}} ={c}^{\mathrm{log}_{{b}} \:{a}} \\…

Question-70197

Question Number 70197 by smartsmith459@gmail.com last updated on 01/Oct/19 Commented by mr W last updated on 01/Oct/19 $${in}\:{the}\:{first}\:\mathrm{27}\:{days}\:{it}\:{climbs}\:\mathrm{27}{m}. \\ $$$${in}\:{the}\:\mathrm{28}{th}\:{day}\:{it}\:{escapes}\:{from}\:{the} \\ $$$${pit}.\:\Rightarrow{totally}\:\mathrm{28}\:{days} \\ $$ Terms…

Silly-question-which-is-correct-ln-n-ab-ln-n-ln-ab-ln-n-ln-a-ln-b-or-ln-n-ab-ln-n-ln-ab-ln-n-ln-a-ln-b-

Question Number 4653 by FilupSmith last updated on 18/Feb/16 $$\mathrm{Silly}\:\mathrm{question} \\ $$$${which}\:{is}\:{correct}??? \\ $$$$ \\ $$$$\mathrm{ln}\left(\frac{{n}}{{ab}}\right)=\mathrm{ln}\left({n}\right)−\mathrm{ln}\left({ab}\right)=\mathrm{ln}\left({n}\right)−\mathrm{ln}\left({a}\right)+\mathrm{ln}\left({b}\right) \\ $$$${or} \\ $$$$\mathrm{ln}\left(\frac{{n}}{{ab}}\right)=\mathrm{ln}\left({n}\right)−\mathrm{ln}\left({ab}\right)=\mathrm{ln}\left({n}\right)−\mathrm{ln}\left({a}\right)−\mathrm{ln}\left({b}\right) \\ $$ Answered by 123456…

In-mathematics-I-have-worked-with-and-e-g-k-1-x-k-1-2-x-x-1-k-1-x-k-k-I-have-never-worked-with-I-am-curious-as-to-what-it-is-Is-it-another-notation-form-Does-k-1-x-k

Question Number 4650 by FilupSmith last updated on 18/Feb/16 $$\mathrm{In}\:\mathrm{mathematics}\:\mathrm{I}\:\mathrm{have}\:\mathrm{worked}\:\mathrm{with}: \\ $$$$\Sigma\:\mathrm{and}\:\Pi. \\ $$$${e}.{g}. \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{x}} {\sum}}{k}\:=\:\frac{\mathrm{1}}{\mathrm{2}}{x}\left({x}+\mathrm{1}\right) \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{x}} {\prod}}{k}\:=\:{k}! \\ $$$$ \\…